Calculus Examples

$f (x) = \frac{e^{- 3 x} \sqrt{2 x - 5}}{{(6 - 5 x)}^{4}}$

Step 1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2 x - 5}$ as ${(2 x - 5)}^{\frac{1}{2}}$ .

$\frac{d}{d x} [\frac{e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}}}{{(6 - 5 x)}^{4}}]$

Step 2

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}}$ and $g (x) = {(6 - 5 x)}^{4}$ .

$\frac{{(6 - 5 x)}^{4} \frac{d}{d x} [e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}}] - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{({(6 - 5 x)}^{4})}^{2}}$

Step 3

Multiply the exponents in ${({(6 - 5 x)}^{4})}^{2}$ .

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Step 3.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{{(6 - 5 x)}^{4} \frac{d}{d x} [e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}}] - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{4 \cdot 2}}$

Step 3.2

Multiply $4$ by $2$ .

$\frac{{(6 - 5 x)}^{4} \frac{d}{d x} [e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}}] - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 4

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = e^{- 3 x}$ and $g (x) = {(2 x - 5)}^{\frac{1}{2}}$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} \frac{d}{d x} [{(2 x - 5)}^{\frac{1}{2}}] + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 5

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{2}}$ and $g (x) = 2 x - 5$ .

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Step 5.1

To apply the Chain Rule, set $u_{1}$ as $2 x - 5$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} (\frac{d}{d u_{1}} [{u_{1}}^{\frac{1}{2}}] \frac{d}{d x} [2 x - 5]) + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 5.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ is $n {u_{1}}^{n - 1}$ where $n = \frac{1}{2}$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} (\frac{1}{2} {u_{1}}^{\frac{1}{2} - 1} \frac{d}{d x} [2 x - 5]) + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 5.3

Replace all occurrences of $u_{1}$ with $2 x - 5$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} (\frac{1}{2} {(2 x - 5)}^{\frac{1}{2} - 1} \frac{d}{d x} [2 x - 5]) + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 6

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} (\frac{1}{2} {(2 x - 5)}^{\frac{1}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d x} [2 x - 5]) + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 7

Combine $- 1$ and $\frac{2}{2}$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} (\frac{1}{2} {(2 x - 5)}^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d x} [2 x - 5]) + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 8

Combine the numerators over the common denominator.

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} (\frac{1}{2} {(2 x - 5)}^{\frac{1 - 1 \cdot 2}{2}} \frac{d}{d x} [2 x - 5]) + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 9

Simplify the numerator.

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Step 9.1

Multiply $- 1$ by $2$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} (\frac{1}{2} {(2 x - 5)}^{\frac{1 - 2}{2}} \frac{d}{d x} [2 x - 5]) + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 9.2

Subtract $2$ from $1$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} (\frac{1}{2} {(2 x - 5)}^{\frac{- 1}{2}} \frac{d}{d x} [2 x - 5]) + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 10

Differentiate.

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Step 10.1

Move the negative in front of the fraction.

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} (\frac{1}{2} {(2 x - 5)}^{- \frac{1}{2}} \frac{d}{d x} [2 x - 5]) + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 10.2

Combine fractions.

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Step 10.2.1

Combine $\frac{1}{2}$ and ${(2 x - 5)}^{- \frac{1}{2}}$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} (\frac{{(2 x - 5)}^{- \frac{1}{2}}}{2} \frac{d}{d x} [2 x - 5]) + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 10.2.2

Move ${(2 x - 5)}^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} (\frac{1}{2 {(2 x - 5)}^{\frac{1}{2}}} \frac{d}{d x} [2 x - 5]) + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 10.2.3

Combine $\frac{1}{2 {(2 x - 5)}^{\frac{1}{2}}}$ and $e^{- 3 x}$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{2 {(2 x - 5)}^{\frac{1}{2}}} \frac{d}{d x} [2 x - 5] + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 10.3

By the Sum Rule, the derivative of $2 x - 5$ with respect to $x$ is $\frac{d}{d x} [2 x] + \frac{d}{d x} [- 5]$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{2 {(2 x - 5)}^{\frac{1}{2}}} (\frac{d}{d x} [2 x] + \frac{d}{d x} [- 5]) + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 10.4

Since $2$ is constant with respect to $x$ , the derivative of $2 x$ with respect to $x$ is $2 \frac{d}{d x} [x]$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{2 {(2 x - 5)}^{\frac{1}{2}}} (2 \frac{d}{d x} [x] + \frac{d}{d x} [- 5]) + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 10.5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{2 {(2 x - 5)}^{\frac{1}{2}}} (2 \cdot 1 + \frac{d}{d x} [- 5]) + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 10.6

Multiply $2$ by $1$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{2 {(2 x - 5)}^{\frac{1}{2}}} (2 + \frac{d}{d x} [- 5]) + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 10.7

Since $- 5$ is constant with respect to $x$ , the derivative of $- 5$ with respect to $x$ is $0$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{2 {(2 x - 5)}^{\frac{1}{2}}} (2 + 0) + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 10.8

Simplify terms.

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Step 10.8.1

Add $2$ and $0$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{2 {(2 x - 5)}^{\frac{1}{2}}} \cdot 2 + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 10.8.2

Combine $\frac{e^{- 3 x}}{2 {(2 x - 5)}^{\frac{1}{2}}}$ and $2$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x} \cdot 2}{2 {(2 x - 5)}^{\frac{1}{2}}} + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 10.8.3

Move $2$ to the left of $e^{- 3 x}$ .

$\frac{{(6 - 5 x)}^{4} (\frac{2 \cdot e^{- 3 x}}{2 {(2 x - 5)}^{\frac{1}{2}}} + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 10.8.4

Cancel the common factor.

$\frac{{(6 - 5 x)}^{4} (\frac{2 e^{- 3 x}}{2 {(2 x - 5)}^{\frac{1}{2}}} + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 10.8.5

Rewrite the expression.

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{{(2 x - 5)}^{\frac{1}{2}}} + {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [e^{- 3 x}]) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 11

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = e^{x}$ and $g (x) = - 3 x$ .

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Step 11.1

To apply the Chain Rule, set $u_{2}$ as $- 3 x$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{{(2 x - 5)}^{\frac{1}{2}}} + {(2 x - 5)}^{\frac{1}{2}} (\frac{d}{d u_{2}} [e^{u_{2}}] \frac{d}{d x} [- 3 x])) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 11.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u_{2}} [a^{u_{2}}]$ is $a^{u_{2}} \ln (a)$ where $a$ = $e$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{{(2 x - 5)}^{\frac{1}{2}}} + {(2 x - 5)}^{\frac{1}{2}} (e^{u_{2}} \frac{d}{d x} [- 3 x])) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 11.3

Replace all occurrences of $u_{2}$ with $- 3 x$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{{(2 x - 5)}^{\frac{1}{2}}} + {(2 x - 5)}^{\frac{1}{2}} (e^{- 3 x} \frac{d}{d x} [- 3 x])) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 12

Differentiate.

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Step 12.1

Since $- 3$ is constant with respect to $x$ , the derivative of $- 3 x$ with respect to $x$ is $- 3 \frac{d}{d x} [x]$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{{(2 x - 5)}^{\frac{1}{2}}} + {(2 x - 5)}^{\frac{1}{2}} e^{- 3 x} (- 3 \frac{d}{d x} [x])) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 12.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{{(2 x - 5)}^{\frac{1}{2}}} + {(2 x - 5)}^{\frac{1}{2}} e^{- 3 x} (- 3 \cdot 1)) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 12.3

Simplify the expression.

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Step 12.3.1

Multiply $- 3$ by $1$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{{(2 x - 5)}^{\frac{1}{2}}} + {(2 x - 5)}^{\frac{1}{2}} e^{- 3 x} \cdot - 3) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 12.3.2

Move $- 3$ to the left of ${(2 x - 5)}^{\frac{1}{2}} e^{- 3 x}$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{{(2 x - 5)}^{\frac{1}{2}}} - 3 \cdot ({(2 x - 5)}^{\frac{1}{2}} e^{- 3 x})) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 13

Combine $\frac{e^{- 3 x}}{{(2 x - 5)}^{\frac{1}{2}}}$ and $- 3 {(2 x - 5)}^{\frac{1}{2}} e^{- 3 x}$ using a common denominator.

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Step 13.1

Move ${(2 x - 5)}^{\frac{1}{2}}$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{{(2 x - 5)}^{\frac{1}{2}}} - 3 e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}}) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 13.2

To write $- 3 e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}}$ as a fraction with a common denominator, multiply by $\frac{{(2 x - 5)}^{\frac{1}{2}}}{{(2 x - 5)}^{\frac{1}{2}}}$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{{(2 x - 5)}^{\frac{1}{2}}} - 3 e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \cdot \frac{{(2 x - 5)}^{\frac{1}{2}}}{{(2 x - 5)}^{\frac{1}{2}}}) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 13.3

Combine $- 3 e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}}$ and $\frac{{(2 x - 5)}^{\frac{1}{2}}}{{(2 x - 5)}^{\frac{1}{2}}}$ .

$\frac{{(6 - 5 x)}^{4} (\frac{e^{- 3 x}}{{(2 x - 5)}^{\frac{1}{2}}} + \frac{- 3 e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} {(2 x - 5)}^{\frac{1}{2}}}{{(2 x - 5)}^{\frac{1}{2}}}) - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 13.4

Combine the numerators over the common denominator.

$\frac{{(6 - 5 x)}^{4} \frac{e^{- 3 x} - 3 e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} {(2 x - 5)}^{\frac{1}{2}}}{{(2 x - 5)}^{\frac{1}{2}}} - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 14

Multiply ${(2 x - 5)}^{\frac{1}{2}}$ by ${(2 x - 5)}^{\frac{1}{2}}$ by adding the exponents.

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Step 14.1

Move ${(2 x - 5)}^{\frac{1}{2}}$ .

$\frac{{(6 - 5 x)}^{4} \frac{e^{- 3 x} - 3 e^{- 3 x} ({(2 x - 5)}^{\frac{1}{2}} {(2 x - 5)}^{\frac{1}{2}})}{{(2 x - 5)}^{\frac{1}{2}}} - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 14.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{{(6 - 5 x)}^{4} \frac{e^{- 3 x} - 3 e^{- 3 x} {(2 x - 5)}^{\frac{1}{2} + \frac{1}{2}}}{{(2 x - 5)}^{\frac{1}{2}}} - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 14.3

Combine the numerators over the common denominator.

$\frac{{(6 - 5 x)}^{4} \frac{e^{- 3 x} - 3 e^{- 3 x} {(2 x - 5)}^{\frac{1 + 1}{2}}}{{(2 x - 5)}^{\frac{1}{2}}} - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 14.4

Add $1$ and $1$ .

$\frac{{(6 - 5 x)}^{4} \frac{e^{- 3 x} - 3 e^{- 3 x} {(2 x - 5)}^{\frac{2}{2}}}{{(2 x - 5)}^{\frac{1}{2}}} - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 14.5

Divide $2$ by $2$ .

$\frac{{(6 - 5 x)}^{4} \frac{e^{- 3 x} - 3 e^{- 3 x} {(2 x - 5)}^{1}}{{(2 x - 5)}^{\frac{1}{2}}} - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 15

Simplify $- 3 e^{- 3 x} {(2 x - 5)}^{1}$ .

$\frac{{(6 - 5 x)}^{4} \frac{e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)}{{(2 x - 5)}^{\frac{1}{2}}} - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 16

Combine ${(6 - 5 x)}^{4}$ and $\frac{e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)}{{(2 x - 5)}^{\frac{1}{2}}}$ .

$\frac{\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5))}{{(2 x - 5)}^{\frac{1}{2}}} - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 17

Multiply $\frac{\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5))}{{(2 x - 5)}^{\frac{1}{2}}} - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$ by $\frac{{(2 x - 5)}^{\frac{1}{2}}}{{(2 x - 5)}^{\frac{1}{2}}}$ .

$\frac{{(2 x - 5)}^{\frac{1}{2}}}{{(2 x - 5)}^{\frac{1}{2}}} \cdot \frac{\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5))}{{(2 x - 5)}^{\frac{1}{2}}} - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}]}{{(6 - 5 x)}^{8}}$

Step 18

Combine.

$\frac{{(2 x - 5)}^{\frac{1}{2}} (\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5))}{{(2 x - 5)}^{\frac{1}{2}}} - e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}])}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 19

Apply the distributive property.

$\frac{{(2 x - 5)}^{\frac{1}{2}} \frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5))}{{(2 x - 5)}^{\frac{1}{2}}} + {(2 x - 5)}^{\frac{1}{2}} (- e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}])}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 20

Cancel the common factor of ${(2 x - 5)}^{\frac{1}{2}}$ .

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Step 20.1

Cancel the common factor.

Step 20.2

Rewrite the expression.

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + {(2 x - 5)}^{\frac{1}{2}} (- e^{- 3 x} {(2 x - 5)}^{\frac{1}{2}} \frac{d}{d x} [{(6 - 5 x)}^{4}])}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 21

Multiply ${(2 x - 5)}^{\frac{1}{2}}$ by ${(2 x - 5)}^{\frac{1}{2}}$ by adding the exponents.

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Step 21.1

Move ${(2 x - 5)}^{\frac{1}{2}}$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + {(2 x - 5)}^{\frac{1}{2}} {(2 x - 5)}^{\frac{1}{2}} (- e^{- 3 x} \frac{d}{d x} [{(6 - 5 x)}^{4}])}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 21.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + {(2 x - 5)}^{\frac{1}{2} + \frac{1}{2}} (- e^{- 3 x} \frac{d}{d x} [{(6 - 5 x)}^{4}])}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 21.3

Combine the numerators over the common denominator.

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + {(2 x - 5)}^{\frac{1 + 1}{2}} (- e^{- 3 x} \frac{d}{d x} [{(6 - 5 x)}^{4}])}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 21.4

Add $1$ and $1$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + {(2 x - 5)}^{\frac{2}{2}} (- e^{- 3 x} \frac{d}{d x} [{(6 - 5 x)}^{4}])}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 21.5

Divide $2$ by $2$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + {(2 x - 5)}^{1} (- e^{- 3 x} \frac{d}{d x} [{(6 - 5 x)}^{4}])}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 22

Simplify ${(2 x - 5)}^{1} (- e^{- 3 x} \frac{d}{d x} [{(6 - 5 x)}^{4}])$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + (2 x - 5) (- e^{- 3 x} \frac{d}{d x} [{(6 - 5 x)}^{4}])}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 23

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{4}$ and $g (x) = 6 - 5 x$ .

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Step 23.1

To apply the Chain Rule, set $u_{3}$ as $6 - 5 x$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + (2 x - 5) (- e^{- 3 x} (\frac{d}{d u_{3}} [{u_{3}}^{4}] \frac{d}{d x} [6 - 5 x]))}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 23.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{3}} [{u_{3}}^{n}]$ is $n {u_{3}}^{n - 1}$ where $n = 4$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + (2 x - 5) (- e^{- 3 x} (4 {u_{3}}^{3} \frac{d}{d x} [6 - 5 x]))}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 23.3

Replace all occurrences of $u_{3}$ with $6 - 5 x$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + (2 x - 5) (- e^{- 3 x} (4 {(6 - 5 x)}^{3} \frac{d}{d x} [6 - 5 x]))}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 24

Differentiate.

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Step 24.1

Multiply $4$ by $- 1$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + (2 x - 5) (- 4 e^{- 3 x} ({(6 - 5 x)}^{3} \frac{d}{d x} [6 - 5 x]))}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 24.2

By the Sum Rule, the derivative of $6 - 5 x$ with respect to $x$ is $\frac{d}{d x} [6] + \frac{d}{d x} [- 5 x]$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + (2 x - 5) (- 4 e^{- 3 x} ({(6 - 5 x)}^{3} (\frac{d}{d x} [6] + \frac{d}{d x} [- 5 x])))}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 24.3

Since $6$ is constant with respect to $x$ , the derivative of $6$ with respect to $x$ is $0$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + (2 x - 5) (- 4 e^{- 3 x} ({(6 - 5 x)}^{3} (0 + \frac{d}{d x} [- 5 x])))}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 24.4

Add $0$ and $\frac{d}{d x} [- 5 x]$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + (2 x - 5) (- 4 e^{- 3 x} ({(6 - 5 x)}^{3} \frac{d}{d x} [- 5 x]))}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 24.5

Since $- 5$ is constant with respect to $x$ , the derivative of $- 5 x$ with respect to $x$ is $- 5 \frac{d}{d x} [x]$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + (2 x - 5) (- 4 e^{- 3 x} ({(6 - 5 x)}^{3} (- 5 \frac{d}{d x} [x])))}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 24.6

Simplify the expression.

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Step 24.6.1

Multiply $- 5$ by $- 4$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + (2 x - 5) (20 e^{- 3 x} ({(6 - 5 x)}^{3} (\frac{d}{d x} [x])))}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 24.6.2

Move $20$ to the left of $2 x - 5$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + 20 \cdot (2 x - 5) e^{- 3 x} ({(6 - 5 x)}^{3} (\frac{d}{d x} [x]))}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 24.7

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + 20 (2 x - 5) e^{- 3 x} ({(6 - 5 x)}^{3} \cdot 1)}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 24.8

Multiply ${(6 - 5 x)}^{3}$ by $1$ .

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x - 5)) + 20 (2 x - 5) e^{- 3 x} {(6 - 5 x)}^{3}}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25

Simplify.

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Step 25.1

Apply the distributive property.

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x) - 3 e^{- 3 x} \cdot - 5) + 20 (2 x - 5) e^{- 3 x} {(6 - 5 x)}^{3}}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.2

Apply the distributive property.

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x) - 3 e^{- 3 x} \cdot - 5) + (20 (2 x) + 20 \cdot - 5) e^{- 3 x} {(6 - 5 x)}^{3}}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.3

Apply the distributive property.

$\frac{{(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x) - 3 e^{- 3 x} \cdot - 5) + (20 (2 x) e^{- 3 x} + 20 \cdot - 5 e^{- 3 x}) {(6 - 5 x)}^{3}}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4

Simplify the numerator.

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Step 25.4.1

Factor ${(6 - 5 x)}^{3}$ out of ${(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x) - 3 e^{- 3 x} \cdot - 5) + (20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x}) {(6 - 5 x)}^{3}$ .

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Step 25.4.1.1

Factor ${(6 - 5 x)}^{3}$ out of ${(6 - 5 x)}^{4} (e^{- 3 x} - 3 e^{- 3 x} (2 x) - 3 e^{- 3 x} \cdot - 5)$ .

$\frac{{(6 - 5 x)}^{3} ((6 - 5 x) (e^{- 3 x} - 3 e^{- 3 x} (2 x) - 3 e^{- 3 x} \cdot - 5)) + (20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x}) {(6 - 5 x)}^{3}}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.1.2

Factor ${(6 - 5 x)}^{3}$ out of $(20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x}) {(6 - 5 x)}^{3}$ .

$\frac{{(6 - 5 x)}^{3} ((6 - 5 x) (e^{- 3 x} - 3 e^{- 3 x} (2 x) - 3 e^{- 3 x} \cdot - 5)) + {(6 - 5 x)}^{3} (20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.1.3

Factor ${(6 - 5 x)}^{3}$ out of ${(6 - 5 x)}^{3} ((6 - 5 x) (e^{- 3 x} - 3 e^{- 3 x} (2 x) - 3 e^{- 3 x} \cdot - 5)) + {(6 - 5 x)}^{3} (20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})$ .

$\frac{{(6 - 5 x)}^{3} ((6 - 5 x) (e^{- 3 x} - 3 e^{- 3 x} (2 x) - 3 e^{- 3 x} \cdot - 5) + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.2

Simplify each term.

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Step 25.4.2.1

Rewrite using the commutative property of multiplication.

$\frac{{(6 - 5 x)}^{3} ((6 - 5 x) (e^{- 3 x} - 3 \cdot 2 e^{- 3 x} x - 3 e^{- 3 x} \cdot - 5) + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.2.2

Multiply $- 3$ by $2$ .

$\frac{{(6 - 5 x)}^{3} ((6 - 5 x) (e^{- 3 x} - 6 e^{- 3 x} x - 3 e^{- 3 x} \cdot - 5) + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.2.3

Multiply $- 5$ by $- 3$ .

$\frac{{(6 - 5 x)}^{3} ((6 - 5 x) (e^{- 3 x} - 6 e^{- 3 x} x + 15 e^{- 3 x}) + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.3

Add $e^{- 3 x}$ and $15 e^{- 3 x}$ .

$\frac{{(6 - 5 x)}^{3} ((6 - 5 x) (- 6 e^{- 3 x} x + 16 e^{- 3 x}) + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.4

Expand $(6 - 5 x) (- 6 e^{- 3 x} x + 16 e^{- 3 x})$ using the FOIL Method.

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Step 25.4.4.1

Apply the distributive property.

$\frac{{(6 - 5 x)}^{3} (6 (- 6 e^{- 3 x} x + 16 e^{- 3 x}) - 5 x (- 6 e^{- 3 x} x + 16 e^{- 3 x}) + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.4.2

Apply the distributive property.

$\frac{{(6 - 5 x)}^{3} (6 (- 6 e^{- 3 x} x) + 6 (16 e^{- 3 x}) - 5 x (- 6 e^{- 3 x} x + 16 e^{- 3 x}) + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.4.3

Apply the distributive property.

$\frac{{(6 - 5 x)}^{3} (6 (- 6 e^{- 3 x} x) + 6 (16 e^{- 3 x}) - 5 x (- 6 e^{- 3 x} x) - 5 x (16 e^{- 3 x}) + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.5

Simplify and combine like terms.

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Step 25.4.5.1

Simplify each term.

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Step 25.4.5.1.1

Multiply $- 6$ by $6$ .

$\frac{{(6 - 5 x)}^{3} (- 36 (e^{- 3 x} x) + 6 (16 e^{- 3 x}) - 5 x (- 6 e^{- 3 x} x) - 5 x (16 e^{- 3 x}) + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.5.1.2

Multiply $16$ by $6$ .

$\frac{{(6 - 5 x)}^{3} (- 36 e^{- 3 x} x + 96 e^{- 3 x} - 5 x (- 6 e^{- 3 x} x) - 5 x (16 e^{- 3 x}) + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.5.1.3

Multiply $x$ by $x$ by adding the exponents.

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Step 25.4.5.1.3.1

Move $x$ .

$\frac{{(6 - 5 x)}^{3} (- 36 e^{- 3 x} x + 96 e^{- 3 x} - 5 (x \cdot x) (- 6 e^{- 3 x}) - 5 x (16 e^{- 3 x}) + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.5.1.3.2

Multiply $x$ by $x$ .

$\frac{{(6 - 5 x)}^{3} (- 36 e^{- 3 x} x + 96 e^{- 3 x} - 5 x^{2} (- 6 e^{- 3 x}) - 5 x (16 e^{- 3 x}) + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.5.1.4

Rewrite using the commutative property of multiplication.

$\frac{{(6 - 5 x)}^{3} (- 36 e^{- 3 x} x + 96 e^{- 3 x} - 5 \cdot - 6 x^{2} e^{- 3 x} - 5 x (16 e^{- 3 x}) + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.5.1.5

Multiply $- 5$ by $- 6$ .

$\frac{{(6 - 5 x)}^{3} (- 36 e^{- 3 x} x + 96 e^{- 3 x} + 30 x^{2} e^{- 3 x} - 5 x (16 e^{- 3 x}) + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.5.1.6

Rewrite using the commutative property of multiplication.

$\frac{{(6 - 5 x)}^{3} (- 36 e^{- 3 x} x + 96 e^{- 3 x} + 30 x^{2} e^{- 3 x} - 5 \cdot 16 x e^{- 3 x} + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.5.1.7

Multiply $- 5$ by $16$ .

$\frac{{(6 - 5 x)}^{3} (- 36 e^{- 3 x} x + 96 e^{- 3 x} + 30 x^{2} e^{- 3 x} - 80 x e^{- 3 x} + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.5.2

Subtract $80 x e^{- 3 x}$ from $- 36 e^{- 3 x} x$ .

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Step 25.4.5.2.1

Move $e^{- 3 x}$ .

$\frac{{(6 - 5 x)}^{3} (- 36 x e^{- 3 x} - 80 x e^{- 3 x} + 96 e^{- 3 x} + 30 x^{2} e^{- 3 x} + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.5.2.2

Subtract $80 x e^{- 3 x}$ from $- 36 x e^{- 3 x}$ .

$\frac{{(6 - 5 x)}^{3} (- 116 x e^{- 3 x} + 96 e^{- 3 x} + 30 x^{2} e^{- 3 x} + 20 \cdot 2 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.6

Multiply $20$ by $2$ .

$\frac{{(6 - 5 x)}^{3} (- 116 x e^{- 3 x} + 96 e^{- 3 x} + 30 x^{2} e^{- 3 x} + 40 x e^{- 3 x} + 20 \cdot - 5 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.7

Multiply $20$ by $- 5$ .

$\frac{{(6 - 5 x)}^{3} (- 116 x e^{- 3 x} + 96 e^{- 3 x} + 30 x^{2} e^{- 3 x} + 40 x e^{- 3 x} - 100 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.8

Add $- 116 x e^{- 3 x}$ and $40 x e^{- 3 x}$ .

$\frac{{(6 - 5 x)}^{3} (- 76 x e^{- 3 x} + 96 e^{- 3 x} + 30 x^{2} e^{- 3 x} - 100 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.9

Subtract $100 e^{- 3 x}$ from $96 e^{- 3 x}$ .

$\frac{{(6 - 5 x)}^{3} (- 76 x e^{- 3 x} + 30 x^{2} e^{- 3 x} - 4 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.10

Rewrite $- 76 x e^{- 3 x} + 30 x^{2} e^{- 3 x} - 4 e^{- 3 x}$ in a factored form.

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Step 25.4.10.1

Factor $2 e^{- 3 x}$ out of $- 76 x e^{- 3 x} + 30 x^{2} e^{- 3 x} - 4 e^{- 3 x}$ .

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Step 25.4.10.1.1

Factor $2 e^{- 3 x}$ out of $- 76 x e^{- 3 x}$ .

$\frac{{(6 - 5 x)}^{3} (2 e^{- 3 x} (- 38 x) + 30 x^{2} e^{- 3 x} - 4 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.10.1.2

Factor $2 e^{- 3 x}$ out of $30 x^{2} e^{- 3 x}$ .

$\frac{{(6 - 5 x)}^{3} (2 e^{- 3 x} (- 38 x) + 2 e^{- 3 x} (15 x^{2}) - 4 e^{- 3 x})}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.10.1.3

Factor $2 e^{- 3 x}$ out of $- 4 e^{- 3 x}$ .

$\frac{{(6 - 5 x)}^{3} (2 e^{- 3 x} (- 38 x) + 2 e^{- 3 x} (15 x^{2}) + 2 e^{- 3 x} (- 2))}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.10.1.4

Factor $2 e^{- 3 x}$ out of $2 e^{- 3 x} (- 38 x) + 2 e^{- 3 x} (15 x^{2})$ .

$\frac{{(6 - 5 x)}^{3} (2 e^{- 3 x} (- 38 x + 15 x^{2}) + 2 e^{- 3 x} (- 2))}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.10.1.5

Factor $2 e^{- 3 x}$ out of $2 e^{- 3 x} (- 38 x + 15 x^{2}) + 2 e^{- 3 x} (- 2)$ .

$\frac{{(6 - 5 x)}^{3} (2 e^{- 3 x} (- 38 x + 15 x^{2} - 2))}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.4.10.2

Reorder terms.

$\frac{{(6 - 5 x)}^{3} (2 e^{- 3 x} (15 x^{2} - 38 x - 2))}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

$\frac{{(6 - 5 x)}^{3} \cdot 2 e^{- 3 x} (15 x^{2} - 38 x - 2)}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.5

Combine terms.

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Step 25.5.1

Move $2$ to the left of ${(6 - 5 x)}^{3}$ .

$\frac{2 \cdot {(6 - 5 x)}^{3} e^{- 3 x} (15 x^{2} - 38 x - 2)}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.5.2

Factor ${(6 - 5 x)}^{3}$ out of $2 {(6 - 5 x)}^{3} e^{- 3 x} (15 x^{2} - 38 x - 2)$ .

$\frac{{(6 - 5 x)}^{3} (2 e^{- 3 x} (15 x^{2} - 38 x - 2))}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}}$

Step 25.5.3

Cancel the common factors.

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Step 25.5.3.1

Factor ${(6 - 5 x)}^{3}$ out of ${(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{8}$ .

$\frac{{(6 - 5 x)}^{3} (2 e^{- 3 x} (15 x^{2} - 38 x - 2))}{{(6 - 5 x)}^{3} ({(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{5})}$

Step 25.5.3.2

Cancel the common factor.

$\frac{{(6 - 5 x)}^{3} (2 e^{- 3 x} (15 x^{2} - 38 x - 2))}{{(6 - 5 x)}^{3} ({(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{5})}$

Step 25.5.3.3

Rewrite the expression.

$\frac{2 e^{- 3 x} (15 x^{2} - 38 x - 2)}{{(2 x - 5)}^{\frac{1}{2}} {(6 - 5 x)}^{5}}$