Algebra Examples

$(1, 2)$ , $(3, 4)$

Find the value of the slope.

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Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{change in y}{change in x}$

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{4 - (2)}{3 - (1)}$

Simplify.

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Simplify the numerator.

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Multiply $- 1$ by $2$ .

$m = \frac{4 - 2}{3 - (1)}$

Subtract $2$ from $4$ .

$m = \frac{2}{3 - (1)}$

Simplify the denominator.

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Multiply $- 1$ by $1$ .

$m = \frac{2}{3 - 1}$

Subtract $1$ from $3$ .

$m = \frac{2}{2}$

Divide $2$ by $2$ .

$m = 1$

Find the value of the y-intercept.

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Substitute the value of $m$ into the slope-intercept form of the equation, $y = m x + b$ .

$y = (1) \cdot x + b$

Substitute the value of $x$ into the slope-intercept form of the equation, $y = m x + b$ .

$y = (1) \cdot (1) + b$

Substitute the value of $y$ into the slope-intercept form of the equation, $y = m x + b$ .

$2 = (1) \cdot (1) + b$

Rewrite the equation as $(1) \cdot (1) + b = 2$ .

$(1) \cdot (1) + b = 2$

Multiply $1$ by $1$ .

$1 + b = 2$

Move all terms not containing $b$ to the right side of the equation.

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Subtract $1$ from both sides of the equation.

$b = 2 - 1$

Subtract $1$ from $2$ .

$b = 1$

The values of the slope and y-intercept are $m = 1$ and $b = 1$ .

$m = 1$

$b = 1$

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