Pre-Algebra Examples

 $\begin{array}{r} h = & 3 \\ r = & 3 \end{array}$

The surface area of a cone is equal to the area of the base plus the area of the cone.

$π \cdot {(r a d i u s)}^{2} + π \cdot ((r a d i u s) \sqrt{r a d i u s^{2} + h e i g h t^{2}})$

Substitute the values of the length $(r = 3)$ , the height $(h = 3)$ , and an approximation for $π (3.14)$ into the formula.

$(3.14) {(3)}^{2} + 3.14 (3) \sqrt{{(3)}^{2} + {(3)}^{2}}$

Simplify each term.

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Raise $3$ to the power of $2$ .

$3.14 \cdot 9 + 3.14 (3) \sqrt{{(3)}^{2} + {(3)}^{2}}$

Multiply $3.14$ by $9$ .

$28.26 + 3.14 (3) \sqrt{{(3)}^{2} + {(3)}^{2}}$

Multiply $3.14$ by $3$ .

$28.26 + 9.42 \sqrt{{(3)}^{2} + {(3)}^{2}}$

Raise $3$ to the power of $2$ .

$28.26 + 9.42 \sqrt{9 + {(3)}^{2}}$

Raise $3$ to the power of $2$ .

$28.26 + 9.42 \sqrt{9 + 9}$

Add $9$ and $9$ .

$28.26 + 9.42 \sqrt{18}$

Rewrite $18$ as $3^{2} \cdot 2$ .

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Factor $9$ out of $18$ .

$28.26 + 9.42 \sqrt{9 (2)}$

Rewrite $9$ as $3^{2}$ .

$28.26 + 9.42 \sqrt{3^{2} \cdot 2}$

Pull terms out from under the radical.

$28.26 + 9.42 (3 \sqrt{2})$

Multiply $9.42 (3 \sqrt{2})$ .

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Multiply $3$ by $9.42$ .

$28.26 + 28.26 \sqrt{2}$

Multiply $28.26$ by $\sqrt{2}$ .

$28.26 + 39.96567527$

Add $28.26$ and $39.96567527$ .

$68.22567527$

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