Calculus Examples

$c = 14 (w + 2 l) + 5 w$

Step 1

Rewrite the equation as $14 (w + 2 l) + 5 w = c$ .

$14 (w + 2 l) + 5 w = c$

Step 2

Simplify $14 (w + 2 l) + 5 w$ .

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Step 2.1

Simplify each term.

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Step 2.1.1

Apply the distributive property.

$14 w + 14 (2 l) + 5 w = c$

Step 2.1.2

Multiply $2$ by $14$ .

$14 w + 28 l + 5 w = c$

Step 2.2

Add $14 w$ and $5 w$ .

$28 l + 19 w = c$

Step 3

Subtract $28 l$ from both sides of the equation.

$19 w = c - 28 l$

Step 4

Divide each term in $19 w = c - 28 l$ by $19$ and simplify.

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Step 4.1

Divide each term in $19 w = c - 28 l$ by $19$ .

$\frac{19 w}{19} = \frac{c}{19} + \frac{- 28 l}{19}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Cancel the common factor of $19$ .

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Step 4.2.1.1

Cancel the common factor.

$\frac{19 w}{19} = \frac{c}{19} + \frac{- 28 l}{19}$

Step 4.2.1.2

Divide $w$ by $1$ .

$w = \frac{c}{19} + \frac{- 28 l}{19}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Move the negative in front of the fraction.

$w = \frac{c}{19} - \frac{28 l}{19}$