Calculus Examples

$g (t) = \cos (\frac{1}{t}) e^{5 t^{2}}$

Step 1

Differentiate using the Product Rule which states that $\frac{d}{d t} [f (t) g (t)]$ is $f (t) \frac{d}{d t} [g (t)] + g (t) \frac{d}{d t} [f (t)]$ where $f (t) = \cos (\frac{1}{t})$ and $g (t) = e^{5 t^{2}}$ .

$\cos (\frac{1}{t}) \frac{d}{d t} [e^{5 t^{2}}] + e^{5 t^{2}} \frac{d}{d t} [\cos (\frac{1}{t})]$

Step 2

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = e^{t}$ and $g (t) = 5 t^{2}$ .

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Step 2.1

To apply the Chain Rule, set $u_{1}$ as $5 t^{2}$ .

$\cos (\frac{1}{t}) (\frac{d}{d u_{1}} [e^{u_{1}}] \frac{d}{d t} [5 t^{2}]) + e^{5 t^{2}} \frac{d}{d t} [\cos (\frac{1}{t})]$

Step 2.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u_{1}} [a^{u_{1}}]$ is $a^{u_{1}} \ln (a)$ where $a$ = $e$ .

$\cos (\frac{1}{t}) (e^{u_{1}} \frac{d}{d t} [5 t^{2}]) + e^{5 t^{2}} \frac{d}{d t} [\cos (\frac{1}{t})]$

Step 2.3

Replace all occurrences of $u_{1}$ with $5 t^{2}$ .

$\cos (\frac{1}{t}) (e^{5 t^{2}} \frac{d}{d t} [5 t^{2}]) + e^{5 t^{2}} \frac{d}{d t} [\cos (\frac{1}{t})]$

Step 3

Differentiate.

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Step 3.1

Since $5$ is constant with respect to $t$ , the derivative of $5 t^{2}$ with respect to $t$ is $5 \frac{d}{d t} [t^{2}]$ .

$\cos (\frac{1}{t}) (e^{5 t^{2}} (5 \frac{d}{d t} [t^{2}])) + e^{5 t^{2}} \frac{d}{d t} [\cos (\frac{1}{t})]$

Step 3.2

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 2$ .

$\cos (\frac{1}{t}) (e^{5 t^{2}} (5 (2 t))) + e^{5 t^{2}} \frac{d}{d t} [\cos (\frac{1}{t})]$

Step 3.3

Multiply $2$ by $5$ .

$\cos (\frac{1}{t}) (e^{5 t^{2}} (10 t)) + e^{5 t^{2}} \frac{d}{d t} [\cos (\frac{1}{t})]$

Step 4

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = \cos (t)$ and $g (t) = \frac{1}{t}$ .

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Step 4.1

To apply the Chain Rule, set $u_{2}$ as $\frac{1}{t}$ .

$\cos (\frac{1}{t}) (e^{5 t^{2}} (10 t)) + e^{5 t^{2}} (\frac{d}{d u_{2}} [\cos (u_{2})] \frac{d}{d t} [\frac{1}{t}])$

Step 4.2

The derivative of $\cos (u_{2})$ with respect to $u_{2}$ is $- \sin (u_{2})$ .

$\cos (\frac{1}{t}) (e^{5 t^{2}} (10 t)) + e^{5 t^{2}} (- \sin (u_{2}) \frac{d}{d t} [\frac{1}{t}])$

Step 4.3

Replace all occurrences of $u_{2}$ with $\frac{1}{t}$ .

$\cos (\frac{1}{t}) (e^{5 t^{2}} (10 t)) + e^{5 t^{2}} (- \sin (\frac{1}{t}) \frac{d}{d t} [\frac{1}{t}])$

Step 5

Differentiate using the Power Rule.

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Step 5.1

Rewrite $\frac{1}{t}$ as $t^{- 1}$ .

$\cos (\frac{1}{t}) (e^{5 t^{2}} (10 t)) + e^{5 t^{2}} (- \sin (\frac{1}{t}) \frac{d}{d t} [t^{- 1}])$

Step 5.2

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = - 1$ .

$\cos (\frac{1}{t}) (e^{5 t^{2}} (10 t)) + e^{5 t^{2}} (- \sin (\frac{1}{t}) (- t^{- 2}))$

Step 5.3

Multiply.

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Step 5.3.1

Multiply $- 1$ by $- 1$ .

$\cos (\frac{1}{t}) (e^{5 t^{2}} (10 t)) + e^{5 t^{2}} (1 \sin (\frac{1}{t}) t^{- 2})$

Step 5.3.2

Multiply $\sin (\frac{1}{t})$ by $1$ .

$\cos (\frac{1}{t}) (e^{5 t^{2}} (10 t)) + e^{5 t^{2}} (\sin (\frac{1}{t}) t^{- 2})$

Step 6

Simplify.

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Step 6.1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\cos (\frac{1}{t}) (e^{5 t^{2}} (10 t)) + e^{5 t^{2}} (\sin (\frac{1}{t}) \frac{1}{t^{2}})$

Step 6.2

Combine terms.

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Step 6.2.1

Combine $\sin (\frac{1}{t})$ and $\frac{1}{t^{2}}$ .

$\cos (\frac{1}{t}) (e^{5 t^{2}} (10 t)) + e^{5 t^{2}} \frac{\sin (\frac{1}{t})}{t^{2}}$

Step 6.2.2

Combine $e^{5 t^{2}}$ and $\frac{\sin (\frac{1}{t})}{t^{2}}$ .

$\cos (\frac{1}{t}) (e^{5 t^{2}} (10 t)) + \frac{e^{5 t^{2}} \sin (\frac{1}{t})}{t^{2}}$

Step 6.3

Reorder terms.

$10 e^{5 t^{2}} t \cos (\frac{1}{t}) + \frac{e^{5 t^{2}} \sin (\frac{1}{t})}{t^{2}}$

Step 6.4

Reorder factors in $10 e^{5 t^{2}} t \cos (\frac{1}{t}) + \frac{e^{5 t^{2}} \sin (\frac{1}{t})}{t^{2}}$ .

$10 t e^{5 t^{2}} \cos (\frac{1}{t}) + \frac{e^{5 t^{2}} \sin (\frac{1}{t})}{t^{2}}$