Precalculus Examples

$A = (6, 8, 9)$ , $B = (1, 5, 9)$

Step 1

$A$ is not a subset of $B$ because $A$ is not contained within $B$ .

A is not a subset of B

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$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$