Basic Math Examples

 $\begin{array}{r} b_{1} = & 6 \\ b_{2} = & 4 \\ h = & 6 \end{array}$

Step 1

The area of a trapezoid is equal to $\frac{1}{2}$ times the height times the sum of the bases $b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height $h = 6$ and bases ( $b_{1} = 6$ and $b_{2} = 4$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot 6 \cdot (6 + 4)$

Step 3

Cancel the common factor of $2$ .

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Factor $2$ out of $6$ .

$\frac{1}{2} \cdot (2 (3)) \cdot (6 + 4)$

Cancel the common factor.

$\frac{1}{2} \cdot (2 \cdot 3) \cdot (6 + 4)$

Rewrite the expression.

$3 \cdot (6 + 4)$

Step 4

Simplify the expression.

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Add $6$ and $4$ .

$3 \cdot 10$

Multiply $3$ by $10$ .

$30$

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