Calculus Examples

$y = \int_{0}^{v} \sqrt{15 + 16 t^{2}} d t$

Step 1

Since $y = \int_{0}^{v} \sqrt{15 + 16 t^{2}} d t$ is constant with respect to $v$ , the derivative of $y = \int_{0}^{v} \sqrt{15 + 16 t^{2}} d t$ with respect to $v$ is $0$ .

$0$