Basic Math Examples

 $\begin{array}{r} b_{1} = & 10 \\ b_{2} = & 2 \\ h = & 1 \end{array}$

The area of a trapezoid is equal to $\frac{1}{2}$ times the height times the sum of the bases $b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t (b_{1} + b_{2}))$

Substitute the values of the height $(h = 1)$ and bases ( $b_{1} = 10$ and $b_{2} = 2$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot (1 (10 + 2))$

Multiply $10 + 2$ by $1$ .

$\frac{1}{2} \cdot (10 + 2)$

Add $10$ and $2$ .

$\frac{1}{2} \cdot 12$

Cancel the common factor of $2$ .

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Write $12$ as a fraction with denominator $1$ .

$\frac{1}{2} \cdot \frac{12}{1}$

Factor out the greatest common factor $2$ .

$\frac{1}{2 \cdot 1} \cdot \frac{2 \cdot 6}{1}$

Cancel the common factor.

$\frac{1}{2 \cdot 1} \cdot \frac{2 \cdot 6}{1}$

Rewrite the expression.

$\frac{1}{1} \cdot \frac{6}{1}$

Simplify.

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Multiply $\frac{1}{1}$ and $\frac{6}{1}$ .

$\frac{6}{1}$

Divide $6$ by $1$ .

$6$

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