Algebra Examples

$4 x^{2} + 9 y^{2} + 8 x + 54 y + 52 = 3$

Move $52$ to the right side of the equation because it does not contain a variable.

$4 x^{2} + 9 y^{2} + 8 x + 54 y = - 52 + 3$

Add $- 52$ and $3$ .

$4 x^{2} + 9 y^{2} + 8 x + 54 y = - 49$

Complete the square for $4 x^{2} + 8 x$ .

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Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 4, b = 8, c = 0$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{8}{2 (4)}$

Simplify the right side.

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Reduce the expression by cancelling the common factors.

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Factor $2$ out of $8$ .

$d = \frac{2 \cdot 4}{2 \cdot 4}$

Cancel the common factors.

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Factor $2$ out of $2 \cdot 4$ .

$d = \frac{2 \cdot 4}{2 (4)}$

Cancel the common factor.

$d = \frac{2 \cdot 4}{2 \cdot 4}$

Rewrite the expression.

$d = \frac{4}{4}$

Reduce the expression by cancelling the common factors.

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Cancel the common factor.

$d = \frac{4}{4}$

Divide $1$ by $1$ .

$d = 1$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

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Simplify each term.

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Raise $8$ to the power of $2$ .

$e = 0 - \frac{64}{4 \cdot 4}$

Multiply $4$ by $4$ .

$e = 0 - \frac{64}{16}$

Divide $64$ by $16$ .

$e = 0 - 1 \cdot 4$

Multiply $- 1$ by $4$ .

$e = 0 - 4$

Subtract $4$ from $0$ .

$e = - 4$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $a {(x + d)}^{2} + e$ .

$4 {(x + 1)}^{2} - 4$

Substitute $4 {(x + 1)}^{2} - 4$ for $4 x^{2} + 8 x$ in the equation $4 x^{2} + 9 y^{2} + 8 x + 54 y = - 49$ .

$4 {(x + 1)}^{2} - 4 + 9 y^{2} + 54 y = - 49$

Move $- 4$ to the right side of the equation by adding $4$ to both sides.

$4 {(x + 1)}^{2} + 9 y^{2} + 54 y = - 49 + 4$

Complete the square for $9 y^{2} + 54 y$ .

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Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 9, b = 54, c = 0$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{54}{2 (9)}$

Simplify the right side.

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Reduce the expression by cancelling the common factors.

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Factor $2$ out of $54$ .

$d = \frac{2 \cdot 27}{2 \cdot 9}$

Cancel the common factors.

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Factor $2$ out of $2 \cdot 9$ .

$d = \frac{2 \cdot 27}{2 (9)}$

Cancel the common factor.

$d = \frac{2 \cdot 27}{2 \cdot 9}$

Rewrite the expression.

$d = \frac{27}{9}$

Reduce the expression by cancelling the common factors.

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Factor $9$ out of $27$ .

$d = \frac{9 \cdot 3}{9}$

Cancel the common factors.

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Factor $9$ out of $9$ .

$d = \frac{9 \cdot 3}{9 (1)}$

Cancel the common factor.

$d = \frac{9 \cdot 3}{9 \cdot 1}$

Rewrite the expression.

$d = \frac{3}{1}$

Divide $3$ by $1$ .

$d = 3$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

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Simplify each term.

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Raise $54$ to the power of $2$ .

$e = 0 - \frac{2916}{4 \cdot 9}$

Multiply $4$ by $9$ .

$e = 0 - \frac{2916}{36}$

Divide $2916$ by $36$ .

$e = 0 - 1 \cdot 81$

Multiply $- 1$ by $81$ .

$e = 0 - 81$

Subtract $81$ from $0$ .

$e = - 81$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $a {(x + d)}^{2} + e$ .

$9 {(y + 3)}^{2} - 81$

Substitute $9 {(y + 3)}^{2} - 81$ for $9 y^{2} + 54 y$ in the equation $4 x^{2} + 9 y^{2} + 8 x + 54 y = - 49$ .

$4 {(x + 1)}^{2} + 9 {(y + 3)}^{2} - 81 = - 49 + 4$

Move $- 81$ to the right side of the equation by adding $81$ to both sides.

$4 {(x + 1)}^{2} + 9 {(y + 3)}^{2} = - 49 + 4 + 81$

Simplify $- 49 + 4 + 81$ .

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Add $- 49$ and $4$ .

$4 {(x + 1)}^{2} + 9 {(y + 3)}^{2} = - 45 + 81$

Add $- 45$ and $81$ .

$4 {(x + 1)}^{2} + 9 {(y + 3)}^{2} = 36$

Divide each term by $36$ to make the right side equal to one.

$\frac{4 {(x + 1)}^{2}}{36} + \frac{9 {(y + 3)}^{2}}{36} = \frac{36}{36}$

Simplify each term in the equation in order to set the right side equal to $1$ . The standard form of an ellipse or hyperbola requires the right side of the equation be $1$ .

$\frac{{(x + 1)}^{2}}{9} + \frac{{(y + 3)}^{2}}{4} = 1$

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