Calculus Examples

$y = | - 3 | + 2$

Step 1

The absolute value is the distance between a number and zero. The distance between $- 3$ and $0$ is $3$ .

$y = 3 + 2$

Step 2

Add $3$ and $2$ .

$y = 5$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$