Calculus Examples

$y = 2 x^{2}$ , $y = x^{4} - 2 x^{2}$

Step 1

Solve by substitution to find the intersection between the curves.

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Step 1.1

Eliminate the equal sides of each equation and combine.

$2 x^{2} = x^{4} - 2 x^{2}$

Step 1.2

Solve $2 x^{2} = x^{4} - 2 x^{2}$ for $x$ .

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Step 1.2.1

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$x^{4} - 2 x^{2} = 2 x^{2}$

Step 1.2.2

Move all terms containing $x$ to the left side of the equation.

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Step 1.2.2.1

Subtract $2 x^{2}$ from both sides of the equation.

$x^{4} - 2 x^{2} - 2 x^{2} = 0$

Step 1.2.2.2

Subtract $2 x^{2}$ from $- 2 x^{2}$ .

$x^{4} - 4 x^{2} = 0$

Step 1.2.3

Factor the left side of the equation.

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Step 1.2.3.1

Rewrite $x^{4}$ as ${(x^{2})}^{2}$ .

${(x^{2})}^{2} - 4 x^{2} = 0$

Step 1.2.3.2

Let $u = x^{2}$ . Substitute $u$ for all occurrences of $x^{2}$ .

$u^{2} - 4 u = 0$

Step 1.2.3.3

Factor $u$ out of $u^{2} - 4 u$ .

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Step 1.2.3.3.1

Factor $u$ out of $u^{2}$ .

$u \cdot u - 4 u = 0$

Step 1.2.3.3.2

Factor $u$ out of $- 4 u$ .

$u \cdot u + u \cdot - 4 = 0$

Step 1.2.3.3.3

Factor $u$ out of $u \cdot u + u \cdot - 4$ .

$u (u - 4) = 0$

Step 1.2.3.4

Replace all occurrences of $u$ with $x^{2}$ .

$x^{2} (x^{2} - 4) = 0$

Step 1.2.4

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x^{2} = 0$

$x^{2} - 4 = 0 + y = x^{4} - 2 x^{2}$

Step 1.2.5

Set $x^{2}$ equal to $0$ and solve for $x$ .

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Step 1.2.5.1

Set $x^{2}$ equal to $0$ .

$x^{2} = 0$

Step 1.2.5.2

Solve $x^{2} = 0$ for $x$ .

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Step 1.2.5.2.1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{0}$

Step 1.2.5.2.2

Simplify $\pm \sqrt{0}$ .

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Step 1.2.5.2.2.1

Rewrite $0$ as $0^{2}$ .

$x = \pm \sqrt{0^{2}}$

Step 1.2.5.2.2.2

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 0$

Step 1.2.5.2.2.3

Plus or minus $0$ is $0$ .

$x = 0$

Step 1.2.6

Set $x^{2} - 4$ equal to $0$ and solve for $x$ .

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Step 1.2.6.1

Set $x^{2} - 4$ equal to $0$ .

$x^{2} - 4 = 0$

Step 1.2.6.2

Solve $x^{2} - 4 = 0$ for $x$ .

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Step 1.2.6.2.1

Add $4$ to both sides of the equation.

$x^{2} = 4$

Step 1.2.6.2.2

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{4}$

Step 1.2.6.2.3

Simplify $\pm \sqrt{4}$ .

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Step 1.2.6.2.3.1

Rewrite $4$ as $2^{2}$ .

$x = \pm \sqrt{2^{2}}$

Step 1.2.6.2.3.2

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 2$

Step 1.2.6.2.4

The complete solution is the result of both the positive and negative portions of the solution.

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Step 1.2.6.2.4.1

First, use the positive value of the $\pm$ to find the first solution.

$x = 2$

Step 1.2.6.2.4.2

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 2$

Step 1.2.6.2.4.3

The complete solution is the result of both the positive and negative portions of the solution.

$x = 2, - 2$

Step 1.2.7

The final solution is all the values that make $x^{2} (x^{2} - 4) = 0$ true.

$x = 0, 2, - 2$

Step 1.3

Evaluate $y$ when $x = 0$ .

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Step 1.3.1

Substitute $0$ for $x$ .

$y = {(0)}^{4} - 2 {(0)}^{2}$

Step 1.3.2

Substitute $0$ for $x$ in $y = {(0)}^{4} - 2 {(0)}^{2}$ and solve for $y$ .

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Step 1.3.2.1

Remove parentheses.

$y = 0^{4} - 2 {(0)}^{2}$

Step 1.3.2.2

Remove parentheses.

$y = 0^{4} - 2 \cdot 0^{2}$

Step 1.3.2.3

Simplify $0^{4} - 2 \cdot 0^{2}$ .

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Step 1.3.2.3.1

Simplify each term.

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Step 1.3.2.3.1.1

Raising $0$ to any positive power yields $0$ .

$y = 0 - 2 \cdot 0^{2}$

Step 1.3.2.3.1.2

Raising $0$ to any positive power yields $0$ .

$y = 0 - 2 \cdot 0$

Step 1.3.2.3.1.3

Multiply $- 2$ by $0$ .

$y = 0 + 0$

Step 1.3.2.3.2

Add $0$ and $0$ .

$y = 0$

Step 1.4

Evaluate $y$ when $x = 2$ .

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Step 1.4.1

Substitute $2$ for $x$ .

$y = {(2)}^{4} - 2 {(2)}^{2}$

Step 1.4.2

Substitute $2$ for $x$ in $y = {(2)}^{4} - 2 {(2)}^{2}$ and solve for $y$ .

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Step 1.4.2.1

Remove parentheses.

$y = 2^{4} - 2 {(2)}^{2}$

Step 1.4.2.2

Remove parentheses.

$y = 2^{4} - 2 \cdot 2^{2}$

Step 1.4.2.3

Simplify $2^{4} - 2 \cdot 2^{2}$ .

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Step 1.4.2.3.1

Simplify each term.

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Step 1.4.2.3.1.1

Raise $2$ to the power of $4$ .

$y = 16 - 2 \cdot 2^{2}$

Step 1.4.2.3.1.2

Raise $2$ to the power of $2$ .

$y = 16 - 2 \cdot 4$

Step 1.4.2.3.1.3

Multiply $- 2$ by $4$ .

$y = 16 - 8$

Step 1.4.2.3.2

Subtract $8$ from $16$ .

$y = 8$

Step 1.5

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(0, 0)$

$(2, 8)$

$(- 2, 8)$

$(0, 0)$

$(2, 8)$

$(- 2, 8)$

Step 2

The area of the region between the curves is defined as the integral of the upper curve minus the integral of the lower curve over each region. The regions are determined by the intersection points of the curves. This can be done algebraically or graphically.

$A r e a = \int_{- 2}^{0} 2 x^{2} d x - \int_{- 2}^{0} x^{4} - 2 x^{2} d x$

Step 3

Integrate to find the area between $- 2$ and $0$ .

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Step 3.1

Combine the integrals into a single integral.

$\int_{- 2}^{0} 2 x^{2} - (x^{4} - 2 x^{2}) d x$

Step 3.2

Simplify each term.

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Step 3.2.1

Apply the distributive property.

$2 x^{2} - x^{4} - (- 2 x^{2})$

Step 3.2.2

Multiply $- 2$ by $- 1$ .

$2 x^{2} - x^{4} + 2 x^{2}$

$\int_{- 2}^{0} 2 x^{2} - x^{4} + 2 x^{2} d x$

Step 3.3

Add $2 x^{2}$ and $2 x^{2}$ .

$\int_{- 2}^{0} - x^{4} + 4 x^{2} d x$

Step 3.4

Split the single integral into multiple integrals.

$\int_{- 2}^{0} - x^{4} d x + \int_{- 2}^{0} 4 x^{2} d x$

Step 3.5

Since $- 1$ is constant with respect to $x$ , move $- 1$ out of the integral.

$- \int_{- 2}^{0} x^{4} d x + \int_{- 2}^{0} 4 x^{2} d x$

Step 3.6

By the Power Rule, the integral of $x^{4}$ with respect to $x$ is $\frac{1}{5} x^{5}$ .

$- (\frac{1}{5} x^{5}]_{- 2}^{0}) + \int_{- 2}^{0} 4 x^{2} d x$

Step 3.7

Combine $\frac{1}{5}$ and $x^{5}$ .

$- (\frac{x^{5}}{5}]_{- 2}^{0}) + \int_{- 2}^{0} 4 x^{2} d x$

Step 3.8

Since $4$ is constant with respect to $x$ , move $4$ out of the integral.

$- (\frac{x^{5}}{5}]_{- 2}^{0}) + 4 \int_{- 2}^{0} x^{2} d x$

Step 3.9

By the Power Rule, the integral of $x^{2}$ with respect to $x$ is $\frac{1}{3} x^{3}$ .

$- (\frac{x^{5}}{5}]_{- 2}^{0}) + 4 (\frac{1}{3} x^{3}]_{- 2}^{0})$

Step 3.10

Simplify the answer.

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Step 3.10.1

Combine $\frac{1}{3}$ and $x^{3}$ .

$- (\frac{x^{5}}{5}]_{- 2}^{0}) + 4 (\frac{x^{3}}{3}]_{- 2}^{0})$

Step 3.10.2

Substitute and simplify.

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Step 3.10.2.1

Evaluate $\frac{x^{5}}{5}$ at $0$ and at $- 2$ .

$- ((\frac{0^{5}}{5}) - \frac{{(- 2)}^{5}}{5}) + 4 (\frac{x^{3}}{3}]_{- 2}^{0})$

Step 3.10.2.2

Evaluate $\frac{x^{3}}{3}$ at $0$ and at $- 2$ .

$- (\frac{0^{5}}{5} - \frac{{(- 2)}^{5}}{5}) + 4 (\frac{0^{3}}{3} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3

Simplify.

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Step 3.10.2.3.1

Raising $0$ to any positive power yields $0$ .

$- (\frac{0}{5} - \frac{{(- 2)}^{5}}{5}) + 4 (\frac{0^{3}}{3} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.2

Cancel the common factor of $0$ and $5$ .

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Step 3.10.2.3.2.1

Factor $5$ out of $0$ .

$- (\frac{5 (0)}{5} - \frac{{(- 2)}^{5}}{5}) + 4 (\frac{0^{3}}{3} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.2.2

Cancel the common factors.

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Step 3.10.2.3.2.2.1

Factor $5$ out of $5$ .

$- (\frac{5 \cdot 0}{5 \cdot 1} - \frac{{(- 2)}^{5}}{5}) + 4 (\frac{0^{3}}{3} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.2.2.2

Cancel the common factor.

$- (\frac{5 \cdot 0}{5 \cdot 1} - \frac{{(- 2)}^{5}}{5}) + 4 (\frac{0^{3}}{3} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.2.2.3

Rewrite the expression.

$- (\frac{0}{1} - \frac{{(- 2)}^{5}}{5}) + 4 (\frac{0^{3}}{3} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.2.2.4

Divide $0$ by $1$ .

$- (0 - \frac{{(- 2)}^{5}}{5}) + 4 (\frac{0^{3}}{3} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.3

Raise $- 2$ to the power of $5$ .

$- (0 - \frac{- 32}{5}) + 4 (\frac{0^{3}}{3} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.4

Move the negative in front of the fraction.

$- (0 - - \frac{32}{5}) + 4 (\frac{0^{3}}{3} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.5

Multiply $- 1$ by $- 1$ .

$- (0 + 1 (\frac{32}{5})) + 4 (\frac{0^{3}}{3} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.6

Multiply $\frac{32}{5}$ by $1$ .

$- (0 + \frac{32}{5}) + 4 (\frac{0^{3}}{3} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.7

Add $0$ and $\frac{32}{5}$ .

$- \frac{32}{5} + 4 (\frac{0^{3}}{3} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.8

Raising $0$ to any positive power yields $0$ .

$- \frac{32}{5} + 4 (\frac{0}{3} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.9

Cancel the common factor of $0$ and $3$ .

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Step 3.10.2.3.9.1

Factor $3$ out of $0$ .

$- \frac{32}{5} + 4 (\frac{3 (0)}{3} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.9.2

Cancel the common factors.

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Step 3.10.2.3.9.2.1

Factor $3$ out of $3$ .

$- \frac{32}{5} + 4 (\frac{3 \cdot 0}{3 \cdot 1} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.9.2.2

Cancel the common factor.

$- \frac{32}{5} + 4 (\frac{3 \cdot 0}{3 \cdot 1} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.9.2.3

Rewrite the expression.

$- \frac{32}{5} + 4 (\frac{0}{1} - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.9.2.4

Divide $0$ by $1$ .

$- \frac{32}{5} + 4 (0 - \frac{{(- 2)}^{3}}{3})$

Step 3.10.2.3.10

Raise $- 2$ to the power of $3$ .

$- \frac{32}{5} + 4 (0 - \frac{- 8}{3})$

Step 3.10.2.3.11

Move the negative in front of the fraction.

$- \frac{32}{5} + 4 (0 - - \frac{8}{3})$

Step 3.10.2.3.12

Multiply $- 1$ by $- 1$ .

$- \frac{32}{5} + 4 (0 + 1 (\frac{8}{3}))$

Step 3.10.2.3.13

Multiply $\frac{8}{3}$ by $1$ .

$- \frac{32}{5} + 4 (0 + \frac{8}{3})$

Step 3.10.2.3.14

Add $0$ and $\frac{8}{3}$ .

$- \frac{32}{5} + 4 (\frac{8}{3})$

Step 3.10.2.3.15

Combine $4$ and $\frac{8}{3}$ .

$- \frac{32}{5} + \frac{4 \cdot 8}{3}$

Step 3.10.2.3.16

Multiply $4$ by $8$ .

$- \frac{32}{5} + \frac{32}{3}$

Step 3.10.2.3.17

To write $- \frac{32}{5}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$- \frac{32}{5} \cdot \frac{3}{3} + \frac{32}{3}$

Step 3.10.2.3.18

To write $\frac{32}{3}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$- \frac{32}{5} \cdot \frac{3}{3} + \frac{32}{3} \cdot \frac{5}{5}$

Step 3.10.2.3.19

Write each expression with a common denominator of $15$ , by multiplying each by an appropriate factor of $1$ .

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Step 3.10.2.3.19.1

Multiply $\frac{32}{5}$ by $\frac{3}{3}$ .

$- \frac{32 \cdot 3}{5 \cdot 3} + \frac{32}{3} \cdot \frac{5}{5}$

Step 3.10.2.3.19.2

Multiply $5$ by $3$ .

$- \frac{32 \cdot 3}{15} + \frac{32}{3} \cdot \frac{5}{5}$

Step 3.10.2.3.19.3

Multiply $\frac{32}{3}$ by $\frac{5}{5}$ .

$- \frac{32 \cdot 3}{15} + \frac{32 \cdot 5}{3 \cdot 5}$

Step 3.10.2.3.19.4

Multiply $3$ by $5$ .

$- \frac{32 \cdot 3}{15} + \frac{32 \cdot 5}{15}$

Step 3.10.2.3.20

Combine the numerators over the common denominator.

$\frac{- 32 \cdot 3 + 32 \cdot 5}{15}$

Step 3.10.2.3.21

Simplify the numerator.

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Step 3.10.2.3.21.1

Multiply $- 32$ by $3$ .

$\frac{- 96 + 32 \cdot 5}{15}$

Step 3.10.2.3.21.2

Multiply $32$ by $5$ .

$\frac{- 96 + 160}{15}$

Step 3.10.2.3.21.3

Add $- 96$ and $160$ .

$\frac{64}{15}$

Step 4

$A r e a = \int_{0}^{2} 2 x^{2} d x - \int_{0}^{2} x^{4} - 2 x^{2} d x$

Step 5

Integrate to find the area between $0$ and $2$ .

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Step 5.1

Combine the integrals into a single integral.

$\int_{0}^{2} 2 x^{2} - (x^{4} - 2 x^{2}) d x$

Step 5.2

Simplify each term.

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Step 5.2.1

Apply the distributive property.

$2 x^{2} - x^{4} - (- 2 x^{2})$

Step 5.2.2

Multiply $- 2$ by $- 1$ .

$2 x^{2} - x^{4} + 2 x^{2}$

$\int_{0}^{2} 2 x^{2} - x^{4} + 2 x^{2} d x$

Step 5.3

Add $2 x^{2}$ and $2 x^{2}$ .

$\int_{0}^{2} - x^{4} + 4 x^{2} d x$

Step 5.4

Split the single integral into multiple integrals.

$\int_{0}^{2} - x^{4} d x + \int_{0}^{2} 4 x^{2} d x$

Step 5.5

Since $- 1$ is constant with respect to $x$ , move $- 1$ out of the integral.

$- \int_{0}^{2} x^{4} d x + \int_{0}^{2} 4 x^{2} d x$

Step 5.6

By the Power Rule, the integral of $x^{4}$ with respect to $x$ is $\frac{1}{5} x^{5}$ .

$- (\frac{1}{5} x^{5}]_{0}^{2}) + \int_{0}^{2} 4 x^{2} d x$

Step 5.7

Combine $\frac{1}{5}$ and $x^{5}$ .

$- (\frac{x^{5}}{5}]_{0}^{2}) + \int_{0}^{2} 4 x^{2} d x$

Step 5.8

Since $4$ is constant with respect to $x$ , move $4$ out of the integral.

$- (\frac{x^{5}}{5}]_{0}^{2}) + 4 \int_{0}^{2} x^{2} d x$

Step 5.9

By the Power Rule, the integral of $x^{2}$ with respect to $x$ is $\frac{1}{3} x^{3}$ .

$- (\frac{x^{5}}{5}]_{0}^{2}) + 4 (\frac{1}{3} x^{3}]_{0}^{2})$

Step 5.10

Simplify the answer.

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Step 5.10.1

Combine $\frac{1}{3}$ and $x^{3}$ .

$- (\frac{x^{5}}{5}]_{0}^{2}) + 4 (\frac{x^{3}}{3}]_{0}^{2})$

Step 5.10.2

Substitute and simplify.

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Step 5.10.2.1

Evaluate $\frac{x^{5}}{5}$ at $2$ and at $0$ .

$- ((\frac{2^{5}}{5}) - \frac{0^{5}}{5}) + 4 (\frac{x^{3}}{3}]_{0}^{2})$

Step 5.10.2.2

Evaluate $\frac{x^{3}}{3}$ at $2$ and at $0$ .

$- (\frac{2^{5}}{5} - \frac{0^{5}}{5}) + 4 (\frac{2^{3}}{3} - \frac{0^{3}}{3})$

Step 5.10.2.3

Simplify.

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Step 5.10.2.3.1

Raise $2$ to the power of $5$ .

$- (\frac{32}{5} - \frac{0^{5}}{5}) + 4 (\frac{2^{3}}{3} - \frac{0^{3}}{3})$

Step 5.10.2.3.2

Raising $0$ to any positive power yields $0$ .

$- (\frac{32}{5} - \frac{0}{5}) + 4 (\frac{2^{3}}{3} - \frac{0^{3}}{3})$

Step 5.10.2.3.3

Cancel the common factor of $0$ and $5$ .

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Step 5.10.2.3.3.1

Factor $5$ out of $0$ .

$- (\frac{32}{5} - \frac{5 (0)}{5}) + 4 (\frac{2^{3}}{3} - \frac{0^{3}}{3})$

Step 5.10.2.3.3.2

Cancel the common factors.

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Step 5.10.2.3.3.2.1

Factor $5$ out of $5$ .

$- (\frac{32}{5} - \frac{5 \cdot 0}{5 \cdot 1}) + 4 (\frac{2^{3}}{3} - \frac{0^{3}}{3})$

Step 5.10.2.3.3.2.2

Cancel the common factor.

$- (\frac{32}{5} - \frac{5 \cdot 0}{5 \cdot 1}) + 4 (\frac{2^{3}}{3} - \frac{0^{3}}{3})$

Step 5.10.2.3.3.2.3

Rewrite the expression.

$- (\frac{32}{5} - \frac{0}{1}) + 4 (\frac{2^{3}}{3} - \frac{0^{3}}{3})$

Step 5.10.2.3.3.2.4

Divide $0$ by $1$ .

$- (\frac{32}{5} - 0) + 4 (\frac{2^{3}}{3} - \frac{0^{3}}{3})$

Step 5.10.2.3.4

Multiply $- 1$ by $0$ .

$- (\frac{32}{5} + 0) + 4 (\frac{2^{3}}{3} - \frac{0^{3}}{3})$

Step 5.10.2.3.5

Add $\frac{32}{5}$ and $0$ .

$- \frac{32}{5} + 4 (\frac{2^{3}}{3} - \frac{0^{3}}{3})$

Step 5.10.2.3.6

Raise $2$ to the power of $3$ .

$- \frac{32}{5} + 4 (\frac{8}{3} - \frac{0^{3}}{3})$

Step 5.10.2.3.7

Raising $0$ to any positive power yields $0$ .

$- \frac{32}{5} + 4 (\frac{8}{3} - \frac{0}{3})$

Step 5.10.2.3.8

Cancel the common factor of $0$ and $3$ .

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Step 5.10.2.3.8.1

Factor $3$ out of $0$ .

$- \frac{32}{5} + 4 (\frac{8}{3} - \frac{3 (0)}{3})$

Step 5.10.2.3.8.2

Cancel the common factors.

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Step 5.10.2.3.8.2.1

Factor $3$ out of $3$ .

$- \frac{32}{5} + 4 (\frac{8}{3} - \frac{3 \cdot 0}{3 \cdot 1})$

Step 5.10.2.3.8.2.2

Cancel the common factor.

$- \frac{32}{5} + 4 (\frac{8}{3} - \frac{3 \cdot 0}{3 \cdot 1})$

Step 5.10.2.3.8.2.3

Rewrite the expression.

$- \frac{32}{5} + 4 (\frac{8}{3} - \frac{0}{1})$

Step 5.10.2.3.8.2.4

Divide $0$ by $1$ .

$- \frac{32}{5} + 4 (\frac{8}{3} - 0)$

Step 5.10.2.3.9

Multiply $- 1$ by $0$ .

$- \frac{32}{5} + 4 (\frac{8}{3} + 0)$

Step 5.10.2.3.10

Add $\frac{8}{3}$ and $0$ .

$- \frac{32}{5} + 4 (\frac{8}{3})$

Step 5.10.2.3.11

Combine $4$ and $\frac{8}{3}$ .

$- \frac{32}{5} + \frac{4 \cdot 8}{3}$

Step 5.10.2.3.12

Multiply $4$ by $8$ .

$- \frac{32}{5} + \frac{32}{3}$

Step 5.10.2.3.13

To write $- \frac{32}{5}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$- \frac{32}{5} \cdot \frac{3}{3} + \frac{32}{3}$

Step 5.10.2.3.14

To write $\frac{32}{3}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$- \frac{32}{5} \cdot \frac{3}{3} + \frac{32}{3} \cdot \frac{5}{5}$

Step 5.10.2.3.15

Write each expression with a common denominator of $15$ , by multiplying each by an appropriate factor of $1$ .

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Step 5.10.2.3.15.1

Multiply $\frac{32}{5}$ by $\frac{3}{3}$ .

$- \frac{32 \cdot 3}{5 \cdot 3} + \frac{32}{3} \cdot \frac{5}{5}$

Step 5.10.2.3.15.2

Multiply $5$ by $3$ .

$- \frac{32 \cdot 3}{15} + \frac{32}{3} \cdot \frac{5}{5}$

Step 5.10.2.3.15.3

Multiply $\frac{32}{3}$ by $\frac{5}{5}$ .

$- \frac{32 \cdot 3}{15} + \frac{32 \cdot 5}{3 \cdot 5}$

Step 5.10.2.3.15.4

Multiply $3$ by $5$ .

$- \frac{32 \cdot 3}{15} + \frac{32 \cdot 5}{15}$

Step 5.10.2.3.16

Combine the numerators over the common denominator.

$\frac{- 32 \cdot 3 + 32 \cdot 5}{15}$

Step 5.10.2.3.17

Simplify the numerator.

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Step 5.10.2.3.17.1

Multiply $- 32$ by $3$ .

$\frac{- 96 + 32 \cdot 5}{15}$

Step 5.10.2.3.17.2

Multiply $32$ by $5$ .

$\frac{- 96 + 160}{15}$

Step 5.10.2.3.17.3

Add $- 96$ and $160$ .

$\frac{64}{15}$

Step 6

Add the areas $\frac{64}{15} + \frac{64}{15}$ .

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Step 6.1

Combine the numerators over the common denominator.

$\frac{64 + 64}{15}$

Step 6.2

Add $64$ and $64$ .

$\frac{128}{15}$

Step 7