Find the Basis and Dimension for the Row Space of the Matrix

$[\begin{array}{c} 2 & 0 \\ 2 & 4 \end{array}]$

Step 1

Find the reduced row echelon form.

Tap for more steps...

Step 1.1

Multiply each element of $R_{1}$ by $\frac{1}{2}$ to make the entry at $1, 1$ a $1$ .

Tap for more steps...

Step 1.1.1

Multiply each element of $R_{1}$ by $\frac{1}{2}$ to make the entry at $1, 1$ a $1$ .

$[\begin{array}{c} \frac{2}{2} & \frac{0}{2} \\ 2 & 4 \end{array}]$

Step 1.1.2

Simplify $R_{1}$ .

$[\begin{array}{c} 1 & 0 \\ 2 & 4 \end{array}]$

Step 1.2

Perform the row operation $R_{2} = R_{2} - 2 R_{1}$ to make the entry at $2, 1$ a $0$ .

Tap for more steps...

Step 1.2.1

Perform the row operation $R_{2} = R_{2} - 2 R_{1}$ to make the entry at $2, 1$ a $0$ .

$[\begin{array}{c} 1 & 0 \\ 2 - 2 \cdot 1 & 4 - 2 \cdot 0 \end{array}]$

Step 1.2.2

Simplify $R_{2}$ .

$[\begin{array}{c} 1 & 0 \\ 0 & 4 \end{array}]$

Step 1.3

Multiply each element of $R_{2}$ by $\frac{1}{4}$ to make the entry at $2, 2$ a $1$ .

Tap for more steps...

Step 1.3.1

Multiply each element of $R_{2}$ by $\frac{1}{4}$ to make the entry at $2, 2$ a $1$ .

$[\begin{array}{c} 1 & 0 \\ \frac{0}{4} & \frac{4}{4} \end{array}]$

Step 1.3.2

Simplify $R_{2}$ .

$[\begin{array}{c} 1 & 0 \\ 0 & 1 \end{array}]$

Step 2

The row space of a matrix is the collection of all possible linear combinations of its row vectors.

$c_{1} [\begin{array}{c} 1 & 0 \end{array}] + c_{2} [\begin{array}{c} 0 & 1 \end{array}]$

Step 3

The basis for $Row (A)$ is the non-zero rows of a matrix in reduced row echelon form. The dimension of the basis for $Row (A)$ is the number of vectors in the basis.

Basis of $Row (A)$ : ${[\begin{array}{c} 1 & 0 \end{array}], [\begin{array}{c} 0 & 1 \end{array}]}$

Dimension of $Row (A)$ : $2$

Enter YOUR Problem

Find the Basis and Dimension for the Row Space of the Matrix

Matrices

How to Use Step-by-Step Examples

Why use Mathway?

Explore More Algebra Help