Trigonometry Examples

$\frac{\sin (x) + 1}{\cos (x)} = \frac{\cos (x)}{1 - \sin (x)}$

Step 1

Start on the right side.

$\frac{\cos (x)}{1 - \sin (x)}$

Step 2

Multiply $\frac{\cos (x)}{1 - \sin (x)}$ by $\frac{1 + \sin (x)}{1 + \sin (x)}$ .

$\frac{\cos (x)}{1 - \sin (x)} \cdot \frac{1 + \sin (x)}{1 + \sin (x)}$

Step 3

Combine.

$\frac{\cos (x) (1 + \sin (x))}{(1 - \sin (x)) (1 + \sin (x))}$

Step 4

Simplify numerator.

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Apply the distributive property.

$\frac{\cos (x) \cdot 1 + \cos (x) \sin (x)}{(1 - \sin (x)) (1 + \sin (x))}$

Multiply $\cos (x)$ by $1$ .

$\frac{\cos (x) + \cos (x) \sin (x)}{(1 - \sin (x)) (1 + \sin (x))}$

Step 5

Simplify denominator.

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Expand $(1 - \sin (x)) (1 + \sin (x))$ using the FOIL Method.

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Apply the distributive property.

$\frac{\cos (x) + \cos (x) \sin (x)}{1 (1 + \sin (x)) - \sin (x) (1 + \sin (x))}$

Apply the distributive property.

$\frac{\cos (x) + \cos (x) \sin (x)}{1 \cdot 1 + 1 \sin (x) - \sin (x) (1 + \sin (x))}$

Apply the distributive property.

$\frac{\cos (x) + \cos (x) \sin (x)}{1 \cdot 1 + 1 \sin (x) - \sin (x) \cdot 1 - \sin (x) \sin (x)}$

Simplify and combine like terms.

$\frac{\cos (x) + \cos (x) \sin (x)}{1 - \sin^{2} (x)}$

Step 6

Apply pythagorean identity.

$\frac{\cos (x) + \cos (x) \sin (x)}{\cos^{2} (x)}$

Step 7

Simplify.

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Factor $\cos (x)$ out of $\cos (x) + \cos (x) \sin (x)$ .

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Multiply by $1$ .

$\frac{\cos (x) \cdot 1 + \cos (x) \sin (x)}{{\cos (x)}^{2}}$

Factor $\cos (x)$ out of $\cos (x) \sin (x)$ .

$\frac{\cos (x) \cdot 1 + \cos (x) (\sin (x))}{{\cos (x)}^{2}}$

Factor $\cos (x)$ out of $\cos (x) \cdot 1 + \cos (x) (\sin (x))$ .

$\frac{\cos (x) (1 + \sin (x))}{{\cos (x)}^{2}}$

Cancel the common factors.

$\frac{1 + \sin (x)}{\cos (x)}$

Step 8

Rewrite $\frac{1 + \sin (x)}{\cos (x)}$ as $\frac{\sin (x) + 1}{\cos (x)}$ .

$\frac{\sin (x) + 1}{\cos (x)}$

Step 9

Because the two sides have been shown to be equivalent, the equation is an identity.

$\frac{\sin (x) + 1}{\cos (x)} = \frac{\cos (x)}{1 - \sin (x)}$ is an identity