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Calculus
Step-by-Step Examples
Basic Differentiation Rules
d
d
x
[
c
u
]
=
c
u
´
d
d
x
[
u
±
v
]
=
u
´
±
v
´
d
d
x
[
u
v
]
=
u
v
´
+
v
u
´
d
d
x
[
u
v
]
=
v
u
´
-
u
v
´
v
2
d
d
x
[
c
]
=
0
d
d
x
[
u
n
]
=
n
u
n
-
1
u
´
d
d
x
[
x
]
=
1
d
d
x
[
|
u
|
]
=
u
|
u
|
(
u
´
)
,
u
≠
0
d
d
x
[
ln
u
]
=
u
´
u
d
d
x
[
e
u
]
=
e
u
u
´
d
d
x
[
log
a
u
]
=
u
´
(
ln
a
)
u
d
d
x
[
a
u
]
=
(
ln
a
)
a
u
u
´
d
d
x
[
sin
u
]
=
(
cos
u
)
u
´
d
d
x
[
cos
u
]
=
-
(
sin
u
)
u
´
d
d
x
[
tan
u
]
=
(
sec
2
u
)
u
´
d
d
x
[
cot
u
]
=
-
(
csc
2
u
)
u
´
d
d
x
[
sec
u
]
=
(
sec
u
tan
u
)
u
´
d
d
x
[
csc
u
]
=
-
(
csc
u
cot
u
)
u
´
d
d
x
[
arc
sin
u
]
=
u
´
1
-
u
2
d
d
x
[
arc
cos
u
]
=
-
u
´
1
-
u
2
d
d
x
[
arc
tan
u
]
=
u
´
1
+
u
2
d
d
x
[
arc
cot
u
]
=
-
u
´
1
+
u
2
d
d
x
[
arc
sec
u
]
=
u
´
|
u
|
u
2
-
1
d
d
x
[
arc
csc
u
]
=
-
u
´
|
u
|
u
2
-
1
Basic Integration Rules (a > 0)
∫
k
f
(
u
)
d
u
=
k
∫
f
(
u
)
d
u
∫
[
f
(
u
)
±
g
(
u
)
]
d
u
=
∫
f
(
u
)
d
u
±
∫
g
(
u
)
d
u
∫
d
u
=
u
+
C
∫
u
n
d
u
=
u
n
+
1
n
+
1
+
C
,
n
≠
-
1
∫
d
u
u
=
ln
|
u
|
+
C
∫
e
u
d
u
=
e
u
+
C
∫
a
u
d
u
=
(
1
ln
a
)
a
u
+
C
∫
sin
u
d
u
=
-
cos
u
+
C
∫
cos
u
d
u
=
sin
u
+
C
∫
tan
u
d
u
=
-
ln
|
cos
u
|
+
C
∫
cot
u
d
u
=
ln
|
sin
u
|
+
C
∫
sec
u
d
u
=
ln
|
sec
u
+
tan
u
|
+
C
∫
csc
u
d
u
=
-
ln
|
csc
u
+
cot
u
|
+
C
∫
sec
2
u
d
u
=
tan
u
+
C
∫
csc
2
u
d
u
=
-
cot
u
+
C
∫
sec
u
tan
u
d
u
=
sec
u
+
C
∫
csc
u
cot
u
d
u
=
-
csc
u
+
C
∫
d
u
a
2
-
u
2
=
arcsin
u
a
+
C
∫
d
u
a
2
+
u
2
=
1
a
arctan
u
a
+
C
∫
d
u
u
u
2
-
a
2
=
1
a
arcsec
|
u
|
a
+
C
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