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有限数学示例概率

求独立事件 A 和 B 的 P(A∩B)

$P (A) = 0.07$ , $P (B) = 0.1$

解题步骤 1

当 $A$ 和 $B$ 是独立事件时， $A$ 和 $B$ 发生的概率为 $P (A \cap B) = P (B \cap A) = P (A) \cdot (P (B))$ ，这被称为独立事件 $A$ 和 $B$ 的乘法法则。

$P (A \cap B) = P (B \cap A) = P (A) \cdot (P (B))$

解题步骤 2

填入已知值。

$P (A \cap B) = P (B \cap A) = 0.07 \cdot 0.1$

解题步骤 3

将 $0.07$ 乘以 $0.1$ 。

$P (A \cap B) = P (B \cap A) = 0.007$

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Solving Combinations Solving Permutations Finding the Probability for Both Mutually Exclusive Events Finding the Conditional Probability for Independent Events Determining if Given Events are Mutually Exclusive Events Finding the Probability of Both not Mutually Exclusive Events Finding the Probability of the Complement

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$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$