Basic Math Examples

 $\begin{array}{r} b_{1} = & 6 \\ b_{2} = & 9 \\ h = & 2 \end{array}$

The area of a trapezoid is equal to $\frac{1}{2}$ times the height times the sum of the bases $b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t (b_{1} + b_{2}))$

Substitute the values of the height $(h = 2)$ and bases ( $b_{1} = 6$ and $b_{2} = 9$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot (2 (6 + 9))$

Cancel the common factor of $2$ .

Tap for more steps...

Write $2 (6 + 9)$ as a fraction with denominator $1$ .

$\frac{1}{2} \cdot \frac{2 (6 + 9)}{1}$

Factor out the greatest common factor $2$ .

$\frac{1}{2 (1)} \cdot \frac{2 (6 + 9)}{1}$

Cancel the common factor.

$\frac{1}{2 \cdot 1} \cdot \frac{2 (6 + 9)}{1}$

Rewrite the expression.

$\frac{1}{1} \cdot \frac{6 + 9}{1}$

Simplify.

Tap for more steps...

Multiply $\frac{1}{1}$ and $\frac{6 + 9}{1}$ .

$\frac{6 + 9}{1}$

Divide $6 + 9$ by $1$ .

$6 + 9$

Add $6$ and $9$ .

$15$

Enter YOUR Problem