Pre-Algebra Examples

$y = 2 x - 5$

Choose $0$ to substitute in for $x$ and find the result.

$y = 2 (0) - 5$

Multiply $2$ by $0$ to get $0$ .

$y = 0 - 5$

Subtract $5$ from $0$ to get $- 5$ .

$y = - 5$

Choose $1$ to substitute in for $x$ and find the result.

$y = 2 (1) - 5$

Multiply $2$ by $1$ to get $2$ .

$y = 2 - 5$

Subtract $5$ from $2$ to get $- 3$ .

$y = - 3$

Choose $2$ to substitute in for $x$ and find the result.

$y = 2 (2) - 5$

Multiply $2$ by $2$ to get $4$ .

$y = 4 - 5$

Subtract $5$ from $4$ to get $- 1$ .

$y = - 1$

These are three possible solutions to the equation.

$(0, - 5), (1, - 3), (2, - 1)$

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]