Calculus Examples

$\frac{5}{2} {(2)}^{2} - 7 \cdot 2 + C = 3$

Step 1

Simplify $\frac{5}{2} \cdot 2^{2} - 7 \cdot 2 + C$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Cancel the common factor of $2$ .

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Step 1.1.1.1

Factor $2$ out of $2^{2}$ .

$\frac{5}{2} \cdot (2 \cdot 2) - 7 \cdot 2 + C = 3$

Step 1.1.1.2

Cancel the common factor.

$\frac{5}{2} \cdot (2 \cdot 2) - 7 \cdot 2 + C = 3$

Step 1.1.1.3

Rewrite the expression.

$5 \cdot 2 - 7 \cdot 2 + C = 3$

Step 1.1.2

Multiply $5$ by $2$ .

$10 - 7 \cdot 2 + C = 3$

Step 1.1.3

Multiply $- 7$ by $2$ .

$10 - 14 + C = 3$

Step 1.2

Subtract $14$ from $10$ .

$- 4 + C = 3$

Step 2

Move all terms not containing $C$ to the right side of the equation.

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Step 2.1

Add $4$ to both sides of the equation.

$C = 3 + 4$

Step 2.2

Add $3$ and $4$ .

$C = 7$