Solve for x

$e^{x} = \frac{1}{e^{20}}$

Step 1

Move $e^{20}$ to the numerator using the negative exponent rule $\frac{1}{b^{n}} = b^{- n}$ .

$e^{x} = e^{- 20}$

Step 2

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$x = - 20$

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$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$