Basic Math Examples

 $\begin{array}{r} b_{1} = & 1 \\ b_{2} = & 6 \\ h = & 2 \end{array}$

The area of a trapezoid is equal to $\frac{1}{2}$ times the height times the sum of the bases $b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t (b_{1} + b_{2}))$

Substitute the values of the height $(h = 2)$ and bases ( $b_{1} = 1$ and $b_{2} = 6$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot (2 (1 + 6))$

Cancel the common factor of $2$ .

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Write $2 (1 + 6)$ as a fraction with denominator $1$ .

$\frac{1}{2} \cdot \frac{2 (1 + 6)}{1}$

Factor out the greatest common factor $2$ .

$\frac{1}{2 (1)} \cdot \frac{2 (1 + 6)}{1}$

Cancel the common factor.

$\frac{1}{2 \cdot 1} \cdot \frac{2 (1 + 6)}{1}$

Rewrite the expression.

$\frac{1}{1} \cdot \frac{1 + 6}{1}$

Simplify.

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Multiply $\frac{1}{1}$ and $\frac{1 + 6}{1}$ to get $\frac{1 + 6}{1}$ .

$\frac{1 + 6}{1}$

Divide $1 + 6$ by $1$ to get $1 + 6$ .

$1 + 6$

Add $1$ and $6$ to get $7$ .

$7$

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