Calculus Examples

Find the Area Under the Curve f(x)=1/x-1/e ; [1,e^3]
;
Step 1
Solve by substitution to find the intersection between the curves.
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Step 1.1
Eliminate the equal sides of each equation and combine.
Step 1.2
Solve for .
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Step 1.2.1
Add to both sides of the equation.
Step 1.2.2
Find the LCD of the terms in the equation.
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Step 1.2.2.1
Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.
Step 1.2.2.2
Since contains both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part then find LCM for the variable part .

Step 1.2.2.3
The LCM is the smallest positive number that all of the numbers divide into evenly.
List the prime factors of each number.

Step 1.2.2.4
The number is not a prime number because it only has one positive factor, which is itself.
Not prime
Step 1.2.2.5
The LCM of is the result of multiplying all prime factors the greatest number of times they occur in either number.
Step 1.2.2.6
The factor for is itself.

Step 1.2.2.7
The LCM of is the result of multiplying all prime factors the greatest number of times they occur in either term.
Step 1.2.3
Multiply each term in by to eliminate the fractions.
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Step 1.2.3.1
Multiply each term in by .
Step 1.2.3.2
Simplify the left side.
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Step 1.2.3.2.1
Cancel the common factor of .
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Step 1.2.3.2.1.1
Cancel the common factor.
Step 1.2.3.2.1.2
Rewrite the expression.
Step 1.2.3.3
Simplify the right side.
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Step 1.2.3.3.1
Combine and .
Step 1.2.4
Solve the equation.
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Step 1.2.4.1
Rewrite the equation as .
Step 1.2.4.2
Multiply both sides of the equation by .
Step 1.2.4.3
Simplify both sides of the equation.
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Step 1.2.4.3.1
Simplify the left side.
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Step 1.2.4.3.1.1
Cancel the common factor of .
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Step 1.2.4.3.1.1.1
Cancel the common factor.
Step 1.2.4.3.1.1.2
Rewrite the expression.
Step 1.2.4.3.2
Simplify the right side.
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Step 1.2.4.3.2.1
Multiply by .
Step 1.3
Substitute for .
Step 1.4
The solution to the system is the complete set of ordered pairs that are valid solutions.
Step 2
The area of the region between the curves is defined as the integral of the upper curve minus the integral of the lower curve over each region. The regions are determined by the intersection points of the curves. This can be done algebraically or graphically.
Step 3
Integrate to find the area between and .
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Step 3.1
Combine the integrals into a single integral.
Step 3.2
Subtract from .
Step 3.3
Split the single integral into multiple integrals.
Step 3.4
The integral of with respect to is .
Step 3.5
Apply the constant rule.
Step 3.6
Simplify the answer.
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Step 3.6.1
Combine and .
Step 3.6.2
Substitute and simplify.
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Step 3.6.2.1
Evaluate at and at .
Step 3.6.2.2
Simplify.
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Step 3.6.2.2.1
Combine and .
Step 3.6.2.2.2
Cancel the common factor of .
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Step 3.6.2.2.2.1
Cancel the common factor.
Step 3.6.2.2.2.2
Rewrite the expression.
Step 3.6.2.2.3
Multiply by .
Step 3.6.2.2.4
Multiply by .
Step 3.7
Simplify.
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Step 3.7.1
Simplify each term.
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Step 3.7.1.1
is approximately which is positive so remove the absolute value
Step 3.7.1.2
The natural logarithm of is .
Step 3.7.1.3
Simplify each term.
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Step 3.7.1.3.1
The absolute value is the distance between a number and zero. The distance between and is .
Step 3.7.1.3.2
The natural logarithm of is .
Step 3.7.1.4
Subtract from .
Step 3.7.1.5
Multiply .
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Step 3.7.1.5.1
Multiply by .
Step 3.7.1.5.2
Multiply by .
Step 3.7.2
Subtract from .
Step 3.7.3
Add and .
Step 4
The area of the region between the curves is defined as the integral of the upper curve minus the integral of the lower curve over each region. The regions are determined by the intersection points of the curves. This can be done algebraically or graphically.
Step 5
Integrate to find the area between and .
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Step 5.1
Combine the integrals into a single integral.
Step 5.2
Subtract from .
Step 5.3
Apply the distributive property.
Step 5.4
Split the single integral into multiple integrals.
Step 5.5
Since is constant with respect to , move out of the integral.
Step 5.6
The integral of with respect to is .
Step 5.7
Apply the constant rule.
Step 5.8
Simplify the answer.
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Step 5.8.1
Substitute and simplify.
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Step 5.8.1.1
Evaluate at and at .
Step 5.8.1.2
Evaluate at and at .
Step 5.8.1.3
Simplify.
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Step 5.8.1.3.1
Combine and .
Step 5.8.1.3.2
Cancel the common factor of and .
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Step 5.8.1.3.2.1
Factor out of .
Step 5.8.1.3.2.2
Cancel the common factors.
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Step 5.8.1.3.2.2.1
Multiply by .
Step 5.8.1.3.2.2.2
Cancel the common factor.
Step 5.8.1.3.2.2.3
Rewrite the expression.
Step 5.8.1.3.2.2.4
Divide by .
Step 5.8.1.3.3
Combine and .
Step 5.8.1.3.4
Cancel the common factor of .
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Step 5.8.1.3.4.1
Cancel the common factor.
Step 5.8.1.3.4.2
Rewrite the expression.
Step 5.8.1.3.5
Multiply by .
Step 5.8.2
Use the quotient property of logarithms, .
Step 5.8.3
Simplify.
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Step 5.8.3.1
is approximately which is positive so remove the absolute value
Step 5.8.3.2
is approximately which is positive so remove the absolute value
Step 5.8.3.3
Cancel the common factor of and .
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Step 5.8.3.3.1
Factor out of .
Step 5.8.3.3.2
Cancel the common factors.
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Step 5.8.3.3.2.1
Multiply by .
Step 5.8.3.3.2.2
Cancel the common factor.
Step 5.8.3.3.2.3
Rewrite the expression.
Step 5.8.3.3.2.4
Divide by .
Step 5.8.3.4
Use logarithm rules to move out of the exponent.
Step 5.8.3.5
The natural logarithm of is .
Step 5.8.3.6
Multiply by .
Step 5.8.3.7
Multiply by .
Step 5.8.3.8
Subtract from .
Step 6