Precalculus Examples

$(6, 8)$ , $(- 9, - 3)$

Step 1

Use the distance formula to determine the distance between the two points.

$Distance = \sqrt{{(x_{2} - x_{1})}^{2} + {(y_{2} - y_{1})}^{2}}$

Step 2

Substitute the actual values of the points into the distance formula.

$\sqrt{{((- 9) - 6)}^{2} + {((- 3) - 8)}^{2}}$

Step 3

Simplify.

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Subtract $6$ from $- 9$ .

$\sqrt{{(- 15)}^{2} + {((- 3) - 8)}^{2}}$

Raise $- 15$ to the power of $2$ .

$\sqrt{225 + {((- 3) - 8)}^{2}}$

Subtract $8$ from $- 3$ .

$\sqrt{225 + {(- 11)}^{2}}$

Raise $- 11$ to the power of $2$ .

$\sqrt{225 + 121}$

Add $225$ and $121$ .

$\sqrt{346}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$\sqrt{346}$

Decimal Form:

$18.60107523 \dots$

Step 5

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