Algebra Examples

$y = x + 3$

Choose $0$ to substitute in for $x$ and find the result.

$y = (0) + 3$

Remove the parentheses around the expression $0$ .

$y = 0 + 3$

Add $0$ and $3$ to get $3$ .

$y = 3$

Choose $1$ to substitute in for $x$ and find the result.

$y = (1) + 3$

Remove the parentheses around the expression $1$ .

$y = 1 + 3$

Add $1$ and $3$ to get $4$ .

$y = 4$

Choose $2$ to substitute in for $x$ and find the result.

$y = (2) + 3$

Remove the parentheses around the expression $2$ .

$y = 2 + 3$

Add $2$ and $3$ to get $5$ .

$y = 5$

These are three possible solutions to the equation.

$(0, 3), (1, 4), (2, 5)$

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]