Algebra Examples

$f (x) = 4 x^{2} + 2$ , $f (x) = 4 x + 1$

Substitute $4 x + 1$ for $f (x)$ .

$4 x + 1 = 4 x^{2} + 2$

Subtract $4 x^{2}$ from both sides of the equation.

$4 x + 1 - 4 x^{2} = 2$

Move $2$ to the left side of the equation by subtracting it from both sides.

$4 x + 1 - 4 x^{2} - 2 = 0$

Subtract $2$ from $1$ .

$4 x - 4 x^{2} - 1 = 0$

Factor the left side of the equation.

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Factor $- 1$ out of $4 x - 4 x^{2} - 1$ .

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Reorder $4 x$ and $- 4 x^{2}$ .

$- 4 x^{2} + 4 x - 1 = 0$

Factor $- 1$ out of $- 4 x^{2}$ .

$- (4 x^{2}) + 4 x - 1 = 0$

Factor $- 1$ out of $4 x$ .

$- (4 x^{2}) - (- 4 x) - 1 = 0$

Rewrite $- 1$ as $- 1 (1)$ .

$- (4 x^{2}) - (- 4 x) - 1 \cdot 1 = 0$

Factor $- 1$ out of $- (4 x^{2}) - (- 4 x)$ .

$- (4 x^{2} - 4 x) - 1 \cdot 1 = 0$

Factor $- 1$ out of $- (4 x^{2} - 4 x) - 1 (1)$ .

$- (4 x^{2} - 4 x + 1) = 0$

Factor using the perfect square rule.

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Rewrite $4 x^{2}$ as ${(2 x)}^{2}$ .

$- ({(2 x)}^{2} - 4 x + 1) = 0$

Rewrite $1$ as $1^{2}$ .

$- ({(2 x)}^{2} - 4 x + 1^{2}) = 0$

Check the middle term by multiplying $2 a b$ and compare this result with the middle term in the original expression.

$2 a b = 2 \cdot (2 x) \cdot - 1$

Simplify.

$2 a b = - 4 x$

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = 2 x$ and $b = - 1$ .

$- {(2 x - 1)}^{2} = 0$

Set $2 x - 1$ equal to $0$ and solve for $x$ .

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Set the factor equal to $0$ .

$2 x - 1 = 0$

Add $1$ to both sides of the equation.

$2 x = 1$

Divide each term by $2$ and simplify.

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Divide each term in $2 x = 1$ by $2$ .

$\frac{2 x}{2} = \frac{1}{2}$

Cancel the common factor of $2$ .

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Cancel the common factor.

$\frac{2 x}{2} = \frac{1}{2}$

Divide $x$ by $1$ .

$x = \frac{1}{2}$

The solution is the result of $2 x - 1 = 0$ .

$x = \frac{1}{2}$

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