Precalculus Examples

$x^{2} + 3 y = 0$ , $y = 5$ , $(3, 4)$

Rewrite the equation as $0 = {(3)}^{2} + 3 (4)$ .

$0 = {(3)}^{2} + 3 (4)$

$(4) = 5$

Simplify each term.

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Remove parentheses around $3$ .

$0 = 3^{2} + 3 (4)$

$(4) = 5$

Raise $3$ to the power of $2$ .

$0 = 9 + 3 (4)$

$(4) = 5$

Multiply $3$ by $4$ .

$0 = 9 + 12$

$(4) = 5$

$0 = 9 + 12$

$(4) = 5$

Add $9$ and $12$ .

$0 = 21$

$(4) = 5$

Since $0 \neq 21$ , there are no solutions.

No solution

Rewrite the equation as $5 = 4$ .

No solution

Since $5 \neq 4$ , there are no solutions.

No solution

The ordered pair is a solution to the system of equations.

$(3, 4)$ is not solution

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