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Rang	Thema	Aufgabe	Formatierte Aufgabe
26801	x 구하기	(2x)/7=1/3	$\frac{2 x}{7} = \frac{1}{3}$
26802	x 구하기	(2x-1)/3=(x+4)/6	$\frac{2 x - 1}{3} = \frac{x + 4}{6}$
26803	x 구하기	3sin(x)^2+2sin(x)=6cos(x)+9sin(x)cos(x)	$3 \sin^{2} (x) + 2 \sin (x) = 6 \cos (x) + 9 \sin (x) \cos (x)$
26804	x 구하기	-3/4x-3y=-15/2	$- \frac{3}{4} x - 3 y = \frac{- 15}{2}$
26805	x 구하기	3/x+1/(x-3)=11/(2x)	$\frac{3}{x} + \frac{1}{x - 3} = \frac{11}{2 x}$
26806	x 구하기	3/(x+5)-1/(x-1)=3/(x^2-4x-5)	$\frac{3}{x + 5} - \frac{1}{x - 1} = \frac{3}{x^{2} - 4 x - 5}$
26807	x 구하기	3^(2x-1)=5^x	$3^{2 x - 1} = 5^{x}$
26808	x 구하기	36x^2-216x-16y^2-160y-652=0	$36 x^{2} - 216 x - 16 y^{2} - 160 y - 652 = 0$
26809	x 구하기	4/(b^2)-1/b=2/(b^2)	$\frac{4}{b^{2}} - \frac{1}{b} = \frac{2}{b^{2}}$
26810	x 구하기	4/31=y/8	$\frac{4}{31} = \frac{y}{8}$
26811	x 구하기	4^(2h-1)=16	$4^{2 h - 1} = 16$
26812	x 구하기	4^(2x)-63*4^x-64=0	$4^{2 x} - 63 \cdot 4^{x} - 64 = 0$
26813	x 구하기	4^(2x-1)=12	$4^{2 x - 1} = 12$
26814	x 구하기	4^4-21x^2+80=0	$4^{4} - 21 x^{2} + 80 = 0$
26815	x 구하기	4^x=39	$4^{x} = 39$
26816	x 구하기	49^x+7^x-12=0	$49^{x} + 7^{x} - 12 = 0$
26817	x 구하기	(4pi)/9+x=90	$\frac{4 π}{9} + x = 90$
26818	x 구하기	5/3-2/x=8/x	$\frac{5}{3} - \frac{2}{x} = \frac{8}{x}$
26819	x 구하기	-5/7t=-20	$- \frac{5}{7} t = - 20$
26820	x 구하기	5/(sin(25))=9/(sin(x))	$\frac{5}{\sin (25)} = \frac{9}{\sin (x)}$
26821	x 구하기	5/(sin(B))=81.3/(sin(96))	$\frac{5}{\sin (B)} = \frac{81.3}{\sin (96)}$
26822	x 구하기	5/(x+4)-4=(9x+16)/(x+6)	$\frac{5}{x + 4} - 4 = \frac{9 x + 16}{x + 6}$
26823	x 구하기	5/(x-4)=77/(x^2-x-12)-11/(x+3)	$\frac{5}{x - 4} = \frac{77}{x^{2} - x - 12} - \frac{11}{x + 3}$
26824	x 구하기	5^(2x)-5x-20=0	$5^{2 x} - 5 x - 20 = 0$
26825	x 구하기	5^x=(1/25)^(4x-1)	$5^{x} = {(\frac{1}{25})}^{4 x - 1}$
26826	x 구하기	5^(x+1)=125	$5^{x + 1} = 125$
26827	x 구하기	5^(x+1)=24	$5^{x + 1} = 24$
26828	x 구하기	6/5*arccos(y/6)=pi	$\frac{6}{5} \cdot \arccos (\frac{y}{6}) = π$
26829	x 구하기	6^2*10^2=x^2	$6^{2} \cdot 10^{2} = x^{2}$
26830	x 구하기	6^(n-2)=50	$6^{n - 2} = 50$
26831	x 구하기	6^(x^2)=28	$6^{x^{2}} = 28$
26832	x 구하기	64/90=sin(x)	$\frac{64}{90} = \sin (x)$
26833	x 구하기	7/12=cos(x)	$\frac{7}{12} = \cos (x)$
26834	x 구하기	7/(a-2)=2/3	$\frac{7}{a - 2} = \frac{2}{3}$
26835	x 구하기	7/(sin(70))=5/(sin(b))	$\frac{7}{\sin (70)} = \frac{5}{\sin (b)}$
26836	x 구하기	7^(2x)+7^x-72=0	$7^{2 x} + 7^{x} - 72 = 0$
26837	x 구하기	8.59/(sin(48))=10/(sin(b))	$\frac{8.59}{\sin (48)} = \frac{10}{\sin (b)}$
26838	x 구하기	8/x+3=(x+8)/(x-4)	$\frac{8}{x} + 3 = \frac{x + 8}{x - 4}$
26839	x 구하기	(8x-4y)/(-10x+5y)=3/9	$\frac{8 x - 4 y}{- 10 x + 5 y} = \frac{3}{9}$
26840	x 구하기	9/(sin(A))=7/(sin(15))	$\frac{9}{\sin (A)} = \frac{7}{\sin (15)}$
26841	x 구하기	9^(2x-12)=81	$9^{2 x - 12} = 81$
26842	x 구하기	9^(8x-32)=3^(x^2)	$9^{8 x - 32} = 3^{x^{2}}$
26843	x 구하기	90/360=(17ft)/(2pr)	$\frac{90}{360} = \frac{17 ft}{2 p r}$
26844	x 구하기	a^2-5a-14=0	$a^{2} - 5 a - 14 = 0$
26845	x 구하기	ax^5-bx^2-c=0	$a x^{5} - b x^{2} - c = 0$
26846	x 구하기	B/(sin(42))=12/(sin(96))	$\frac{B}{\sin (42)} = \frac{12}{\sin (96)}$
26847	x 구하기	b/(sin(87.7))=687/1.2	$\frac{b}{\sin (87.7)} = \frac{687}{1.2}$
26848	x 구하기	c^2=261	$c^{2} = 261$
26849	x 구하기	cos(2)^2x-1=0	$\cos^{2} (2) x - 1 = 0$
26850	x 구하기	(cos(x))/(sec(x)-1)=(cos(x)+1)/(tan(x)^2)	$\frac{\cos (x)}{\sec (x) - 1} = \frac{\cos (x) + 1}{\tan^{2} (x)}$
26851	x 구하기	arccos(\|cos(x)\|)=arccos(0.128)	$\arccos (\| \cos (x) \|) = \arccos (0.128)$
26852	x 구하기	arccos(5x)=pi	$\arccos (5 x) = π$
26853	x 구하기	cos(x)^2+tan(x)^2*cos(x)^2=1	$\cos^{2} (x) + \tan^{2} (x) \cdot \cos^{2} (x) = 1$
26854	x 구하기	cos(x)^2-3cos(x)-1=0	$\cos^{2} (x) - 3 \cos (x) - 1 = 0$
26855	x 구하기	cos(x-8)^2cos(x-1)=0	$\cos^{2} (x - 8) \cos (x - 1) = 0$
26856	x 구하기	cos(2x)^2-sin(2x)^2=2cos(2x)^2-1	$\cos^{2} (2 x) - \sin^{2} (2 x) = 2 \cos^{2} (2 x) - 1$
26857	Berechne	sin(arccos(1/2))	$\sin (\arccos (\frac{1}{2}))$
26858	x 구하기	cos(x)^2+6cos(x)+4=0	$\cos^{2} (x) + 6 \cos (x) + 4 = 0$
26859	x 구하기	cos(x)^2+cos(x)-2=0	$\cos^{2} (x) + \cos (x) - 2 = 0$
26860	x 구하기	(cot(A)csc(A))/(sec(A))=(cot(A)^2+1)/(tan(A)^2+1)	$\frac{\cot (A) \csc (A)}{\sec (A)} = \frac{\cot^{2} (A) + 1}{\tan^{2} (A) + 1}$
26861	x 구하기	cot(2.745)^0.1	$\cot^{0.1} (2.745)$
26862	x 구하기	arccot(x)=arctan(4/3)	$arccot (x) = \arctan (\frac{4}{3})$
26863	x 구하기	cot(x)^2+6cot(x)-2=0	$\cot^{2} (x) + 6 \cot (x) - 2 = 0$
26864	x 구하기	cot(x)^2-8cot(x)+12=0	$\cot^{2} (x) - 8 \cot (x) + 12 = 0$
26865	x 구하기	cot(x)^4-4cot(x)^2+3=0	$\cot^{4} (x) - 4 \cot^{2} (x) + 3 = 0$
26866	x 구하기	csc(x)^2tan(x)^2-2=tan(x)^2	$\csc^{2} (x) \tan^{2} (x) - 2 = \tan^{2} (x)$
26867	x 구하기	csc(x)^2=(-1/5)^2+1	$\csc^{2} (x) = {(- \frac{1}{5})}^{2} + 1$
26868	x 구하기	csc(x)^2-csc(x)-2=0	$\csc^{2} (x) - \csc (x) - 2 = 0$
26869	x 구하기	e^(-2x)=0.2	$e^{- 2 x} = 0.2$
26870	x 구하기	e^(2x)=10.4	$e^{2 x} = 10.4$
26871	x 구하기	e^3.8=x	$e^{3.8} = x$
26872	x 구하기	e^6=x	$e^{6} = x$
26873	x 구하기	e^(7x+4)=10	$e^{7 x + 4} = 10$
26874	x 구하기	e^(-c)=8^(2c)	$e^{- c} = 8^{2 c}$
26875	x 구하기	h^2+17h+16=0	$h^{2} + 17 h + 16 = 0$
26876	x 구하기	ine^x = natural log of 0.83	$i n e^{x} = \ln (0.83)$
26877	x 구하기	k/x+23/30=5/6	$\frac{k}{x} + \frac{23}{30} = \frac{5}{6}$
26878	x 구하기	k^2+3k-10=0	$k^{2} + 3 k - 10 = 0$
26879	x 구하기	( natürlicher Logarithmus von 2)/12=(12k)/12	$\frac{\ln (2)}{12} = \frac{12 k}{12}$
26880	x 구하기	natürlicher Logarithmus von (3x-2)^2=5	$\ln ({(3 x - 2)}^{2}) = 5$
26881	x 구하기	( natürlicher Logarithmus von 8)/(6 natürlicher Logarithmus von 1.015)=t	$\frac{\ln (8)}{6 \ln (1.015)} = t$
26882	x 구하기	( Logarithmus von 16-x^2)/( Logarithmus von 3x-4)=2	$\frac{\log (16 - x^{2})}{\log (3 x - 4)} = 2$
26883	x 구하기	Logarithmische Basis 11 von x-7=-5	$\log_{11} (x - 7) = - 5$
26884	x 구하기	logarithmische Basis 12 von 2x+1=1-2 logarithmische Basis 12 von 2	$\log_{12} (2 x + 1) = 1 - 2 \log_{12} (2)$
26885	x 구하기	logarithmische Basis 19 von 3+ logarithmische Basis 19 von x+7 = logarithmische Basis 19 von 8x+6	$\log_{19} (3) + \log_{19} (x + 7) = \log_{19} (8 x + 6)$
26886	x 구하기	Logarithmische Basis 3 von 1/27=y	$\log_{3} (\frac{1}{27}) = y$
26887	x 구하기	Logarithmische Basis 5 von 2x-5=-4	$\log_{5} (2 x) - 5 = - 4$
26888	x 구하기	logarithmische Basis 6 von 2x-1+ logarithmische Basis 6 von 4x+3=2	$\log_{6} (2 x - 1) + \log_{6} (4 x + 3) = 2$
26889	x 구하기	logarithmische Basis 6 von 5(2y-3) = logarithmische Basis 6 von 25	$\log_{6} (5) (2 y - 3) = \log_{6} (25)$
26890	x 구하기	logarithmische Basis 7 von 2x+1 = logarithmische Basis 7 von 10-x	$\log_{7} (2 x + 1) = \log_{7} (10 - x)$
26891	x 구하기	logarithmische Basis 7 von x=1- logarithmische Basis 7 von x-6	$\log_{7} (x) = 1 - \log_{7} (x - 6)$
26892	Ermittle den exakten Wert	sin(-(7pi)/12)	$\sin (- \frac{7 π}{12})$
26893	x 구하기	2cos(x)=2sin(x)+1	$2 \cos (x) = 2 \sin (x) + 1$
26894	x 구하기	2sin(x)-1-csc(x)=0	$2 \sin (x) - 1 - \csc (x) = 0$
26895	x 구하기	2sin(x)cos(x)-2cos(x)=0	$2 \sin (x) \cos (x) - 2 \cos (x) = 0$
26896	x 구하기	2sin(x+1)=csc(x)	$2 \sin (x + 1) = \csc (x)$
26897	x 구하기	2sin(x+17)cos(x+17)=cos(x+8)	$2 \sin (x + 17) \cos (x + 17) = \cos (x + 8)$
26898	x 구하기	2sin(x/2)=1	$2 \sin (\frac{x}{2}) = 1$
26899	x 구하기	2sin(x/2)=2cos(x/2)	$2 \sin (\frac{x}{2}) = 2 \cos (\frac{x}{2})$
26900	x 구하기	2sin(2x)cos(2x)*2=0	$2 \sin (2 x) \cos (2 x) \cdot 2 = 0$