Algebra Examples

$(x + 3) - y = 4$ , $x - 4 y = 10$ , $(- 2, - 3)$

Multiply $- 1$ by $- 3$ .

$- 2 + 3 + 3 = 4$

$(- 2) - 4 \cdot - 3 = 10$

Add $- 2$ and $3$ .

$1 + 3 = 4$

$(- 2) - 4 \cdot - 3 = 10$

Add $1$ and $3$ .

$4 = 4$

$(- 2) - 4 \cdot - 3 = 10$

Since $4 = 4$ , the equation will always be true.

Always true

$(- 2) - 4 \cdot - 3 = 10$

Multiply $- 4$ by $- 3$ .

Always true

$- 2 + 12 = 10$

Add $- 2$ and $12$ .

Always true

$10 = 10$

Since $10 = 10$ , the equation will always be true.

Always true

The ordered pair is a solution to the system of equations.

$(- 2, - 3)$ is a solution

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