Calculus Examples

$\int_{0}^{1} \frac{3 x^{3} - x^{2} + 2 x - 4}{\sqrt{x^{2} - 3 x + 2}} d x$

Step 1

This derivative could not be completed using the quotient rule. Mathway will use another method.

Step 2

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x^{2} - 3 x + 2}$ as ${(x^{2} - 3 x + 2)}^{\frac{1}{2}}$ .

$\frac{d}{d x} [\int_{0}^{1} \frac{3 x^{3} - x^{2} + 2 x - 4}{{(x^{2} - 3 x + 2)}^{\frac{1}{2}}} d x]$

Step 3

Once $\int_{0}^{1} \frac{3 x^{3} - x^{2} + 2 x - 4}{{(x^{2} - 3 x + 2)}^{\frac{1}{2}}} d x$ has been evaluated, it will be constant with respect to $x$ , so the derivative of $\int_{0}^{1} \frac{3 x^{3} - x^{2} + 2 x - 4}{{(x^{2} - 3 x + 2)}^{\frac{1}{2}}} d x$ with respect to $x$ is $0$ .

$0$