Pre-Algebra Examples

$x - y + 4 = 8$

Step 1

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Step 2

Rewrite in slope-intercept form.

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Move all terms not containing $y$ to the right side of the equation.

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Subtract $x$ from both sides of the equation.

$- y + 4 = 8 - x$

Subtract $4$ from both sides of the equation.

$- y = 8 - x - 4$

Subtract $4$ from $8$ .

$- y = - x + 4$

Divide each term in $- y = - x + 4$ by $- 1$ and simplify.

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Divide each term in $- y = - x + 4$ by $- 1$ .

$\frac{- y}{- 1} = \frac{- x}{- 1} + \frac{4}{- 1}$

Simplify the left side.

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Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- x}{- 1} + \frac{4}{- 1}$

Divide $y$ by $1$ .

$y = \frac{- x}{- 1} + \frac{4}{- 1}$

Simplify the right side.

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Simplify each term.

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Dividing two negative values results in a positive value.

$y = \frac{x}{1} + \frac{4}{- 1}$

Divide $x$ by $1$ .

$y = x + \frac{4}{- 1}$

Divide $4$ by $- 1$ .

$y = x - 4$

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