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Find the Perfect Square Trinomial

$x^{2} - 12 x$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $x$ by $2$ and square the result.

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Step 1.1

Divide $12$ by $2$ .

${(- 1 \cdot 6)}^{2}$

Step 1.2

Multiply $- 1$ by $6$ .

${(- 6)}^{2}$

Step 1.3

Raise $- 6$ to the power of $2$ .

$36$

Step 2

Add $36$ to get the perfect square trinomial.

$x^{2} - 12 x + 36$

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$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$