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Rang	Thema	Aufgabe	Formatierte Aufgabe
66301	x 구하기	\|x+3\|=9	$\| x + 3 \| = 9$
66302	Finde die quadratische Gleichung	-7 , 11	$- 7$ , $11$
66303	x 구하기	\|x+2\|=4	$\| x + 2 \| = 4$
66304	Finde die quadratische Gleichung	7 , 4	$7$ , $4$
66305	x 구하기	\|x+2\|=10	$\| x + 2 \| = 10$
66306	x 구하기	\|x-6\|=9	$\| x - 6 \| = 9$
66307	x 구하기	\|x-6\|=5	$\| x - 6 \| = 5$
66308	Finde die quadratische Gleichung	9 , -6	$9$ , $- 6$
66309	x 구하기	10^x=10000	$10^{x} = 10000$
66310	Finde die quadratische Gleichung	9i , -9i	$9 i$ , $- 9 i$
66311	x 구하기	10^(6x)=93	$10^{6 x} = 93$
66312	x 구하기	1/(x+2)+4/(x^2-4)=1	$\frac{1}{x + 2} + \frac{4}{x^{2} - 4} = 1$
66313	x 구하기	1/(x+4)+8/(x^2-16)=1	$\frac{1}{x + 4} + \frac{8}{x^{2} - 16} = 1$
66314	x 구하기	1/3x-5=12	$\frac{1}{3} x - 5 = 12$
66315	x 구하기	1/4=2^(5x)	$\frac{1}{4} = 2^{5 x}$
66316	x 구하기	1/4=8^(3x+5)	$\frac{1}{4} = 8^{3 x + 5}$
66317	x 구하기	1/3x+3/4=5/12	$\frac{1}{3} x + \frac{3}{4} = \frac{5}{12}$
66318	x 구하기	1/3x+3/5=4/15	$\frac{1}{3} x + \frac{3}{5} = \frac{4}{15}$
66319	x 구하기	1/6x=1/2	$\frac{1}{6} x = \frac{1}{2}$
66320	x 구하기	2^(3x-7)=4	$2^{3 x - 7} = 4$
66321	Ermittle den Wertebereich	(x+1)^2+(y-3)^2=36	${(x + 1)}^{2} + {(y - 3)}^{2} = 36$
66322	x 구하기	2^(x^2-3)=64	$2^{x^{2} - 3} = 64$
66323	x 구하기	2/(x-5)=20/(x^2-25)	$\frac{2}{x - 5} = \frac{20}{x^{2} - 25}$
66324	Ermittle den Wertebereich	(x+2)^2+(y-1)^2=25	${(x + 2)}^{2} + {(y - 1)}^{2} = 25$
66325	x 구하기	2/(x+2)+1/5=6/(x+5)	$\frac{2}{x + 2} + \frac{1}{5} = \frac{6}{x + 5}$
66326	x 구하기	2^(2x-1)=32	$2^{2 x - 1} = 32$
66327	Ermittle den Wertebereich	(x+2)^2+(y-5)^2=16	${(x + 2)}^{2} + {(y - 5)}^{2} = 16$
66328	x 구하기	2^x=30	$2^{x} = 30$
66329	Ermittle den Wertebereich	(x+2)^2+(y-6)^2=16	${(x + 2)}^{2} + {(y - 6)}^{2} = 16$
66330	x 구하기	25^(10x+8)=(1/125)^(4-2x)	$25^{10 x + 8} = {(\frac{1}{125})}^{4 - 2 x}$
66331	x 구하기	256^x=128	$256^{x} = 128$
66332	x 구하기	256^(4x)=64^(x+2)	$256^{4 x} = 64^{x + 2}$
66333	Ermittle den Wertebereich	(x+4)^2+(y-2)^2=25	${(x + 4)}^{2} + {(y - 2)}^{2} = 25$
66334	x 구하기	27^(3x)=9^(x+1)	$27^{3 x} = 9^{x + 1}$
66335	x 구하기	(2x)/5=x/3+5	$\frac{2 x}{5} = \frac{x}{3} + 5$
66336	Ermittle den Wertebereich	(x+4)^2+(y-5)^2=36	${(x + 4)}^{2} + {(y - 5)}^{2} = 36$
66337	x 구하기	5x-x+12+2x-7=10	$5 x - x + 12 + 2 x - 7 = 10$
66338	x 구하기	(2x)/3-x/4=5	$\frac{2 x}{3} - \frac{x}{4} = 5$
66339	x 구하기	2/5*(x-2)=4x	$\frac{2}{5} \cdot (x - 2) = 4 x$
66340	Ermittle den Wertebereich	(x+5)^2+(y-1)^2=9	${(x + 5)}^{2} + {(y - 1)}^{2} = 9$
66341	x 구하기	2/5*(10x-3)-x=9/5	$\frac{2}{5} \cdot (10 x - 3) - x = \frac{9}{5}$
66342	Ermittle den Wertebereich	(x+5)^2+(y-4)^2=25	${(x + 5)}^{2} + {(y - 4)}^{2} = 25$
66343	x 구하기	2/3x-5=7	$\frac{2}{3} x - 5 = 7$
66344	Ermittle den Wertebereich	(x+5)^2+(y-4)^2=36	${(x + 5)}^{2} + {(y - 4)}^{2} = 36$
66345	x 구하기	16^x=1/( Quadratwurzel von 2)	$16^{x} = \frac{1}{\sqrt{2}}$
66346	x 구하기	12^x=4^(x+1)	$12^{x} = 4^{x + 1}$
66347	b 구하기	5^2+b^2=9^2	$5^{2} + b^{2} = 9^{2}$
66348	Ermittle den Wertebereich	(x+6)^2+(y-1)^2=16	${(x + 6)}^{2} + {(y - 1)}^{2} = 16$
66349	b 구하기	b/9-1/2=5/18	$\frac{b}{9} - \frac{1}{2} = \frac{5}{18}$
66350	Löse durch Faktorisieren	x^6+6x^3+5=0	$x^{6} + 6 x^{3} + 5 = 0$
66351	Ermittle den Wertebereich	(x+6)^2+(y-3)^2=16	${(x + 6)}^{2} + {(y - 3)}^{2} = 16$
66352	a 구하기	a/11=(a-6)/5	$\frac{a}{11} = \frac{a - 6}{5}$
66353	Ermittle den Wertebereich	(x+6)^2+(y-4)^2=16	${(x + 6)}^{2} + {(y - 4)}^{2} = 16$
66354	a 구하기	a/3-9/2=2a+1	$\frac{a}{3} - \frac{9}{2} = 2 a + 1$
66355	c 구하기	-14=-5+3c	$- 14 = - 5 + 3 c$
66356	c 구하기	7c+12=-4c+78	$7 c + 12 = - 4 c + 78$
66357	Ermittle den Wertebereich	(x-4)^2+(y-3)^2=9	${(x - 4)}^{2} + {(y - 3)}^{2} = 9$
66358	b 구하기	a=9/2*(b+35)	$a = \frac{9}{2} \cdot (b + 35)$
66359	d 구하기	72+4-14d=36	$72 + 4 - 14 d = 36$
66360	Ermittle den Wertebereich	(x-5)^2+(y-4)^2=9	${(x - 5)}^{2} + {(y - 4)}^{2} = 9$
66361	D 구하기	A=2BC+2BD+2CD	$A = 2 B C + 2 B D + 2 C D$
66362	g 구하기	A=((f+g)/2)h	$A = (\frac{f + g}{2}) h$
66363	g 구하기	w=gh-3gt^2	$w = g h - 3 g t^{2}$
66364	g 구하기	1/2*(3g-2)=g/2	$\frac{1}{2} \cdot (3 g - 2) = \frac{g}{2}$
66365	f 구하기	35=5/9*(f-32)	$35 = \frac{5}{9} \cdot (f - 32)$
66366	f 구하기	7f+g=5	$7 f + g = 5$
66367	p 구하기	2=6p-8-5p	$2 = 6 p - 8 - 5 p$
66368	p 구하기	-2/5p+2=1/5p+11	$- \frac{2}{5} p + 2 = \frac{1}{5} p + 11$
66369	n 구하기	-5+n/3=0	$- 5 + \frac{n}{3} = 0$
66370	n 구하기	3n+46=1+8n	$3 n + 46 = 1 + 8 n$
66371	Ermittle den Wertebereich	H=-16t^2+368t	$H = - 16 t^{2} + 368 t$
66372	n 구하기	-36=6(2-8n)	$- 36 = 6 (2 - 8 n)$
66373	Ermittle den Wertebereich	h=50t-16t^2	$h = 50 t - 16 t^{2}$
66374	n 구하기	-4(8+5n)=8	$- 4 (8 + 5 n) = 8$
66375	Ermittle den Wertebereich	x^2+(y-3)^2=36	$x^{2} + {(y - 3)}^{2} = 36$
66376	n 구하기	-6n-20=-2n+4(1-3n)	$- 6 n - 20 = - 2 n + 4 (1 - 3 n)$
66377	Ermittle den Wertebereich	x^2+(y-5)^2=30	$x^{2} + {(y - 5)}^{2} = 30$
66378	p 구하기	Logarithmus von 4p-2 = Logarithmus von -5p+5	$\log (4 p - 2) = \log (- 5 p + 5)$
66379	r 구하기	2700=2300(1+r)^5	$2700 = 2300 {(1 + r)}^{5}$
66380	Ermittle den Wertebereich	x^2+y^2-13x+11y-55/2=0	$x^{2} + y^{2} - 13 x + 11 y - \frac{55}{2} = 0$
66381	r 구하기	2r-(5-r)=13+2r	$2 r - (5 - r) = 13 + 2 r$
66382	r 구하기	r/5-6=-1	$\frac{r}{5} - 6 = - 1$
66383	r 구하기	r^(4/7)=16	$r^{\frac{4}{7}} = 16$
66384	q 구하기	50q-43=52q-81	$50 q - 43 = 52 q - 81$
66385	q 구하기	2/r=3/p+1/q	$\frac{2}{r} = \frac{3}{p} + \frac{1}{q}$
66386	Ermittle den Wertebereich	y=2/3sin(x)	$y = \frac{2}{3} \sin (x)$
66387	r 구하기	\|r-8\|=5	$\| r - 8 \| = 5$
66388	Dividiere	(a^(2n)-a^n-6)÷(a^n+8)	$(a^{2 n} - a^{n} - 6) \div (a^{n} + 8)$
66389	Ermittle den Wertebereich	y=4/5sin(x)	$y = \frac{4}{5} \sin (x)$
66390	L 구하기	16LW=V	$16 L W = V$
66391	Ermittle den Wertebereich	y = cube root of x+8	$y = \sqrt[3]{x} + 8$
66392	k 구하기	natürlicher Logarithmus von 1/2=23k	$\ln (\frac{1}{2}) = 23 k$
66393	Ermittle den Wertebereich	y = cube root of -x-3	$y = \sqrt[3]{- x - 3}$
66394	m 구하기	-2(5+6m)+16=-90	$- 2 (5 + 6 m) + 16 = - 90$
66395	Ermittle den Wertebereich	y=-13 Quadratwurzel von x-2.4+1	$y = - 13 \sqrt{x - 2.4} + 1$
66396	m 구하기	m/16-9=-8	$\frac{m}{16} - 9 = - 8$
66397	Ermittle den Wertebereich	y=-2+5sin(pi/12(x-2))	$y = - 2 + 5 \sin (\frac{π}{12} (x - 2))$
66398	Bestimme den Definitionsbereich	f(x)=3/(x+2)- Quadratwurzel von x-3	$f (x) = \frac{3}{x + 2} - \sqrt{x - 3}$
66399	m 구하기	c=amt	$c =$ amt
66400	m 구하기	km+5x=6y	$km + 5 x = 6 y$