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Calculus
Step-by-Step Examples
Basic Differentiation Rules
d
d
x
c
u
=
c
u
´
d
d
x
u
±
v
=
u
´
±
v
´
d
d
x
u
v
=
u
v
´
+
v
u
´
d
d
x
u
v
=
v
u
´
+
u
v
´
v
2
d
d
x
c
=
0
d
d
x
u
n
=
n
u
n
-
1
u
´
d
d
x
x
=
1
d
d
x
u
=
u
u
u
´
,
u
≠
0
d
d
x
ln
u
=
u
´
u
d
d
x
e
u
=
e
u
u
´
d
d
x
log
a
u
=
u
´
ln
a
u
d
d
x
a
u
=
ln
a
a
u
u
´
d
d
x
sin
u
=
cos
u
u
´
d
d
x
cos
u
=
-
sin
u
u
´
d
d
x
tan
u
=
sec
2
u
u
´
d
d
x
cot
u
=
-
csc
2
u
u
´
d
d
x
sec
u
=
sec
u
tan
u
u
´
d
d
x
csc
u
=
-
csc
u
cot
u
u
´
d
d
x
arc
sin
u
=
u
´
1
-
u
2
d
d
x
arc
cos
u
=
-
u
´
1
-
u
2
d
d
x
arc
tan
u
=
u
´
1
+
u
2
d
d
x
arc
cot
u
=
-
u
´
1
+
u
2
d
d
x
arc
sec
u
=
u
´
u
u
2
-
1
d
d
x
arc
csc
u
=
-
u
´
u
u
2
-
1
Basic Integration Rules (a > 0)
∫
k
f
(
u
)
d
u
=
k
∫
f
(
u
)
d
u
∫
[
f
(
u
)
±
g
(
u
)
]
d
u
=
∫
f
(
u
)
d
u
±
∫
g
(
u
)
d
u
∫
d
u
=
u
+
C
∫
u
n
d
u
=
u
n
+
1
n
+
1
+
C
,
n
≠
-
1
∫
d
u
u
=
l
n
|
u
|
+
C
∫
e
u
d
u
=
e
u
+
C
∫
a
u
d
u
=
(
1
l
n
a
)
a
u
+
C
∫
s
i
n
u
d
u
=
-
c
o
s
u
+
C
∫
c
o
s
u
d
u
=
s
i
n
u
+
C
∫
t
a
n
u
d
u
=
-
l
n
|
c
o
s
u
|
+
C
∫
c
o
t
u
d
u
=
l
n
|
s
i
n
u
|
+
C
∫
s
e
c
u
d
u
=
l
n
|
s
e
c
u
+
t
a
n
u
|
+
C
∫
c
s
c
u
d
u
=
-
l
n
|
c
s
c
u
+
c
o
t
u
|
+
C
∫
s
e
c
u
d
u
=
l
n
|
s
e
c
u
+
t
a
n
u
|
+
C
∫
c
s
c
u
d
u
=
-
l
n
|
c
s
c
u
+
c
o
t
u
|
+
C
∫
s
e
c
2
u
d
u
=
t
a
n
u
+
C
∫
c
s
c
2
u
d
u
=
-
c
o
t
u
+
C
∫
s
e
c
u
t
a
n
u
d
u
=
s
e
c
u
+
C
∫
c
s
c
u
c
o
t
u
d
u
=
-
c
s
c
u
+
C
∫
d
u
a
2
-
u
2
2
=
a
r
c
s
i
n
u
a
+
C
∫
d
u
a
2
+
u
2
=
1
a
a
r
c
t
a
n
u
a
+
C
∫
d
u
u
u
2
-
a
2
2
=
1
a
a
r
c
s
e
c
|
u
|
a
+
C
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