Algebra Examples

$(2, 3)$ , $(- 1, - 5)$

Step 1

The general equation of a parabola with vertex $(h, k)$ is $y = a {(x - h)}^{2} + k$ . In this case we have $(2, 3)$ as the vertex $(h, k)$ and $(- 1, - 5)$ is a point $(x, y)$ on the parabola. To find $a$ , substitute the two points in $y = a {(x - h)}^{2} + k$ .

$- 5 = a {(- 1 - (2))}^{2} + 3$

Step 2

Using $- 5 = a {(- 1 - (2))}^{2} + 3$ to solve for $a$ , $a = - \frac{8}{9}$ .

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Rewrite the equation as $a {(- 1 - (2))}^{2} + 3 = - 5$ .

$a {(- 1 - (2))}^{2} + 3 = - 5$

Simplify each term.

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Multiply $- 1$ by $2$ .

$a {(- 1 - 2)}^{2} + 3 = - 5$

Subtract $2$ from $- 1$ .

$a {(- 3)}^{2} + 3 = - 5$

Raise $- 3$ to the power of $2$ .

$a \cdot 9 + 3 = - 5$

Move $9$ to the left of $a$ .

$9 a + 3 = - 5$

Move all terms not containing $a$ to the right side of the equation.

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Subtract $3$ from both sides of the equation.

$9 a = - 5 - 3$

Subtract $3$ from $- 5$ .

$9 a = - 8$

Divide each term in $9 a = - 8$ by $9$ and simplify.

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Divide each term in $9 a = - 8$ by $9$ .

$\frac{9 a}{9} = \frac{- 8}{9}$

Simplify the left side.

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Cancel the common factor of $9$ .

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Cancel the common factor.

$\frac{9 a}{9} = \frac{- 8}{9}$

Divide $a$ by $1$ .

$a = \frac{- 8}{9}$

Simplify the right side.

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Move the negative in front of the fraction.

$a = - \frac{8}{9}$

Step 3

Using $y = a {(x - h)}^{2} + k$ , the general equation of the parabola with the vertex $(2, 3)$ and $a = - \frac{8}{9}$ is $y = (- \frac{8}{9}) {(x - (2))}^{2} + 3$ .

$y = (- \frac{8}{9}) {(x - (2))}^{2} + 3$

Step 4

Solve $y = (- \frac{8}{9}) {(x - (2))}^{2} + 3$ for $y$ .

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Remove parentheses.

$y = (- \frac{8}{9}) {(x - (2))}^{2} + 3$

Multiply $- \frac{8}{9}$ by ${(x - (2))}^{2}$ .

$y = - \frac{8}{9} \cdot {(x - (2))}^{2} + 3$

Remove parentheses.

$y = (- \frac{8}{9}) {(x - (2))}^{2} + 3$

Simplify $(- \frac{8}{9}) {(x - (2))}^{2} + 3$ .

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Simplify each term.

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Multiply $- 1$ by $2$ .

$y = - \frac{8}{9} {(x - 2)}^{2} + 3$

Rewrite ${(x - 2)}^{2}$ as $(x - 2) (x - 2)$ .

$y = - \frac{8}{9} ((x - 2) (x - 2)) + 3$

Expand $(x - 2) (x - 2)$ using the FOIL Method.

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Apply the distributive property.

$y = - \frac{8}{9} (x (x - 2) - 2 (x - 2)) + 3$

Apply the distributive property.

$y = - \frac{8}{9} (x \cdot x + x \cdot - 2 - 2 (x - 2)) + 3$

Apply the distributive property.

$y = - \frac{8}{9} (x \cdot x + x \cdot - 2 - 2 x - 2 \cdot - 2) + 3$

Simplify and combine like terms.

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Simplify each term.

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Multiply $x$ by $x$ .

$y = - \frac{8}{9} (x^{2} + x \cdot - 2 - 2 x - 2 \cdot - 2) + 3$

Move $- 2$ to the left of $x$ .

$y = - \frac{8}{9} (x^{2} - 2 \cdot x - 2 x - 2 \cdot - 2) + 3$

Multiply $- 2$ by $- 2$ .

$y = - \frac{8}{9} (x^{2} - 2 x - 2 x + 4) + 3$

Subtract $2 x$ from $- 2 x$ .

$y = - \frac{8}{9} (x^{2} - 4 x + 4) + 3$

Apply the distributive property.

$y = - \frac{8}{9} x^{2} - \frac{8}{9} (- 4 x) - \frac{8}{9} \cdot 4 + 3$

Simplify.

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Combine $x^{2}$ and $\frac{8}{9}$ .

$y = - \frac{x^{2} \cdot 8}{9} - \frac{8}{9} (- 4 x) - \frac{8}{9} \cdot 4 + 3$

Multiply $- \frac{8}{9} (- 4 x)$ .

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Multiply $- 4$ by $- 1$ .

$y = - \frac{x^{2} \cdot 8}{9} + 4 (\frac{8}{9}) x - \frac{8}{9} \cdot 4 + 3$

Combine $4$ and $\frac{8}{9}$ .

$y = - \frac{x^{2} \cdot 8}{9} + \frac{4 \cdot 8}{9} x - \frac{8}{9} \cdot 4 + 3$

Multiply $4$ by $8$ .

$y = - \frac{x^{2} \cdot 8}{9} + \frac{32}{9} x - \frac{8}{9} \cdot 4 + 3$

Combine $\frac{32}{9}$ and $x$ .

$y = - \frac{x^{2} \cdot 8}{9} + \frac{32 x}{9} - \frac{8}{9} \cdot 4 + 3$

Multiply $- \frac{8}{9} \cdot 4$ .

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Multiply $4$ by $- 1$ .

$y = - \frac{x^{2} \cdot 8}{9} + \frac{32 x}{9} - 4 (\frac{8}{9}) + 3$

Combine $- 4$ and $\frac{8}{9}$ .

$y = - \frac{x^{2} \cdot 8}{9} + \frac{32 x}{9} + \frac{- 4 \cdot 8}{9} + 3$

Multiply $- 4$ by $8$ .

$y = - \frac{x^{2} \cdot 8}{9} + \frac{32 x}{9} + \frac{- 32}{9} + 3$

Simplify each term.

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Move $8$ to the left of $x^{2}$ .

$y = - \frac{8 \cdot x^{2}}{9} + \frac{32 x}{9} + \frac{- 32}{9} + 3$

Move the negative in front of the fraction.

$y = - \frac{8 x^{2}}{9} + \frac{32 x}{9} - \frac{32}{9} + 3$

To write $3$ as a fraction with a common denominator, multiply by $\frac{9}{9}$ .

$y = - \frac{8 x^{2}}{9} + \frac{32 x}{9} - \frac{32}{9} + 3 \cdot \frac{9}{9}$

Combine $3$ and $\frac{9}{9}$ .

$y = - \frac{8 x^{2}}{9} + \frac{32 x}{9} - \frac{32}{9} + \frac{3 \cdot 9}{9}$

Combine the numerators over the common denominator.

$y = - \frac{8 x^{2}}{9} + \frac{32 x}{9} + \frac{- 32 + 3 \cdot 9}{9}$

Simplify the numerator.

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Multiply $3$ by $9$ .

$y = - \frac{8 x^{2}}{9} + \frac{32 x}{9} + \frac{- 32 + 27}{9}$

Add $- 32$ and $27$ .

$y = - \frac{8 x^{2}}{9} + \frac{32 x}{9} + \frac{- 5}{9}$

Move the negative in front of the fraction.

$y = - \frac{8 x^{2}}{9} + \frac{32 x}{9} - \frac{5}{9}$

Step 5

The standard form and vertex form are as follows.

Standard Form: $y = - \frac{8}{9} x^{2} + \frac{32}{9} x - \frac{5}{9}$

Vertex Form: $y = (- \frac{8}{9}) {(x - (2))}^{2} + 3$

Step 6

Simplify the standard form.

Standard Form: $y = - \frac{8}{9} x^{2} + \frac{32}{9} x - \frac{5}{9}$

Vertex Form: $y = - \frac{8}{9} {(x - 2)}^{2} + 3$

Step 7