Trigonometry Examples

$\cos (6 x)$

A good method to expand $\cos (6 x)$ is by using De Moivre's theorem $(r {(\cos (x) + i \cdot \sin (x))}^{n} = r^{n} (\cos (n x) + i \cdot \sin (n x)))$ . When $r = 1$ , $\cos (n x) + i \cdot \sin (n x) = {(\cos (x) + i \cdot \sin (x))}^{n}$ .

$\cos (n x) + i \cdot \sin (n x) = {(\cos (x) + i \cdot \sin (x))}^{n}$

Expand the right hand side of $\cos (n x) + i \cdot \sin (n x) = {(\cos (x) + i \cdot \sin (x))}^{n}$ using the binomial theorem.

Expand: ${(\cos (x) + i \cdot \sin (x))}^{6}$

Use the Binomial Theorem.

$\cos^{6} (x) + 6 \cos^{5} (x) (i \sin (x)) + 15 \cos^{4} (x) {(i \sin (x))}^{2} + 20 \cos^{3} (x) {(i \sin (x))}^{3} + 15 \cos^{2} (x) {(i \sin (x))}^{4} + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Simplify terms.

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Simplify each term.

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Apply the product rule to $i \sin (x)$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) + 15 \cos^{4} (x) (i^{2} \sin^{2} (x)) + 20 \cos^{3} (x) {(i \sin (x))}^{3} + 15 \cos^{2} (x) {(i \sin (x))}^{4} + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Rewrite using the commutative property of multiplication.

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) + 15 \cdot i^{2} (\cos^{4} (x) \sin^{2} (x)) + 20 \cos^{3} (x) {(i \sin (x))}^{3} + 15 \cos^{2} (x) {(i \sin (x))}^{4} + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Rewrite $i^{2}$ as $- 1$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) + 15 \cdot - 1 (\cos^{4} (x) \sin^{2} (x)) + 20 \cos^{3} (x) {(i \sin (x))}^{3} + 15 \cos^{2} (x) {(i \sin (x))}^{4} + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Multiply $15$ by $- 1$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 (\cos^{4} (x) \sin^{2} (x)) + 20 \cos^{3} (x) {(i \sin (x))}^{3} + 15 \cos^{2} (x) {(i \sin (x))}^{4} + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Apply the product rule to $i \sin (x)$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) + 20 \cos^{3} (x) (i^{3} \sin^{3} (x)) + 15 \cos^{2} (x) {(i \sin (x))}^{4} + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Rewrite using the commutative property of multiplication.

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) + 20 \cdot i^{3} (\cos^{3} (x) \sin^{3} (x)) + 15 \cos^{2} (x) {(i \sin (x))}^{4} + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Factor out $i^{2}$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) + 20 \cdot (i^{2} \cdot i) (\cos^{3} (x) \sin^{3} (x)) + 15 \cos^{2} (x) {(i \sin (x))}^{4} + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Rewrite $i^{2}$ as $- 1$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) + 20 \cdot (- 1 \cdot i) (\cos^{3} (x) \sin^{3} (x)) + 15 \cos^{2} (x) {(i \sin (x))}^{4} + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Rewrite $- 1 i$ as $- i$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) + 20 \cdot (- i) (\cos^{3} (x) \sin^{3} (x)) + 15 \cos^{2} (x) {(i \sin (x))}^{4} + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Multiply $- 1$ by $20$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i (\cos^{3} (x) \sin^{3} (x)) + 15 \cos^{2} (x) {(i \sin (x))}^{4} + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Apply the product rule to $i \sin (x)$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) (i^{4} \sin^{4} (x)) + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Rewrite using the commutative property of multiplication.

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cdot i^{4} (\cos^{2} (x) \sin^{4} (x)) + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Rewrite $i^{4}$ as $1$ .

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Rewrite $i^{4}$ as ${(i^{2})}^{2}$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cdot {(i^{2})}^{2} (\cos^{2} (x) \sin^{4} (x)) + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Rewrite $i^{2}$ as $- 1$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cdot {(- 1)}^{2} (\cos^{2} (x) \sin^{4} (x)) + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Raise $- 1$ to the power of $2$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cdot 1 (\cos^{2} (x) \sin^{4} (x)) + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Multiply $15$ by $1$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 (\cos^{2} (x) \sin^{4} (x)) + 6 \cos (x) {(i \sin (x))}^{5} + {(i \sin (x))}^{6}$

Apply the product rule to $i \sin (x)$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) \sin^{4} (x) + 6 \cos (x) (i^{5} \sin^{5} (x)) + {(i \sin (x))}^{6}$

Factor out $i^{4}$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) \sin^{4} (x) + 6 \cos (x) (i^{4} i \sin^{5} (x)) + {(i \sin (x))}^{6}$

Rewrite $i^{4}$ as $1$ .

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Rewrite $i^{4}$ as ${(i^{2})}^{2}$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) \sin^{4} (x) + 6 \cos (x) ({(i^{2})}^{2} i \sin^{5} (x)) + {(i \sin (x))}^{6}$

Rewrite $i^{2}$ as $- 1$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) \sin^{4} (x) + 6 \cos (x) ({(- 1)}^{2} i \sin^{5} (x)) + {(i \sin (x))}^{6}$

Raise $- 1$ to the power of $2$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) \sin^{4} (x) + 6 \cos (x) (1 i \sin^{5} (x)) + {(i \sin (x))}^{6}$

Multiply $i$ by $1$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) \sin^{4} (x) + 6 \cos (x) (i \sin^{5} (x)) + {(i \sin (x))}^{6}$

Apply the product rule to $i \sin (x)$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) \sin^{4} (x) + 6 \cos (x) i \sin^{5} (x) + i^{6} \sin^{6} (x)$

Factor out $i^{4}$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) \sin^{4} (x) + 6 \cos (x) i \sin^{5} (x) + i^{4} i^{2} \sin^{6} (x)$

Rewrite $i^{4}$ as $1$ .

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Rewrite $i^{4}$ as ${(i^{2})}^{2}$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) \sin^{4} (x) + 6 \cos (x) i \sin^{5} (x) + {(i^{2})}^{2} i^{2} \sin^{6} (x)$

Rewrite $i^{2}$ as $- 1$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) \sin^{4} (x) + 6 \cos (x) i \sin^{5} (x) + {(- 1)}^{2} i^{2} \sin^{6} (x)$

Raise $- 1$ to the power of $2$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) \sin^{4} (x) + 6 \cos (x) i \sin^{5} (x) + 1 i^{2} \sin^{6} (x)$

Multiply $i^{2}$ by $1$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) \sin^{4} (x) + 6 \cos (x) i \sin^{5} (x) + i^{2} \sin^{6} (x)$

Rewrite $i^{2}$ as $- 1$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) \sin^{4} (x) + 6 \cos (x) i \sin^{5} (x) - 1 \sin^{6} (x)$

Rewrite $- 1 \sin^{6} (x)$ as $- \sin^{6} (x)$ .

$\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) \sin^{4} (x) + 6 \cos (x) i \sin^{5} (x) - \sin^{6} (x)$

Reorder factors in $\cos^{6} (x) + 6 \cos^{5} (x) i \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) \sin^{4} (x) + 6 \cos (x) i \sin^{5} (x) - \sin^{6} (x)$ .

$\cos^{6} (x) + 6 i \cos^{5} (x) \sin (x) - 15 \cos^{4} (x) \sin^{2} (x) - 20 i \cos^{3} (x) \sin^{3} (x) + 15 \cos^{2} (x) \sin^{4} (x) + 6 i \cos (x) \sin^{5} (x) - \sin^{6} (x)$

Take out the expressions with the imaginary part, which are equal to $\cos (6 x)$ . Remove the imaginary number $i$ .

$\cos (6 x) = \cos^{6} (x) - 15 \cos^{4} (x) \sin^{2} (x) + 15 \cos^{2} (x) \sin^{4} (x) - \sin^{6} (x)$

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