Precalculus Examples

$x = 2$ , $x = - 2$ , $x = 1$

Since the roots of an equation are the points where the solution is $0$ , set each root as a factor of the equation that equals $0$ .

$(x - 2) (x - (- 2)) (x - 1) = 0$

Simplify.

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Expand $(x - 2) (x + 2)$ using the FOIL Method.

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Apply the distributive property.

$(x (x + 2) - 2 (x + 2)) (x - 1) = 0$

Apply the distributive property.

$(x \cdot x + x \cdot 2 - 2 (x + 2)) (x - 1) = 0$

Apply the distributive property.

$(x \cdot x + x \cdot 2 - 2 x - 2 \cdot 2) (x - 1) = 0$

Simplify terms.

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Combine the opposite terms in $x \cdot x + x \cdot 2 - 2 x - 2 \cdot 2$ .

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Reorder the factors in the terms $x \cdot 2$ and $- 2 x$ .

$(x \cdot x + 2 x - 2 x - 2 \cdot 2) (x - 1) = 0$

Subtract $2 x$ from $2 x$ .

$(x \cdot x + 0 - 2 \cdot 2) (x - 1) = 0$

Add $x \cdot x$ and $0$ .

$(x \cdot x - 2 \cdot 2) (x - 1) = 0$

Simplify each term.

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Multiply $x$ by $x$ .

$(x^{2} - 2 \cdot 2) (x - 1) = 0$

Multiply $- 2$ by $2$ .

$(x^{2} - 4) (x - 1) = 0$

Expand $(x^{2} - 4) (x - 1)$ using the FOIL Method.

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Apply the distributive property.

$x^{2} (x - 1) - 4 (x - 1) = 0$

Apply the distributive property.

$x^{2} x + x^{2} \cdot - 1 - 4 (x - 1) = 0$

Apply the distributive property.

$x^{2} x + x^{2} \cdot - 1 - 4 x - 4 \cdot - 1 = 0$

Simplify each term.

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Multiply $x^{2}$ by $x$ by adding the exponents.

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Multiply $x^{2}$ by $x$ .

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Raise $x$ to the power of $1$ .

$x^{2} x + x^{2} \cdot - 1 - 4 x - 4 \cdot - 1 = 0$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x^{2 + 1} + x^{2} \cdot - 1 - 4 x - 4 \cdot - 1 = 0$

Add $2$ and $1$ .

$x^{3} + x^{2} \cdot - 1 - 4 x - 4 \cdot - 1 = 0$

Move $- 1$ to the left of $x^{2}$ .

$x^{3} - 1 \cdot x^{2} - 4 x - 4 \cdot - 1 = 0$

Rewrite $- 1 x^{2}$ as $- x^{2}$ .

$x^{3} - x^{2} - 4 x - 4 \cdot - 1 = 0$

Multiply $- 4$ by $- 1$ .

$x^{3} - x^{2} - 4 x + 4 = 0$

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