Calculus Examples

$f (4) = 18 \sec^{2} (3 x + 6) \tan (3 x + 6)$

Step 1

Replace the variable $x$ with $4$ in the expression.

$f (4) = 18 \sec^{2} (3 (4) + 6) \tan (3 (4) + 6)$

Step 2

Simplify the result.

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Step 2.1

Multiply $3$ by $4$ .

$f (4) = 18 \sec^{2} (12 + 6) \tan (3 (4) + 6)$

Step 2.2

Add $12$ and $6$ .

$f (4) = 18 \sec^{2} (18) \tan (3 (4) + 6)$

Step 2.3

Evaluate $\sec (18)$ .

$f (4) = 18 \cdot ({1.05146222}^{2} \tan (3 (4) + 6))$

Step 2.4

Raise $1.05146222$ to the power of $2$ .

$f (4) = 18 \cdot (1.1055728 \tan (3 (4) + 6))$

Step 2.5

Multiply $18$ by $1.1055728$ .

$f (4) = 19.90031056 \tan (3 (4) + 6)$

Step 2.6

Multiply $3$ by $4$ .

$f (4) = 19.90031056 \tan (12 + 6)$

Step 2.7

Add $12$ and $6$ .

$f (4) = 19.90031056 \tan (18)$

Step 2.8

Evaluate $\tan (18)$ .

$f (4) = 19.90031056 \cdot 0.32491969$

Step 2.9

Multiply $19.90031056$ by $0.32491969$ .

$f (4) = 6.46600286$

Step 2.10

The final answer is $6.46600286$ .

$6.46600286$

Step 3