Calculus Examples

$z = \sqrt{x^{2} + y^{2}}$

Step 1

Since $\sqrt{x^{2} + y^{2}}$ is constant with respect to $z$ , the derivative of $\sqrt{x^{2} + y^{2}}$ with respect to $z$ is $0$ .

$0$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$