Algebra Examples

$(- 2, - 4)$ , $(- 8, - 5)$

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{change in y}{change in x}$

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{- 5 - (- 4)}{- 8 - (- 2)}$

Simplify.

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Simplify the numerator.

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Multiply $- 1$ by $- 4$ to get $4$ .

$m = \frac{- 5 + 4}{- 8 - (- 2)}$

Add $- 5$ and $4$ to get $- 1$ .

$m = \frac{- 1}{- 8 - (- 2)}$

Simplify the denominator.

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Remove parentheses.

$m = \frac{- 1}{- 8 - (- 2)}$

Multiply $- 1$ by $- 2$ to get $2$ .

$m = \frac{- 1}{- 8 + 2}$

Add $- 8$ and $2$ to get $- 6$ .

$m = \frac{- 1}{- 6}$

Dividing two negative values results in a positive value.

$m = \frac{1}{6}$

The slope of a perpendicular line is the negative reciprocal of the slope of the line that passes through the two given points.

$m_{perpendicular} = - \frac{1}{m}$

Simplify $- \frac{1}{\frac{1}{6}}$ .

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Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = - (1 \cdot 6)$

Multiply $6$ by $1$ to get $6$ .

$m_{perpendicular} = - 1 \cdot 6$

Multiply $- 1$ by $6$ to get $- 6$ .

$m_{perpendicular} = - 6$

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