Basic Math Examples

 $\begin{array}{r} b_{1} = & 7 \\ b_{2} = & 10 \\ h = & 10 \end{array}$

The area of a trapezoid is equal to $\frac{1}{2}$ times the height times the sum of the bases $b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t (b_{1} + b_{2}))$

Substitute the values of the height $(h = 10)$ and bases ( $b_{1} = 7$ and $b_{2} = 10$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot (10 (7 + 10))$

Cancel the common factor of $2$ .

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Write $10 (7 + 10)$ as a fraction with denominator $1$ .

$\frac{1}{2} \cdot \frac{10 (7 + 10)}{1}$

Factor out the greatest common factor $2$ .

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Factor $2$ out of $10$ .

$\frac{1}{2 \cdot 1} \cdot \frac{2 \cdot 5 (7 + 10)}{1}$

Factor $2$ out of $10$ .

$\frac{1}{2 (1)} \cdot \frac{2 (5) (7 + 10)}{1}$

Move $2$ .

$\frac{1}{2 (1)} \cdot \frac{2 ((5) (7 + 10))}{1}$

Multiply $5$ by $7 + 10$ .

$\frac{1}{2 (1)} \cdot \frac{2 (5 (7 + 10))}{1}$

Cancel the common factor.

$\frac{1}{2 \cdot 1} \cdot \frac{2 (5 (7 + 10))}{1}$

Rewrite the expression.

$\frac{1}{1} \cdot \frac{5 (7 + 10)}{1}$

Simplify.

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Multiply $\frac{1}{1}$ and $\frac{5 (7 + 10)}{1}$ .

$\frac{5 (7 + 10)}{1}$

Divide $5 (7 + 10)$ by $1$ .

$5 (7 + 10)$

Add $7$ and $10$ .

$5 \cdot 17$

Multiply $5$ by $17$ .

$85$

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