Precalculus Examples

$(6, 4)$

Step 1

$x = 6$ and $x = 4$ are the two real distinct solutions for the quadratic equation, which means that $x - 6$ and $x - 4$ are the factors of the quadratic equation.

$(x - 6) (x - 4) = 0$

Step 2

Expand $(x - 6) (x - 4)$ using the FOIL Method.

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Step 2.1

Apply the distributive property.

$x (x - 4) - 6 (x - 4) = 0$

Step 2.2

Apply the distributive property.

$x \cdot x + x \cdot - 4 - 6 (x - 4) = 0$

Step 2.3

Apply the distributive property.

$x \cdot x + x \cdot - 4 - 6 x - 6 \cdot - 4 = 0$

Step 3

Simplify and combine like terms.

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Step 3.1

Simplify each term.

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Step 3.1.1

Multiply $x$ by $x$ .

$x^{2} + x \cdot - 4 - 6 x - 6 \cdot - 4 = 0$

Step 3.1.2

Move $- 4$ to the left of $x$ .

$x^{2} - 4 \cdot x - 6 x - 6 \cdot - 4 = 0$

Step 3.1.3

Multiply $- 6$ by $- 4$ .

$x^{2} - 4 x - 6 x + 24 = 0$

Step 3.2

Subtract $6 x$ from $- 4 x$ .

$x^{2} - 10 x + 24 = 0$

Step 4

The standard quadratic equation using the given set of solutions ${6, 4}$ is $y = x^{2} - 10 x + 24$ .

$y = x^{2} - 10 x + 24$

Step 5

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