Precalculus Examples

$\log (58344 - 4800) = 2 (t) \log (1.025)$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 10$ , $x = 58344 - 4800$ , and $y = 2 (t) \log (1.025)$ .

$b = 10$

$x = 58344 - 4800$

$y = 2 (t) \log (1.025)$

Step 2

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

$10^{2 (t) \log (1.025)} = 58344 - 4800$