Calculus Examples

$x^{2} + y^{2} - 25 = 0$ $2 x - y = - 5$

Step 1

Solve for $x$ in $2 x - y = - 5$ .

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Step 1.1

Add $y$ to both sides of the equation.

$2 x = - 5 + y$

$x^{2} + y^{2} - 25 = 0$

Step 1.2

Divide each term in $2 x = - 5 + y$ by $2$ and simplify.

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Step 1.2.1

Divide each term in $2 x = - 5 + y$ by $2$ .

$\frac{2 x}{2} = \frac{- 5}{2} + \frac{y}{2}$

$x^{2} + y^{2} - 25 = 0$

Step 1.2.2

Simplify the left side.

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Step 1.2.2.1

Cancel the common factor of $2$ .

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Step 1.2.2.1.1

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 5}{2} + \frac{y}{2}$

$x^{2} + y^{2} - 25 = 0$

Step 1.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{- 5}{2} + \frac{y}{2}$

$x^{2} + y^{2} - 25 = 0$

$x = \frac{- 5}{2} + \frac{y}{2}$

$x^{2} + y^{2} - 25 = 0$

$x = \frac{- 5}{2} + \frac{y}{2}$

$x^{2} + y^{2} - 25 = 0$

Step 1.2.3

Simplify the right side.

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Step 1.2.3.1

Move the negative in front of the fraction.

$x = - \frac{5}{2} + \frac{y}{2}$

$x^{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$x^{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$x^{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$x^{2} + y^{2} - 25 = 0$

Step 2

Replace all occurrences of $x$ with $- \frac{5}{2} + \frac{y}{2}$ in each equation.

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Step 2.1

Replace all occurrences of $x$ in $x^{2} + y^{2} - 25 = 0$ with $- \frac{5}{2} + \frac{y}{2}$ .

${(- \frac{5}{2} + \frac{y}{2})}^{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify ${(- \frac{5}{2} + \frac{y}{2})}^{2} + y^{2} - 25$ .

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Step 2.2.1.1

Simplify each term.

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Step 2.2.1.1.1

Rewrite ${(- \frac{5}{2} + \frac{y}{2})}^{2}$ as $(- \frac{5}{2} + \frac{y}{2}) (- \frac{5}{2} + \frac{y}{2})$ .

$(- \frac{5}{2} + \frac{y}{2}) (- \frac{5}{2} + \frac{y}{2}) + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.2

Expand $(- \frac{5}{2} + \frac{y}{2}) (- \frac{5}{2} + \frac{y}{2})$ using the FOIL Method.

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Step 2.2.1.1.2.1

Apply the distributive property.

$- \frac{5}{2} \cdot (- \frac{5}{2} + \frac{y}{2}) + \frac{y}{2} \cdot (- \frac{5}{2} + \frac{y}{2}) + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.2.2

Apply the distributive property.

$- \frac{5}{2} \cdot (- \frac{5}{2}) - \frac{5}{2} \cdot \frac{y}{2} + \frac{y}{2} \cdot (- \frac{5}{2} + \frac{y}{2}) + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.2.3

Apply the distributive property.

$- \frac{5}{2} \cdot (- \frac{5}{2}) - \frac{5}{2} \cdot \frac{y}{2} + \frac{y}{2} \cdot (- \frac{5}{2}) + \frac{y}{2} \cdot \frac{y}{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$- \frac{5}{2} \cdot (- \frac{5}{2}) - \frac{5}{2} \cdot \frac{y}{2} + \frac{y}{2} \cdot (- \frac{5}{2}) + \frac{y}{2} \cdot \frac{y}{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3

Simplify and combine like terms.

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Step 2.2.1.1.3.1

Simplify each term.

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Step 2.2.1.1.3.1.1

Multiply $- \frac{5}{2} (- \frac{5}{2})$ .

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Step 2.2.1.1.3.1.1.1

Multiply $- 1$ by $- 1$ .

$1 (\frac{5}{2}) \cdot \frac{5}{2} - \frac{5}{2} \cdot \frac{y}{2} + \frac{y}{2} \cdot (- \frac{5}{2}) + \frac{y}{2} \cdot \frac{y}{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.1.1.2

Multiply $\frac{5}{2}$ by $1$ .

$\frac{5}{2} \cdot \frac{5}{2} - \frac{5}{2} \cdot \frac{y}{2} + \frac{y}{2} \cdot (- \frac{5}{2}) + \frac{y}{2} \cdot \frac{y}{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.1.1.3

Multiply $\frac{5}{2}$ by $\frac{5}{2}$ .

$\frac{5 \cdot 5}{2 \cdot 2} - \frac{5}{2} \cdot \frac{y}{2} + \frac{y}{2} \cdot (- \frac{5}{2}) + \frac{y}{2} \cdot \frac{y}{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.1.1.4

Multiply $5$ by $5$ .

$\frac{25}{2 \cdot 2} - \frac{5}{2} \cdot \frac{y}{2} + \frac{y}{2} \cdot (- \frac{5}{2}) + \frac{y}{2} \cdot \frac{y}{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.1.1.5

Multiply $2$ by $2$ .

$\frac{25}{4} - \frac{5}{2} \cdot \frac{y}{2} + \frac{y}{2} \cdot (- \frac{5}{2}) + \frac{y}{2} \cdot \frac{y}{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$\frac{25}{4} - \frac{5}{2} \cdot \frac{y}{2} + \frac{y}{2} \cdot (- \frac{5}{2}) + \frac{y}{2} \cdot \frac{y}{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.1.2

Multiply $- \frac{5}{2} \cdot \frac{y}{2}$ .

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Step 2.2.1.1.3.1.2.1

Multiply $\frac{y}{2}$ by $\frac{5}{2}$ .

$\frac{25}{4} - \frac{y \cdot 5}{2 \cdot 2} + \frac{y}{2} \cdot (- \frac{5}{2}) + \frac{y}{2} \cdot \frac{y}{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.1.2.2

Multiply $2$ by $2$ .

$\frac{25}{4} - \frac{y \cdot 5}{4} + \frac{y}{2} \cdot (- \frac{5}{2}) + \frac{y}{2} \cdot \frac{y}{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$\frac{25}{4} - \frac{y \cdot 5}{4} + \frac{y}{2} \cdot (- \frac{5}{2}) + \frac{y}{2} \cdot \frac{y}{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.1.3

Move $5$ to the left of $y$ .

$\frac{25}{4} - \frac{5 \cdot y}{4} + \frac{y}{2} \cdot (- \frac{5}{2}) + \frac{y}{2} \cdot \frac{y}{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.1.4

Multiply $\frac{y}{2} (- \frac{5}{2})$ .

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Step 2.2.1.1.3.1.4.1

Multiply $\frac{y}{2}$ by $\frac{5}{2}$ .

$\frac{25}{4} - \frac{5 y}{4} - \frac{y \cdot 5}{2 \cdot 2} + \frac{y}{2} \cdot \frac{y}{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.1.4.2

Multiply $2$ by $2$ .

$\frac{25}{4} - \frac{5 y}{4} - \frac{y \cdot 5}{4} + \frac{y}{2} \cdot \frac{y}{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$\frac{25}{4} - \frac{5 y}{4} - \frac{y \cdot 5}{4} + \frac{y}{2} \cdot \frac{y}{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.1.5

Move $5$ to the left of $y$ .

$\frac{25}{4} - \frac{5 y}{4} - \frac{5 \cdot y}{4} + \frac{y}{2} \cdot \frac{y}{2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.1.6

Multiply $\frac{y}{2} \cdot \frac{y}{2}$ .

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Step 2.2.1.1.3.1.6.1

Multiply $\frac{y}{2}$ by $\frac{y}{2}$ .

$\frac{25}{4} - \frac{5 y}{4} - \frac{5 y}{4} + \frac{y \cdot y}{2 \cdot 2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.1.6.2

Raise $y$ to the power of $1$ .

$\frac{25}{4} - \frac{5 y}{4} - \frac{5 y}{4} + \frac{y \cdot y}{2 \cdot 2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.1.6.3

Raise $y$ to the power of $1$ .

$\frac{25}{4} - \frac{5 y}{4} - \frac{5 y}{4} + \frac{y \cdot y}{2 \cdot 2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.1.6.4

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{25}{4} - \frac{5 y}{4} - \frac{5 y}{4} + \frac{y^{1 + 1}}{2 \cdot 2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.1.6.5

Add $1$ and $1$ .

$\frac{25}{4} - \frac{5 y}{4} - \frac{5 y}{4} + \frac{y^{2}}{2 \cdot 2} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.1.6.6

Multiply $2$ by $2$ .

$\frac{25}{4} - \frac{5 y}{4} - \frac{5 y}{4} + \frac{y^{2}}{4} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$\frac{25}{4} - \frac{5 y}{4} - \frac{5 y}{4} + \frac{y^{2}}{4} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$\frac{25}{4} - \frac{5 y}{4} - \frac{5 y}{4} + \frac{y^{2}}{4} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.3.2

Subtract $\frac{5 y}{4}$ from $- \frac{5 y}{4}$ .

$\frac{25}{4} - 2 \frac{5 y}{4} + \frac{y^{2}}{4} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$\frac{25}{4} - 2 \frac{5 y}{4} + \frac{y^{2}}{4} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.4

Simplify each term.

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Step 2.2.1.1.4.1

Cancel the common factor of $2$ .

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Step 2.2.1.1.4.1.1

Factor $2$ out of $- 2$ .

$\frac{25}{4} + 2 (- 1) (\frac{5 y}{4}) + \frac{y^{2}}{4} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.4.1.2

Factor $2$ out of $4$ .

$\frac{25}{4} + 2 \cdot (- 1 \frac{5 y}{2 \cdot 2}) + \frac{y^{2}}{4} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.4.1.3

Cancel the common factor.

$\frac{25}{4} + 2 \cdot (- 1 \frac{5 y}{2 \cdot 2}) + \frac{y^{2}}{4} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.4.1.4

Rewrite the expression.

$\frac{25}{4} - 1 \frac{5 y}{2} + \frac{y^{2}}{4} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$\frac{25}{4} - 1 \frac{5 y}{2} + \frac{y^{2}}{4} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.1.4.2

Rewrite $- 1 \frac{5 y}{2}$ as $- \frac{5 y}{2}$ .

$\frac{25}{4} - \frac{5 y}{2} + \frac{y^{2}}{4} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$\frac{25}{4} - \frac{5 y}{2} + \frac{y^{2}}{4} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$\frac{25}{4} - \frac{5 y}{2} + \frac{y^{2}}{4} + y^{2} - 25 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.2

To write $- 25$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$- \frac{5 y}{2} + \frac{y^{2}}{4} + y^{2} + \frac{25}{4} - 25 \cdot \frac{4}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.3

Combine $- 25$ and $\frac{4}{4}$ .

$- \frac{5 y}{2} + \frac{y^{2}}{4} + y^{2} + \frac{25}{4} + \frac{- 25 \cdot 4}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.4

Combine the numerators over the common denominator.

$- \frac{5 y}{2} + \frac{y^{2}}{4} + y^{2} + \frac{25 - 25 \cdot 4}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.5

Simplify the numerator.

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Step 2.2.1.5.1

Multiply $- 25$ by $4$ .

$- \frac{5 y}{2} + \frac{y^{2}}{4} + y^{2} + \frac{25 - 100}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.5.2

Subtract $100$ from $25$ .

$- \frac{5 y}{2} + \frac{y^{2}}{4} + y^{2} + \frac{- 75}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$- \frac{5 y}{2} + \frac{y^{2}}{4} + y^{2} + \frac{- 75}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.6

Move the negative in front of the fraction.

$- \frac{5 y}{2} + \frac{y^{2}}{4} + y^{2} - \frac{75}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.7

To write $y^{2}$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$- \frac{5 y}{2} + \frac{y^{2}}{4} + y^{2} \cdot \frac{4}{4} - \frac{75}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.8

Simplify terms.

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Step 2.2.1.8.1

Combine $y^{2}$ and $\frac{4}{4}$ .

$- \frac{5 y}{2} + \frac{y^{2}}{4} + \frac{y^{2} \cdot 4}{4} - \frac{75}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.8.2

Combine the numerators over the common denominator.

$- \frac{5 y}{2} + \frac{y^{2} + y^{2} \cdot 4}{4} - \frac{75}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.8.3

Combine the numerators over the common denominator.

$\frac{- 5 y}{2} + \frac{y^{2} + y^{2} \cdot 4 - 75}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$\frac{- 5 y}{2} + \frac{y^{2} + y^{2} \cdot 4 - 75}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.9

Move $4$ to the left of $y^{2}$ .

$\frac{- 5 y}{2} + \frac{y^{2} + 4 y^{2} - 75}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.10

Add $y^{2}$ and $4 y^{2}$ .

$\frac{- 5 y}{2} + \frac{5 y^{2} - 75}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.11

Simplify each term.

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Step 2.2.1.11.1

Move the negative in front of the fraction.

$- \frac{5 y}{2} + \frac{5 y^{2} - 75}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.11.2

Factor $5$ out of $5 y^{2} - 75$ .

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Step 2.2.1.11.2.1

Factor $5$ out of $5 y^{2}$ .

$- \frac{5 y}{2} + \frac{5 (y^{2}) - 75}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.11.2.2

Factor $5$ out of $- 75$ .

$- \frac{5 y}{2} + \frac{5 y^{2} + 5 \cdot - 15}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.11.2.3

Factor $5$ out of $5 y^{2} + 5 \cdot - 15$ .

$- \frac{5 y}{2} + \frac{5 (y^{2} - 15)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$- \frac{5 y}{2} + \frac{5 (y^{2} - 15)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$- \frac{5 y}{2} + \frac{5 (y^{2} - 15)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.12

To write $- \frac{5 y}{2}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$- \frac{5 y}{2} \cdot \frac{2}{2} + \frac{5 (y^{2} - 15)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.13

Write each expression with a common denominator of $4$ , by multiplying each by an appropriate factor of $1$ .

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Step 2.2.1.13.1

Multiply $\frac{5 y}{2}$ by $\frac{2}{2}$ .

$- \frac{5 y \cdot 2}{2 \cdot 2} + \frac{5 (y^{2} - 15)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.13.2

Multiply $2$ by $2$ .

$- \frac{5 y \cdot 2}{4} + \frac{5 (y^{2} - 15)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$- \frac{5 y \cdot 2}{4} + \frac{5 (y^{2} - 15)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.14

Combine the numerators over the common denominator.

$\frac{- 5 y \cdot 2 + 5 (y^{2} - 15)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.15

Simplify the numerator.

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Step 2.2.1.15.1

Factor $5$ out of $- 5 y \cdot 2 + 5 (y^{2} - 15)$ .

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Step 2.2.1.15.1.1

Factor $5$ out of $- 5 y \cdot 2$ .

$\frac{5 (- y \cdot 2) + 5 (y^{2} - 15)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.15.1.2

Factor $5$ out of $5 (- y \cdot 2) + 5 (y^{2} - 15)$ .

$\frac{5 (- y \cdot 2 + y^{2} - 15)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$\frac{5 (- y \cdot 2 + y^{2} - 15)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.15.2

Multiply $2$ by $- 1$ .

$\frac{5 (- 2 y + y^{2} - 15)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.15.3

Reorder terms.

$\frac{5 (y^{2} - 2 y - 15)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 2.2.1.15.4

Factor $y^{2} - 2 y - 15$ using the AC method.

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Step 2.2.1.15.4.1

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 15$ and whose sum is $- 2$ .

$- 5, 3$

Step 2.2.1.15.4.2

Write the factored form using these integers.

$\frac{5 ((y - 5) (y + 3))}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$\frac{5 (y - 5) (y + 3)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$\frac{5 (y - 5) (y + 3)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$\frac{5 (y - 5) (y + 3)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$\frac{5 (y - 5) (y + 3)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

$\frac{5 (y - 5) (y + 3)}{4} = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 3

Solve for $y$ in $\frac{5 (y - 5) (y + 3)}{4} = 0$ .

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Step 3.1

Set the numerator equal to zero.

$5 (y - 5) (y + 3) = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 3.2

Solve the equation for $y$ .

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Step 3.2.1

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$y - 5 = 0$

$y + 3 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 3.2.2

Set $y - 5$ equal to $0$ and solve for $y$ .

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Step 3.2.2.1

Set $y - 5$ equal to $0$ .

$y - 5 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 3.2.2.2

Add $5$ to both sides of the equation.

$y = 5$

$x = - \frac{5}{2} + \frac{y}{2}$

$y = 5$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 3.2.3

Set $y + 3$ equal to $0$ and solve for $y$ .

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Step 3.2.3.1

Set $y + 3$ equal to $0$ .

$y + 3 = 0$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 3.2.3.2

Subtract $3$ from both sides of the equation.

$y = - 3$

$x = - \frac{5}{2} + \frac{y}{2}$

$y = - 3$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 3.2.4

The final solution is all the values that make $5 (y - 5) (y + 3) = 0$ true.

$y = 5, - 3$

$x = - \frac{5}{2} + \frac{y}{2}$

$y = 5, - 3$

$x = - \frac{5}{2} + \frac{y}{2}$

$y = 5, - 3$

$x = - \frac{5}{2} + \frac{y}{2}$

Step 4

Replace all occurrences of $y$ with $5$ in each equation.

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Step 4.1

Replace all occurrences of $y$ in $x = - \frac{5}{2} + \frac{y}{2}$ with $5$ .

$x = - \frac{5}{2} + \frac{5}{2}$

$y = 5$

Step 4.2

Simplify the right side.

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Step 4.2.1

Simplify $- \frac{5}{2} + \frac{5}{2}$ .

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Step 4.2.1.1

Combine the numerators over the common denominator.

$x = \frac{- 5 + 5}{2}$

$y = 5$

Step 4.2.1.2

Simplify the expression.

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Step 4.2.1.2.1

Add $- 5$ and $5$ .

$x = \frac{0}{2}$

$y = 5$

Step 4.2.1.2.2

Divide $0$ by $2$ .

$x = 0$

$y = 5$

$x = 0$

$y = 5$

$x = 0$

$y = 5$

$x = 0$

$y = 5$

$x = 0$

$y = 5$

Step 5

Replace all occurrences of $y$ with $- 3$ in each equation.

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Step 5.1

Replace all occurrences of $y$ in $x = - \frac{5}{2} + \frac{y}{2}$ with $- 3$ .

$x = - \frac{5}{2} + \frac{- 3}{2}$

$y = - 3$

Step 5.2

Simplify the right side.

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Step 5.2.1

Simplify $- \frac{5}{2} + \frac{- 3}{2}$ .

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Step 5.2.1.1

Combine the numerators over the common denominator.

$x = \frac{- 5 - 3}{2}$

$y = - 3$

Step 5.2.1.2

Simplify the expression.

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Step 5.2.1.2.1

Subtract $3$ from $- 5$ .

$x = \frac{- 8}{2}$

$y = - 3$

Step 5.2.1.2.2

Divide $- 8$ by $2$ .

$x = - 4$

$y = - 3$

$x = - 4$

$y = - 3$

$x = - 4$

$y = - 3$

$x = - 4$

$y = - 3$

$x = - 4$

$y = - 3$

Step 6

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(0, 5)$

$(- 4, - 3)$

Step 7

The result can be shown in multiple forms.

Point Form:

$(0, 5), (- 4, - 3)$

Equation Form:

$x = 0, y = 5$

$x = - 4, y = - 3$

Step 8