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Algebra Examples

$x^{2} + y = 0$ , $y = 5 x^{2}$ , $(0, 0)$

Rewrite the equation as $0 = {(0)}^{2} + 0$ .

$0 = {(0)}^{2} + 0$

$(0) = 5 {(0)}^{2}$

Simplify each term.

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Remove parentheses around $0$ .

$0 = 0^{2} + 0$

$(0) = 5 {(0)}^{2}$

Raising $0$ to any positive power yields $0$ .

$0 = 0 + 0$

$(0) = 5 {(0)}^{2}$

$0 = 0 + 0$

$(0) = 5 {(0)}^{2}$

Add $0$ and $0$ .

$0 = 0$

$(0) = 5 {(0)}^{2}$

Since $0 = 0$ , the equation will always be true.

Always true

$(0) = 5 {(0)}^{2}$

Rewrite the equation as $5 {(0)}^{2} = 0$ .

$A l w a y s (t r u e)$

$5 {(0)}^{2} = 0$

Remove parentheses around $0$ .

$A l w a y s (t r u e)$

$5 \cdot 0^{2} = 0$

Raising $0$ to any positive power yields $0$ .

$A l w a y s (t r u e)$

$5 \cdot 0 = 0$

Multiply $5$ by $0$ .

$A l w a y s (t r u e)$

$0 = 0$

Since $0 = 0$ , the equation will always be true.

$A l w a y s (t r u e)$

Always true

The ordered pair is a solution to the system of equations.

$(0, 0)$ is a solution

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$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$