Statistics Examples

$P (A) = 0.08$ , $P (B) = 0.2$ , $P (A a n d B) = 0.06$

When $A$ and $B$ are not mutually exclusive events, the probability of $A$ or $B$ occurring is $P (A \cup B) = P (A) + P (B) - P (A \cap B)$ , which is called the addition rule for not mutually exclusive events $A$ and $B$ .

$P (A \cup B) = P (A) + P (B) - P (A \cap B)$

Fill in the known values.

$P (A \cup B) = 0.08 + 0.2 - (0.06)$

Multiply $- 1$ by $0.06$ to get $- 0.06$ .

$P (A \cup B) = 0.08 + 0.2 - 0.06$

Add $0.08$ and $0.2$ to get $0.28$ .

$P (A \cup B) = 0.28 - 0.06$

Subtract $0.06$ from $0.28$ to get $0.22$ .

$P (A \cup B) = 0.22$

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