Precalculus Examples

$\log (1.46 \cdot 10^{35})$

Rewrite $\log (1.46 \cdot 10^{35})$ as $\log (1.46) + \log (10^{35})$ .

$\log (1.46) + \log (10^{35})$

Expand $\log (10^{35})$ by moving $35$ outside the logarithm.

$\log (1.46) + 35 \log (10)$

Log base $10$ of $1.46$ is approximately $0.16435285$ .

$0.16435285 + 35 \log (10)$

Logarithm base $10$ of $10$ is $1$ .

$0.16435285 + 35 \cdot 1$

Multiply $35$ by $1$ .

$0.16435285 + 35$

Add $0.16435285$ and $35$ .

$35.16435285$