Precalculus Examples

$x - y = - 1$ , $x - y = - 2$

Step 1

Solve the system of equations.

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Multiply each equation by the value that makes the coefficients of $x$ opposite.

$x - y = - 1$

$(- 1) \cdot (x - y) = (- 1) (- 2)$

Simplify.

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Simplify the left side.

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Simplify $(- 1) \cdot (x - y)$ .

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Apply the distributive property.

$x - y = - 1$

$- 1 x - 1 (- y) = (- 1) (- 2)$

Rewrite $- 1 x$ as $- x$ .

$x - y = - 1$

$- x - 1 (- y) = (- 1) (- 2)$

Multiply $- 1 (- y)$ .

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Multiply $- 1$ by $- 1$ .

$x - y = - 1$

$- x + 1 y = (- 1) (- 2)$

Multiply $y$ by $1$ .

$x - y = - 1$

$- x + y = (- 1) (- 2)$

$x - y = - 1$

$- x + y = (- 1) (- 2)$

$x - y = - 1$

$- x + y = (- 1) (- 2)$

$x - y = - 1$

$- x + y = (- 1) (- 2)$

Simplify the right side.

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Multiply $- 1$ by $- 2$ .

$x - y = - 1$

$- x + y = 2$

$x - y = - 1$

$- x + y = 2$

$x - y = - 1$

$- x + y = 2$

Add the two equations together to eliminate $x$ from the system.

		$x$	$-$	$y$	$=$	$-$	$1$
$+$	$-$	$x$	$+$	$y$	$=$		$2$
				$0$	$=$		$1$

Since $0 \neq 1$ , there are no solutions.

No solution

Step 2

Since the system has no solution, the equations and graphs are parallel and do not intersect. Thus, the system is inconsistent.

Inconsistent

Step 3

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