Find the Perfect Square Trinomial

$z^{2} + 6 z$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $z$ by $2$ and square the result.

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Step 1.1

Divide $6$ by $2$ .

$3^{2}$

Step 1.2

Raise $3$ to the power of $2$ .

$9$

Step 2

Add $9$ to get the perfect square trinomial.

$z^{2} + 6 z + 9$

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$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$