Calculus Examples

$\log_{b} (\frac{1}{N}) = - \log_{b} (N)$

Simplify $- \log_{b} (N)$ by moving $- 1$ inside the logarithm.

$\log_{b} (\frac{1}{N}) = \log_{b} (N^{- 1})$

For the equation to be equal, the argument of the logarithms on both sides of the equation must be equal.

$\frac{1}{N} = N^{- 1}$

Solve for $b$ .

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Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{N} = \frac{1}{N}$

Find the LCD of the terms in the equation.

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Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

N,N

Since $N, N$ contain both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part $1, 1$ then find LCM for the variable part $N^{1}, N^{1}$ .

The LCM is the smallest positive number that all of the numbers divide into evenly.

1. List the prime factors of each number.

2. Multiply each factor the greatest number of times it occurs in either number.

The number $1$ is not a prime number because it only has one positive factor, which is itself.

Not prime

The LCM of $1, 1$ is the result of multiplying all prime factors the greatest number of times they occur in either number.

$1$

The factor for $N^{1}$ is $N$ itself.

$N^{1} = N$

$N$ occurs $1$ time.

The LCM of $N^{1}, N^{1}$ is the result of multiplying all prime factors the greatest number of times they occur in either term.

$N$

Multiply each term in $\frac{1}{N} = \frac{1}{N}$ by $N$ to eliminate the fractions.

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Multiply each term in $\frac{1}{N} = \frac{1}{N}$ by $N$ .

$\frac{1}{N} N = \frac{1}{N} N$

Simplify the left side.

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Cancel the common factor of $N$ .

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Cancel the common factor.

$\frac{1}{N} N = \frac{1}{N} N$

Rewrite the expression.

$1 = \frac{1}{N} N$

Simplify the right side.

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Cancel the common factor of $N$ .

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Cancel the common factor.

$1 = \frac{1}{N} N$

Rewrite the expression.

$1 = 1$

Since $1 = 1$ , the equation will always be true.

Always true

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$