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Rang	Thema	Aufgabe	Formatierte Aufgabe
24601	x 구하기	3sin(x)^2+sin(x)-2=0	$3 \sin^{2} (x) + \sin (x) - 2 = 0$
24602	@VAR 구하기	3t^2=7t-4	$3 t^{2} = 7 t - 4$
24603	x 구하기	3tan(2x)^2-1=0	$3 \tan^{2} (2 x) - 1 = 0$
24604	x 구하기	3x^2+2y^2-2x+5y=11	$3 x^{2} + 2 y^{2} - 2 x + 5 y = 11$
24605	@VAR 구하기	30=pi/6	$30 = \frac{π}{6}$
24606	x 구하기	3cos(x)=3cos(2x)	$3 \cos (x) = 3 \cos (2 x)$
24607	x 구하기	3cot(x)-7=-5	$3 \cot (x) - 7 = - 5$
24608	x 구하기	3cot(x+2)=5	$3 \cot (x + 2) = 5$
24609	x 구하기	-3-sin(x)=-2-2sin(x)	$- 3 - \sin (x) = - 2 - 2 \sin (x)$
24610	x 구하기	3y=x	$3 y = x$
24611	@VAR 구하기	4(a)-(a+5)+8=0	$4 (a) - (a + 5) + 8 = 0$
24612	@VAR 구하기	4 4/5	$4 \frac{4}{5}$
24613	x 구하기	4arcsin(x)=pi	$4 \arcsin (x) = π$
24614	x 구하기	4x^2-16x+16=0	$4 x^{2} - 16 x + 16 = 0$
24615	x 구하기	4+2cot(x)=12-( Quadratwurzel von 3)/3+cot(x)	$4 + 2 \cot (x) = 12 - \frac{\sqrt{3}}{3} + \cot (x)$
24616	Vereinfache mithilfe der Halbwinkelformel	sin(112.5 Grad )	$4 \cos (x) \cos (\frac{π}{4} + x) \cos (\frac{π}{4} - x) = \cos (x) + \cos (3 x)$
24617	x 구하기	4sin(x)+10=12	$4 \sin (x) + 10 = 12$
24618	x 구하기	4x+2i=8+yi	$4 x + 2 i = 8 + y i$
24619	@VAR 구하기	5.878*180/(p^57.295)=1058.04/p	$5.878 \cdot \frac{180}{p^{57.295}} = \frac{1058.04}{p}$
24620	x 구하기	5cos(2x)=4	$5 \cos (2 x) = 4$
24621	x 구하기	5cot(x)+1=4	$5 \cot (x) + 1 = 4$
24622	x 구하기	6x^2-4x-12=0	$6 x^{2} - 4 x - 12 = 0$
24623	@VAR 구하기	6=0.5r^2(1/4)	$6 = 0.5 r^{2} (\frac{1}{4})$
24624	x 구하기	6cos(2x)=6cos(x)	$6 \cos (2 x) = 6 \cos (x)$
24625	x 구하기	6cot(x+5)=-1	$6 \cot (x + 5) = - 1$
24626	x 구하기	6sin(x)=-6cos(x)	$6 \sin (x) = - 6 \cos (x)$
24627	x 구하기	6x-3y=4a	$6 x - 3 y = 4 a$
24628	y 구하기	7 = square root of y+2	$7 = \sqrt{y + 2}$
24629	@VAR 구하기	75+50m=175	$75 + 50 m = 175$
24630	@VAR 구하기	-8=a(0)^2+b(0)+c	$- 8 = a {(0)}^{2} + b (0) + c$
24631	x 구하기	8sin(2x)=6	$8 \sin (2 x) = 6$
24632	x 구하기	Quadratwurzel von 1-cos(2x)^2=\|sin(x)\|	$\sqrt{1 - \cos^{2} (2 x)} = \| \sin (x) \|$
24633	x 구하기	Quadratwurzel von 1-sin(x)^2=cos(x)	$\sqrt{1 - \sin^{2} (x)} = \cos (x)$
24634	x 구하기	Quadratwurzel von 1-sin(x)*sin(x)=cos(x)	$\sqrt{1 - \sin (x) \cdot \sin (x)} = \cos (x)$
24635	@VAR 구하기	Quadratwurzel von 2sin(A)-1=0	$\sqrt{2} \sin (A) - 1 = 0$
24636	x 구하기	Quadratwurzel von 3x+5=6	$\sqrt{3 x + 5} = 6$
24637	x 구하기	siebte Wurzel von 7x-9 = siebte Wurzel von 8x+2	$\sqrt[7]{7 x} - 9 = \sqrt[7]{8 x} + 2$
24638	x 구하기	(cot(x)^2)/(csc(x))=csc(x)-sin(x)	$\frac{\cot^{2} (x)}{\csc (x)} = \csc (x) - \sin (x)$
24639	x 구하기	(csc(x)^2)/(csc(x)^2-1)-1=tan(x)^2	$\frac{\csc^{2} (x)}{\csc^{2} (x) - 1} - 1 = \tan^{2} (x)$
24640	Bestimme den modulo 2π gleichen Winkel	-(4pi)/3	$\frac{\sec^{2} (x)}{2 \tan (x)} = \csc (2 x)$
24641	x 구하기	(sin(x)^2+2cos(x)-1)/(sin(x)^2+3cos(x)-3)=1/(1-sec(x))	$\frac{\sin^{2} (x) + 2 \cos (x) - 1}{\sin^{2} (x) + 3 \cos (x) - 3} = \frac{1}{1 - \sec (x)}$
24642	@VAR 구하기	(tan(t)^2)/(sec(t))=sec(t)-cos(t)	$\frac{\tan^{2} (t)}{\sec (t)} = \sec (t) - \cos (t)$
24643	x 구하기	sin(x)^2+tan(x)^2=sec(x)^2	$\sin^{2} (x) + \tan^{2} (x) = \sec^{2} (x)$
24644	x 구하기	(tan(x)+sec(x)-1)/(tan(x)-sec(x)+1)=tan(x)+sec(x)	$\frac{\tan (x) + \sec (x) - 1}{\tan (x) - \sec (x) + 1} = \tan (x) + \sec (x)$
24645	x 구하기	(tan(x)sec(x))/(csc(x))cot(x)=tan(x)	$\frac{\tan (x) \cdot \sec (x)}{\csc (x)} \cdot \cot (x) = \tan (x)$
24646	x 구하기	(tan(x)+cot(x))/(csc(x))=sec(x)	$\frac{\tan (x) + \cot (x)}{\csc (x)} = \sec (x)$
24647	x 구하기	(tan(x)+cot(y))/(tan(x)*cot(y))=tan(y)+cot(x)	$\frac{\tan (x) + \cot (y)}{\tan (x) \cdot \cot (y)} = \tan (y) + \cot (x)$
24648	x 구하기	(tan(x)-1)/(tan(x)+1)=(1-cot(x))/(1+cot(x))	$\frac{\tan (x) - 1}{\tan (x) + 1} = \frac{1 - \cot (x)}{1 + \cot (x)}$
24649	x 구하기	tan(x)^2+6=sec(x)^2+5	$\tan^{2} (x) + 6 = \sec^{2} (x) + 5$
24650	x 구하기	tan(x)^2=(1-cos(2x))/(1+cos(2x))	$\tan^{2} (x) = \frac{1 - \cos (2 x)}{1 + \cos (2 x)}$
24651	x 구하기	Quadratwurzel von (cos(x))/(tan(x))=cot(x)	$\sqrt{\frac{\cos (x)}{\tan (x)}} = \cot (x)$
24652	x 구하기	Quadratwurzel von 1-cos(x)^2=sin(x)	$\sqrt{1 - \cos^{2} (x)} = \sin (x)$
24653	@VAR 구하기	Logarithmische Basis u von 15/16=v	$\log_{u} (\frac{15}{16}) = v$
24654	x 구하기	pi/3(x)=2sin(x)+cos(3x)	$\frac{π}{3} (x) = 2 \sin (x) + \cos (3 x)$
24655	@VAR 구하기	r^2+2r-24=0	$r^{2} + 2 r - 24 = 0$
24656	@VAR 구하기	r^2=75	$r^{2} = 75$
24657	x 구하기	sec(x)^4-tan(x)^4-2tan(x)^2=1	$\sec^{4} (x) - \tan^{4} (x) - 2 \tan^{2} (x) = 1$
24658	Solve for θ in Radians	tan(theta)-1=0	$\frac{\sin (x) + 1}{\cos (x)} = \frac{\cos (x)}{1 - \sin (x)}$
24659	x 구하기	(sin(pi/2+x))/(sin(pi-x))=cot(x)	$\frac{\sin (\frac{π}{2} + x)}{\sin (π - x)} = \cot (x)$
24660	x 구하기	(sin(53.1301))/10=(sin(x))/8	$\frac{\sin (53.1301)}{10} = \frac{\sin (x)}{8}$
24661	x 구하기	(sin(62))/x=(sin(39))/15	$\frac{\sin (62)}{x} = \frac{\sin (39)}{15}$
24662	x 구하기	(sin(x)+sin(3x)+sin(5x))/(cos(3x)+cos(3x)+cos(5x))=tan(3x)	$\frac{\sin (x) + \sin (3 x) + \sin (5 x)}{\cos (3 x) + \cos (3 x) + \cos (5 x)} = \tan (3 x)$
24663	x 구하기	(sin(x)+sin(y))/(cos(x)-cos(y))=cot(x)	$\frac{\sin (x) + \sin (y)}{\cos (x) - \cos (y)} = \cot (x)$
24664	x 구하기	(sin(x+y))/(sin(x-y))=(tan(x)+tan(y))/(tan(x)-tan(y))	$\frac{\sin (x + y)}{\sin (x - y)} = \frac{\tan (x) + \tan (y)}{\tan (x) - \tan (y)}$
24665	x 구하기	(cot(x))/(1+csc(x))=(csc(x)-1)/(cot(x))	$\frac{\cot (x)}{1 + \csc (x)} = \frac{\csc (x) - 1}{\cot (x)}$
24666	x 구하기	(cot(x))/(csc(x)-1)=(csc(x)+1)/(cot(x))	$\frac{\cot (x)}{\csc (x) - 1} = \frac{\csc (x) + 1}{\cot (x)}$
24667	x 구하기	(cot(x))/(tan(x))=tan(x)^2	$\frac{\cot (x)}{\tan (x)} = \tan^{2} (x)$
24668	@VAR 구하기	logarithmische Basis a+ Logarithmus von a+21=2	$\log (a) + \log (a + 21) = 2$
24669	x 구하기	(cos(2x))/(cos(x)^2)=sec(x)^2-2tan(x)^2	$\frac{\cos (2 x)}{\cos^{2} (x)} = \sec^{2} (x) - 2 \tan^{2} (x)$
24670	x 구하기	(cos(x))/(csc(x)-sin(x))=tan(x)	$\frac{\cos (x)}{\csc (x) - \sin (x)} = \tan (x)$
24671	x 구하기	(cos(x))/(sin(x))-(cot(x))/(sec(x))=(1-cos(x))/(tan(x))	$\frac{\cos (x)}{\sin (x)} - \frac{\cot (x)}{\sec (x)} = \frac{1 - \cos (x)}{\tan (x)}$
24672	x 구하기	cos(x)^2-cot(x)^2=-cos(x)^2cot(x)^2	$\cos^{2} (x) - \cot^{2} (x) = - \cos^{2} (x) \cot^{2} (x)$
24673	x 구하기	cos(x)^2-sin(x)^2=(1-tan(x)^2)/(1+tan(x)^2)	$\cos^{2} (x) - \sin^{2} (x) = \frac{1 - \tan^{2} (x)}{1 + \tan^{2} (x)}$
24674	Ermittele den Kotangens bei gegebenem Punkt	(-5,-12)	$\cos^{2} (x) - \sin^{2} (x) = 2 \cos^{2} (x - 1)$
24675	x 구하기	cos(x)^2+tan(x)^2=sec(x)^2	$\cos^{2} (x) + \tan^{2} (x) = \sec^{2} (x)$
24676	x 구하기	cos(x)^2=-( Quadratwurzel von 3)/2	$\cos^{2} (x) = - \frac{\sqrt{3}}{2}$
24677	Vereinfache mithilfe der Halbwinkelformel	tan(22.5 Grad )	$\cos^{2} (x) = \frac{1 - \cos (2 x)}{2}$
24678	x 구하기	cos(x)^2csc(x)sec(x)=cot(x)	$\cos^{2} (x) \csc (x) \sec (x) = \cot (x)$
24679	x 구하기	(1-cos(x))/(sin(x)) = square root of ((1-cos(x))^2)/(1-cos(x)^2)	$\frac{1 - \cos (x)}{\sin (x)} = \sqrt{\frac{{(1 - \cos (x))}^{2}}{1 - \cos^{2} (x)}}$
24680	x 구하기	(1-csc(x))/(1-sin(x))=-csc(x)	$\frac{1 - \csc (x)}{1 - \sin (x)} = - \csc (x)$
24681	x 구하기	(1-sin(x))/(1+sin(x))=(sec(x)-tan(x))^2	$\frac{1 - \sin (x)}{1 + \sin (x)} = {(\sec (x) - \tan (x))}^{2}$
24682	x 구하기	2/( Quadratwurzel von 3)*cos(3x)=1	$\frac{2}{\sqrt{3}} \cdot \cos (3 x) = 1$
24683	x 구하기	2/( Quadratwurzel von 3cos(x)+sin(x))=sec(pi/6-x)	$\frac{2}{\sqrt{3} \cos (x) + \sin (x)} = \sec (\frac{π}{6} - x)$
24684	x 구하기	2/3*cos(x)=f(x)	$\frac{2}{3} \cdot \cos (x) = f (x)$
24685	x 구하기	(2tan(x))/(1-tan(x)^2)-cot(x)=0	$\frac{2 \tan (x)}{1 - \tan^{2} (x)} - \cot (x) = 0$
24686	x 구하기	3^(x^(2-12))=9^(2x)	$3^{x^{2 - 12}} = 9^{2 x}$
24687	@VAR 구하기	5/3+3*5=4 1/6	$\frac{5}{3} + 3 \cdot 5 = 4 \frac{1}{6}$
24688	x 구하기	670/4020=201/16-67/(32(670/4020))+67/(13sin(x))	$\frac{670}{4020} = \frac{201}{16} - \frac{67}{32 (\frac{670}{4020})} + \frac{67}{13 \sin (x)}$
24689	x 구하기	7/(x-3)-8=10/(2x-3)	$\frac{7}{x - 3} - 8 = \frac{10}{2 x - 3}$
24690	x 구하기	(9+sin(x)^2)/(cos(x)^2)=10sec(x)^2-1	$\frac{9 + \sin^{2} (x)}{\cos^{2} (x)} = 10 \sec^{2} (x) - 1$
24691	@VAR 구하기	c^2=85	$c^{2} = 85$
24692	x 구하기	cos(x)^2+sin(x)^2=(x/r)^2+(y/r)^2	$\cos^{2} (x) + \sin^{2} (x) = {(\frac{x}{r})}^{2} + {(\frac{y}{r})}^{2}$
24693	x 구하기	2\|x+1/3\|<9	$2 \| x + \frac{1}{3} \| < 9$
24694	x 구하기	2x^2+17x+21=0	$2 x^{2} + 17 x + 21 = 0$
24695	x 구하기	2x^3+x^2-6x<0	$2 x^{3} + x^{2} - 6 x < 0$
24696	x 구하기	2y^2+5y+3=0	$2 y^{2} + 5 y + 3 = 0$
24697	x 구하기	2+(4x-4)^(1/2)=6	$2 + {(4 x - 4)}^{\frac{1}{2}} = 6$
24698	x 구하기	20x+14=19x	$20 x + 14 = 19 x$
24699	x 구하기	23+\|x\|>19	$23 + \| x \| > 19$
24700	x 구하기	25m-0.2(25m)=620	$25 m - 0.2 (25 m) = 620$