Calculus Examples

Find the Area Under the Curve y=sec(x)^2 , 0<=x<=pi/6
,
Step 1
Solve by substitution to find the intersection between the curves.
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Step 1.1
Eliminate the equal sides of each equation and combine.
Step 1.2
Solve for .
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Step 1.2.1
Take the specified root of both sides of the equation to eliminate the exponent on the left side.
Step 1.2.2
Simplify .
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Step 1.2.2.1
Rewrite as .
Step 1.2.2.2
Pull terms out from under the radical, assuming positive real numbers.
Step 1.2.2.3
Plus or minus is .
Step 1.2.3
The range of secant is and . Since does not fall in this range, there is no solution.
No solution
No solution
No solution
Step 2
The area of the region between the curves is defined as the integral of the upper curve minus the integral of the lower curve over each region. The regions are determined by the intersection points of the curves. This can be done algebraically or graphically.
Step 3
Integrate to find the area between and .
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Step 3.1
Combine the integrals into a single integral.
Step 3.2
Subtract from .
Step 3.3
Since the derivative of is , the integral of is .
Step 3.4
Simplify the answer.
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Step 3.4.1
Evaluate at and at .
Step 3.4.2
Simplify.
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Step 3.4.2.1
The exact value of is .
Step 3.4.2.2
The exact value of is .
Step 3.4.2.3
Multiply by .
Step 3.4.2.4
Add and .
Step 4
The result can be shown in multiple forms.
Exact Form:
Decimal Form:
Step 5