Precalculus Examples

$(12, 12)$ , $(12, 24)$

Step 1

Use the midpoint formula to find the midpoint of the line segment.

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$

Step 2

Substitute in the values for $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ .

$(\frac{12 + 12}{2}, \frac{12 + 24}{2})$

Step 3

Cancel the common factor of $12 + 12$ and $2$ .

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Factor $2$ out of $12$ .

$(\frac{2 \cdot 6 + 12}{2}, \frac{12 + 24}{2})$

Factor $2$ out of $12$ .

$(\frac{2 \cdot 6 + 2 \cdot 6}{2}, \frac{12 + 24}{2})$

Factor $2$ out of $2 \cdot 6 + 2 \cdot 6$ .

$(\frac{2 \cdot (6 + 6)}{2}, \frac{12 + 24}{2})$

Cancel the common factors.

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Factor $2$ out of $2$ .

$(\frac{2 \cdot (6 + 6)}{2 (1)}, \frac{12 + 24}{2})$

Cancel the common factor.

$(\frac{2 \cdot (6 + 6)}{2 \cdot 1}, \frac{12 + 24}{2})$

Rewrite the expression.

$(\frac{6 + 6}{1}, \frac{12 + 24}{2})$

Divide $6 + 6$ by $1$ .

$(6 + 6, \frac{12 + 24}{2})$

Step 4

Add $6$ and $6$ .

$(12, \frac{12 + 24}{2})$

Step 5

Cancel the common factor of $12 + 24$ and $2$ .

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Factor $2$ out of $12$ .

$(12, \frac{2 \cdot 6 + 24}{2})$

Factor $2$ out of $24$ .

$(12, \frac{2 \cdot 6 + 2 \cdot 12}{2})$

Factor $2$ out of $2 \cdot 6 + 2 \cdot 12$ .

$(12, \frac{2 \cdot (6 + 12)}{2})$

Cancel the common factors.

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Factor $2$ out of $2$ .

$(12, \frac{2 \cdot (6 + 12)}{2 (1)})$

Cancel the common factor.

$(12, \frac{2 \cdot (6 + 12)}{2 \cdot 1})$

Rewrite the expression.

$(12, \frac{6 + 12}{1})$

Divide $6 + 12$ by $1$ .

$(12, 6 + 12)$

Step 6

Add $6$ and $12$ .

$(12, 18)$

Step 7

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