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Beliebte Aufgaben

Rang	Thema	Aufgabe	Formatierte Aufgabe
14401	? 구하기	7tan(x)sin(x)-4tan(x)=0	$7 \tan (x) \sin (x) - 4 \tan (x) = 0$
14402	? 구하기	7tan(x)sin(x)-6tan(x)=0	$7 \tan (x) \sin (x) - 6 \tan (x) = 0$
14403	? 구하기	8sin(x)-4 Quadratwurzel von 3=0	$8 \sin (x) - 4 \sqrt{3} = 0$
14404	? 구하기	8sin(x)-4csc(x)=0	$8 \sin (x) - 4 \csc (x) = 0$
14405	? 구하기	8sin(x)^2tan(x)-8sin(x)^2=0	$8 \sin^{2} (x) \tan (x) - 8 \sin^{2} (x) = 0$
14406	? 구하기	8sin(x)+1=6sin(x)	$8 \sin (x) + 1 = 6 \sin (x)$
14407	? 구하기	9sec(x)^2-5tan(x)^2=5+4sec(x)^2	$9 \sec^{2} (x) - 5 \tan^{2} (x) = 5 + 4 \sec^{2} (x)$
14408	? 구하기	9sec(x)^2tan(x)=12tan(x)	$9 \sec^{2} (x) \tan (x) = 12 \tan (x)$
14409	? 구하기	6sin(x)+5=0	$6 \sin (x) + 5 = 0$
14410	? 구하기	6cos(x)=6cos(2x)	$6 \cos (x) = 6 \cos (2 x)$
14411	? 구하기	6sin(x)+2=0	$6 \sin (x) + 2 = 0$
14412	? 구하기	6tan(x)+7=0	$6 \tan (x) + 7 = 0$
14413	? 구하기	7sin(x)^2+15sin(x)+8=0	$7 \sin^{2} (x) + 15 \sin (x) + 8 = 0$
14414	? 구하기	7tan(x)+sec(x)^2=9	$7 \tan (x) + \sec^{2} (x) = 9$
14415	? 구하기	7sin(x)-5=2sin(x)	$7 \sin (x) - 5 = 2 \sin (x)$
14416	? 구하기	7(1-cos(x))=sin(x)^2	$7 (1 - \cos (x)) = \sin^{2} (x)$
14417	? 구하기	2xcos(x)+x=0	$2 x \cos (x) + x = 0$
14418	? 구하기	150=1/2x*400^2	$150 = \frac{1}{2} x \cdot 400^{2}$
14419	? 구하기	16cos(x)^2=12	$16 \cos^{2} (x) = 12$
14420	? 구하기	11(1-cos(x))=sin(x)^2	$11 (1 - \cos (x)) = \sin^{2} (x)$
14421	? 구하기	12sin(x)^2-6sin(x)=4	$12 \sin^{2} (x) - 6 \sin (x) = 4$
14422	? 구하기	16sin(x)^2-4=0	$16 \sin^{2} (x) - 4 = 0$
14423	? 구하기	tan(x)^2=tan(x)	$\tan^{2} (x) = \tan (x)$
14424	? 구하기	Quadratwurzel von 3csc(2x)-2=0	$\sqrt{3} \csc (2 x) - 2 = 0$
14425	? 구하기	Quadratwurzel von 2sin(2x)=2sin(x)	$\sqrt{2} \sin (2 x) = 2 \sin (x)$
14426	? 구하기	Quadratwurzel von 3sin(x)+cos(x)=1	$\sqrt{3} \sin (x) + \cos (x) = 1$
14427	? 구하기	Quadratwurzel von 3tan(3x)+1=0	$\sqrt{3} \tan (3 x) + 1 = 0$
14428	? 구하기	Quadratwurzel von 3tan(x)+1=0	$\sqrt{3} \tan (x) + 1 = 0$
14429	? 구하기	Quadratwurzel von 3tan(3x)-1=0	$\sqrt{3} \tan (3 x) - 1 = 0$
14430	? 구하기	x^2=4sin(2*x)	$x^{2} = 4 \sin (2 \cdot x)$
14431	? 구하기	1-tan(x)^2=sec(x)^2	$1 - \tan^{2} (x) = \sec^{2} (x)$
14432	? 구하기	2cos(x)^2-5cos(x)-3=0	$2 \cos^{2} (x) - 5 \cos (x) - 3 = 0$
14433	? 구하기	2cos(x)^2-3cos(x)=2	$2 \cos^{2} (x) - 3 \cos (x) = 2$
14434	? 구하기	2cos(x-1)^2=0	$2 \cos^{2} (x - 1) = 0$
14435	? 구하기	2cos(x)^3=cos(x)	$2 \cos^{3} (x) = \cos (x)$
14436	? 구하기	2cos(x)^2- Quadratwurzel von 2cos(x)=0	$2 \cos^{2} (x) - \sqrt{2} \cos (x) = 0$
14437	? 구하기	2cos(x)^2+ Quadratwurzel von 2cos(x)=0	$2 \cos^{2} (x) + \sqrt{2} \cos (x) = 0$
14438	? 구하기	2sin(x)^2+5sin(x)+3=0	$2 \sin^{2} (x) + 5 \sin (x) + 3 = 0$
14439	? 구하기	2sin(x)^2+7sin(x)=4	$2 \sin^{2} (x) + 7 \sin (x) = 4$
14440	? 구하기	2sin(x)^2-sin(x)+8=0	$2 \sin^{2} (x) - \sin (x) + 8 = 0$
14441	? 구하기	2sin(x)^2-5sin(x)+3=0	$2 \sin^{2} (x) - 5 \sin (x) + 3 = 0$
14442	? 구하기	2+sec(x)=0	$2 + \sec (x) = 0$
14443	? 구하기	2cos(x)+1=-1	$2 \cos (x) + 1 = - 1$
14444	? 구하기	2cos(x)+2 Quadratwurzel von 3 = Quadratwurzel von 3	$2 \cos (x) + 2 \sqrt{3} = \sqrt{3}$
14445	? 구하기	2cos(x- Quadratwurzel von 3)=0	$2 \cos (x - \sqrt{3}) = 0$
14446	? 구하기	2 Quadratwurzel von 2cos(x)+4=6	$2 \sqrt{2} \cos (x) + 4 = 6$
14447	? 구하기	(sin(x))/(cos(x))=- Quadratwurzel von 2sin(x)	$\frac{\sin (x)}{\cos (x)} = - \sqrt{2} \sin (x)$
14448	? 구하기	(sin(3x))/(sin(x))-(cos(3x))/(cos(x))=2	$\frac{\sin (3 x)}{\sin (x)} - \frac{\cos (3 x)}{\cos (x)} = 2$
14449	? 구하기	cos(x)^2=3(1-sin(x))	$\cos^{2} (x) = 3 (1 - \sin (x))$
14450	? 구하기	x=arctan( Quadratwurzel von 3)	$x = \arctan (\sqrt{3})$
14451	? 구하기	csc(x)^2-2cot(x)=0	$\csc^{2} (x) - 2 \cot (x) = 0$
14452	? 구하기	csc(x)^2+2csc(x)=0	$\csc^{2} (x) + 2 \csc (x) = 0$
14453	? 구하기	csc(x)^2=8cot(x)+10	$\csc^{2} (x) = 8 \cot (x) + 10$
14454	? 구하기	csc(x)^2+3csc(x)+2=0	$\csc^{2} (x) + 3 \csc (x) + 2 = 0$
14455	? 구하기	cot(x)^2-4csc(x)=-5	$\cot^{2} (x) - 4 \csc (x) = - 5$
14456	? 구하기	cot(x)^2=-5/2*csc(x)-2	$\cot^{2} (x) = - \frac{5}{2} \cdot \csc (x) - 2$
14457	Ermittele den Kotangens bei gegebenem Punkt	(-1/2,( Quadratwurzel von 3)/2)	$\cot^{2} (x) - \cos^{2} (x) = \cot^{2} (x) \cos^{2} (x)$
14458	? 구하기	cot(x)^2+4csc(x)=-5	$\cot^{2} (x) + 4 \csc (x) = - 5$
14459	? 구하기	cot(x)^2-15cot(x)=16	$\cot^{2} (x) - 15 \cot (x) = 16$
14460	? 구하기	sin(x)^2=8sin(x)+9	$\sin^{2} (x) = 8 \sin (x) + 9$
14461	? 구하기	sin(x)^2=cos(x)^2-1	$\sin^{2} (x) = \cos^{2} (x) - 1$
14462	? 구하기	sin(x)^2=2cos(x)+2	$\sin^{2} (x) = 2 \cos (x) + 2$
14463	? 구하기	sin(x)^2(1+cot(x)^2)-1=0	$\sin^{2} (x) (1 + \cot^{2} (x)) - 1 = 0$
14464	? 구하기	sin(x)^2+2cos(x)=-2	$\sin^{2} (x) + 2 \cos (x) = - 2$
14465	Solve for θ in Radians	theta=arcsin(cos(-pi/6))	$\tan^{2} (x) = \frac{3}{2} \cdot \sec (x)$
14466	? 구하기	sin(x)^2-4sin(x)-5=0	$\sin^{2} (x) - 4 \sin (x) - 5 = 0$
14467	? 구하기	sin(x)^2cos(x)=cos(x)	$\sin^{2} (x) \cos (x) = \cos (x)$
14468	Vereinfache mithilfe der Halbwinkelformel	cos(105 Grad )	$\tan^{2} (x) = - \frac{\sqrt{3}}{6} \cdot \sec (x)$
14469	? 구하기	tan(x)^2-4sec(x)=4	$\tan^{2} (x) - 4 \sec (x) = 4$
14470	? 구하기	tan(x)^2-6sec(x)=6	$\tan^{2} (x) - 6 \sec (x) = 6$
14471	? 구하기	tan(x)^2-tan(x)=0	$\tan^{2} (x) - \tan (x) = 0$
14472	? 구하기	Quadratwurzel von 2sin(2x)+1=0	$\sqrt{2} \sin (2 x) + 1 = 0$
14473	? 구하기	Quadratwurzel von 2cos(x)^2-cos(x)=0	$\sqrt{2} \cos^{2} (x) - \cos (x) = 0$
14474	? 구하기	Quadratwurzel von 2cos(2x)=1	$\sqrt{2} \cos (2 x) = 1$
14475	? 구하기	Quadratwurzel von 10/9+1=sec(x)	$\sqrt{\frac{10}{9} + 1} = \sec (x)$
14476	v 구하기	sin(v)^2	$\sin^{2} (v)$
14477	Ermittle Amplitude, Periode und Phasenverschiebung	y=3cos(2)theta	$y = 3 \cos (2) θ$
14478	Ermittle Amplitude, Periode und Phasenverschiebung	y=tan(2theta)	$y = \tan (2 θ)$
14479	? 구하기	( Quadratwurzel von 3)tan(x)=2sin(x)	$(\sqrt{3}) \tan (x) = 2 \sin (x)$
14480	Bestimme den Referenzwinkel	108 Grad	$108 °$
14481	Bestimme den Referenzwinkel	140 Grad	$140 °$
14482	Ermittle den Wert mithilfe des Einheitskreises	cos(210 Grad )	$\cos (210 °)$
14483	Ermittle den exakten Wert	sin(arccos(( Quadratwurzel von 2)/2))	$\sin (\arccos (\frac{\sqrt{2}}{2}))$
14484	Stelle graphisch dar	2x+3y=-17	$2 x + 3 y = - 17$
14485	Wandle in Polarkoordinaten um	(-9,-9)	$(- 9, - 9)$
14486	Vereinfache	3sin(x)^3csc(x)+cos(x)^2+2cos(-x)cos(x)	$3 \sin^{3} (x) \csc (x) + \cos^{2} (x) + 2 \cos (- x) \cos (x)$
14487	x 구하기	5*2^(3x)=21	$5 \cdot 2^{3 x} = 21$
14488	? 구하기	theta=270	$θ = 270$
14489	Vereinfache	sin(x+(3pi)/2)	$\sin (x + \frac{3 π}{2})$
14490	x 구하기	tan(56)=24/x	$\tan (56) = \frac{24}{x}$
14491	? 구하기	sec(theta)=- Quadratwurzel von 2	$\sec (θ) = - \sqrt{2}$
14492	Ermittle den exakten Wert	arccos(cos((5pi)/8))	$\arccos (\cos (\frac{5 π}{8}))$
14493	Ermittle den exakten Wert	arccos(4/5)	$\arccos (\frac{4}{5})$
14494	Rechne von Radiant in Grad um	(29pi)/15	$\frac{29 π}{15}$
14495	Rechne von Radiant in Grad um	(23pi)/20	$\frac{23 π}{20}$
14496	Ermittle Amplitude, Periode und Phasenverschiebung	y=4cos(1/3)x	$y = 4 \cos (\frac{1}{3}) x$
14497	Stelle graphisch dar	cot(x)	$\cot (x)$
14498	Stelle graphisch dar	-2pi<=x<=2pi	$- 2 π \leq x \leq 2 π$
14499	Wandle in die trigonometrische Form um	(1+i)^6	${(1 + i)}^{6}$
14500	Stelle graphisch dar	y=cot(2x+pi/4)	$y = \cot (2 x + \frac{π}{4})$