Precalculus Examples

$x^{2} + y = 0$ , $y = 5 x^{2}$ , $(3, 4)$

Raise $3$ to the power of $2$ .

$9 + 4 = 0$

$4 = 5 {(3)}^{2}$

Add $9$ and $4$ .

$13 = 0$

$4 = 5 {(3)}^{2}$

Since $13 \neq 0$ , there are no solutions.

No solution

Simplify $5 {(3)}^{2}$ .

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Raise $3$ to the power of $2$ .

No solution

$4 = 5 \cdot 9$

Multiply $5$ by $9$ .

No solution

$4 = 45$

No solution

Since $4 \neq 45$ , there are no solutions.

No solution

The ordered pair is not a solution to the system of equations.

$(3, 4)$ is not a solution

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