Calculus Examples

$lim_{x \to - \infty} e^{x} \sin (x)$

Step 1

Since $e^{x} \cdot - 1 \leq e^{x} \sin (x) \leq e^{x} \cdot 1$ and $lim_{x \to - \infty} e^{x} \cdot - 1 = lim_{x \to - \infty} e^{x} \cdot 1 = 0$ , apply the squeeze theorem.

$0$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$