Calculus Examples

$\frac{d y}{d x} - \frac{1}{x} y = 2 x$

Step 1

The integrating factor is defined by the formula $e^{\int P (x) d x}$ , where $P (x) = - \frac{1}{x}$ .

Tap for more steps...

Set up the integration.

$e^{\int - \frac{1}{x} d x}$

Integrate $- \frac{1}{x}$ .

Tap for more steps...

Since $- 1$ is constant with respect to $x$ , move $- 1$ out of the integral.

$e^{- \int \frac{1}{x} d x}$

The integral of $\frac{1}{x}$ with respect to $x$ is $\ln (| x |)$ .

$e^{- (\ln (| x |) + C)}$

Simplify.

$e^{- \ln (| x |) + C}$

Remove the constant of integration.

$e^{- \ln (x)}$

Use the logarithmic power rule.

$e^{\ln (x^{- 1})}$

Exponentiation and log are inverse functions.

$x^{- 1}$

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{x}$

Step 2

Multiply each term by the integrating factor $\frac{1}{x}$ .

Tap for more steps...

Multiply each term by $\frac{1}{x}$ .

$\frac{1}{x} \frac{d y}{d x} + \frac{1}{x} (- \frac{1}{x} y) = \frac{1}{x} (2 x)$

Simplify each term.

Tap for more steps...

Combine $\frac{1}{x}$ and $\frac{d y}{d x}$ .

$\frac{\frac{d y}{d x}}{x} + \frac{1}{x} (- \frac{1}{x} y) = \frac{1}{x} (2 x)$

Rewrite using the commutative property of multiplication.

$\frac{\frac{d y}{d x}}{x} - \frac{1}{x} (\frac{1}{x} y) = \frac{1}{x} (2 x)$

Combine $\frac{1}{x}$ and $y$ .

$\frac{\frac{d y}{d x}}{x} - \frac{1}{x} \cdot \frac{y}{x} = \frac{1}{x} (2 x)$

Multiply $- \frac{1}{x} \cdot \frac{y}{x}$ .

Tap for more steps...

Multiply $\frac{y}{x}$ by $\frac{1}{x}$ .

$\frac{\frac{d y}{d x}}{x} - \frac{y}{x \cdot x} = \frac{1}{x} (2 x)$

Raise $x$ to the power of $1$ .

$\frac{\frac{d y}{d x}}{x} - \frac{y}{x^{1} x} = \frac{1}{x} (2 x)$

Raise $x$ to the power of $1$ .

$\frac{\frac{d y}{d x}}{x} - \frac{y}{x^{1} x^{1}} = \frac{1}{x} (2 x)$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{\frac{d y}{d x}}{x} - \frac{y}{x^{1 + 1}} = \frac{1}{x} (2 x)$

Add $1$ and $1$ .

$\frac{\frac{d y}{d x}}{x} - \frac{y}{x^{2}} = \frac{1}{x} (2 x)$

Rewrite using the commutative property of multiplication.

$\frac{\frac{d y}{d x}}{x} - \frac{y}{x^{2}} = 2 \frac{1}{x} x$

Combine $2$ and $\frac{1}{x}$ .

$\frac{\frac{d y}{d x}}{x} - \frac{y}{x^{2}} = \frac{2}{x} x$

Cancel the common factor of $x$ .

Tap for more steps...

Cancel the common factor.

$\frac{\frac{d y}{d x}}{x} - \frac{y}{x^{2}} = \frac{2}{x} x$

Rewrite the expression.

$\frac{\frac{d y}{d x}}{x} - \frac{y}{x^{2}} = 2$

Step 3

Rewrite the left side as a result of differentiating a product.

$\frac{d}{d x} [\frac{1}{x} y] = 2$

Step 4

Set up an integral on each side.

$\int \frac{d}{d x} [\frac{1}{x} y] d x = \int 2 d x$

Step 5

Integrate the left side.

$\frac{1}{x} y = \int 2 d x$

Step 6

Apply the constant rule.

$\frac{1}{x} y = 2 x + C$

Step 7

Solve for $y$ .

Tap for more steps...

Combine $\frac{1}{x}$ and $y$ .

$\frac{y}{x} = 2 x + C$

Multiply each term in $\frac{y}{x} = 2 x + C$ by $x$ to eliminate the fractions.

Tap for more steps...

Multiply each term in $\frac{y}{x} = 2 x + C$ by $x$ .

$\frac{y}{x} x = 2 x \cdot x + C x$

Simplify the left side.

Tap for more steps...

Cancel the common factor of $x$ .

Tap for more steps...

Cancel the common factor.

$\frac{y}{x} x = 2 x \cdot x + C x$

Rewrite the expression.

$y = 2 x \cdot x + C x$

Simplify the right side.

Tap for more steps...

Multiply $x$ by $x$ by adding the exponents.

Tap for more steps...

Move $x$ .

$y = 2 (x \cdot x) + C x$

Multiply $x$ by $x$ .

$y = 2 x^{2} + C x$

Enter YOUR Problem