Calculus Examples

$f (x) = x^{2} - x^{3} + 4 x$

Step 1

Find $f (- x)$ .

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Find $f (- x)$ by substituting $- x$ for all occurrence of $x$ in $f (x)$ .

$f (- x) = {(- x)}^{2} - {(- x)}^{3} + 4 (- x)$

Simplify each term.

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Apply the product rule to $- x$ .

$f (- x) = {(- 1)}^{2} x^{2} - {(- x)}^{3} + 4 (- x)$

Raise $- 1$ to the power of $2$ .

$f (- x) = 1 x^{2} - {(- x)}^{3} + 4 (- x)$

Multiply $x^{2}$ by $1$ .

$f (- x) = x^{2} - {(- x)}^{3} + 4 (- x)$

Apply the product rule to $- x$ .

$f (- x) = x^{2} - ({(- 1)}^{3} x^{3}) + 4 (- x)$

Multiply $- 1$ by ${(- 1)}^{3}$ by adding the exponents.

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Move ${(- 1)}^{3}$ .

$f (- x) = x^{2} + {(- 1)}^{3} \cdot (- 1 x^{3}) + 4 (- x)$

Multiply ${(- 1)}^{3}$ by $- 1$ .

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Raise $- 1$ to the power of $1$ .

$f (- x) = x^{2} + {(- 1)}^{3} \cdot ((- 1) x^{3}) + 4 (- x)$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f (- x) = x^{2} + {(- 1)}^{3 + 1} x^{3} + 4 (- x)$

Add $3$ and $1$ .

$f (- x) = x^{2} + {(- 1)}^{4} x^{3} + 4 (- x)$

Raise $- 1$ to the power of $4$ .

$f (- x) = x^{2} + 1 x^{3} + 4 (- x)$

Multiply $x^{3}$ by $1$ .

$f (- x) = x^{2} + x^{3} + 4 (- x)$

Multiply $- 1$ by $4$ .

$f (- x) = x^{2} + x^{3} - 4 x$

Step 2

A function is even if $f (- x) = f (x)$ .

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Check if $f (- x) = f (x)$ .

$x^{2} + x^{3} - 4 x$ $\neq$ $x^{2} - x^{3} + 4 x$

Since $x^{2} + x^{3} - 4 x$ $\neq$ $x^{2} - x^{3} + 4 x$ , the function is not even.

The function is not even

Step 3

A function is odd if $f (- x) = - f (x)$ .

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Find $- f (x)$ .

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Multiply $x^{2} - x^{3} + 4 x$ by $- 1$ .

$- f (x) = - (x^{2} - x^{3} + 4 x)$

Apply the distributive property.

$- f (x) = - x^{2} + x^{3} - (4 x)$

Multiply $4$ by $- 1$ .

$- f (x) = - x^{2} + x^{3} - 4 x$

Since $x^{2} + x^{3} - 4 x$ $\neq$ $- x^{2} + x^{3} - 4 x$ , the function is not odd.

The function is not odd

Step 4

The function is neither odd nor even

Step 5

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